RRB NTPC Graduate CBT 1 2024 PYQs

Concept: Replace the letters by the signs and solve using BODMAS.

1. Replace: $19\times 4-7\times 8+32-11\times 2$
2. Multiplications first: $76-56+32-22$
3. Left to right: $20+32-22=30$

Trick: Do all × and ÷ first, then add all positives ($76+32=108$) and subtract all negatives ($56+22=78$): $108-78=30$.

Answer: (C) 30

Concept: A letter common to two words gets the digit common to both codes.

1. ROME → 7245 and TURN → 5689.
2. The only letter common to both words is R.
3. The only digit common to both codes is 5, so R = 5.

Trick: Match common letter with common digit – no need to decode the other letters.

Answer: (B) 5

Concept: Each letter moves +4 from one cluster to the next.

1. CX → GB → KF: C+4=G, G+4=K; X+4=B, B+4=F.
2. WR → AV → EZ: W+4=A, A+4=E; R+4=V, V+4=Z ✓
3. Others fail, e.g. FA-JE-NJ: E+4=I, not J.

Trick: Check just the second letters: X→B→F (+4); only R→V→Z also goes +4.

Answer: (B) WR-AV-EZ

Concept: A letter common to two words gets the digit common to both codes.

1. ROPE → 5391 and OILY → 2458.
2. The only common letter is O.
3. The only common digit is 5, so O = 5.

Trick: Common letter ↔ common digit.

Answer: (B) 5

Concept: Find the rule in the complete pair DAF : % from the first pair and apply.

1. Test option (C): OLQ → LIN: O−3=L, L−3=I, Q−3=N (each letter −3).
2. Same rule on DAF: D−3=A, A−3=X, F−3=C → AXC.
3. Both pairs follow −3, so # = OLQ and % = AXC.

Trick: Work backward from LIN (+3 gives OLQ) and forward from DAF (−3 gives AXC).

Answer: (C) # = OLQ, % = AXC

Concept: Facing the centre, a person's left is clockwise and right is anticlockwise.

1. Fix T; B is 3rd to the left (clockwise) of T.
2. A and R are T's neighbours. If R were left of T, S (2nd right of R) would clash with A, so R is on T's right and A on T's left; then S is 2nd right of R.
3. Remaining two seats: the one next to B is D (C cannot sit beside B), the other is C.
4. Clockwise: T, A, D, B, S, C, R. From D going right: A, T, then R → 2 persons.

Trick: Place the fixed-distance clues (B–T, R–S) first; the neighbour clue then leaves only one arrangement.

Answer: (D) Two

Concept: Change each digit by the rule, then read the required positions.

1. 6753412: odd digits 7, 5, 3, 1 → +1 = 8, 6, 4, 2; even digits 6, 4, 2 → −2 = 4, 2, 0.
2. New number: 4 8 6 4 2 2 0
3. 2nd from left = 8, 2nd from right = 2; sum $=8+2=10$

Trick: Only transform the two digits you need: 7 → 8 and 1 → 2.

Answer: (B) 10

Concept: Compare position changes of first letters and of second letters.

1. BU – GK: B+5=G; U−10=K.
2. YR – DH: Y+5=D; R−10=H. MF – RV: M+5=R; F−10=V (6−10 → 22).
3. TN – YC: T+5=Y but N−11=C (not −10) → odd one.

Trick: First letters all move +5; check only the second letters for the break.

Answer: (C) TN – YC

Concept: Swap the signs as told, then apply BODMAS.

1. Replace: $96÷6\times 8+71-26$
2. $96÷6=16$; $16\times 8=128$
3. $128+71-26=173$

Trick: Write the converted expression fully before calculating – most errors come from half-swapped signs.

Answer: (C) 173

Concept: Draw the minimum Venn diagram; a conclusion follows only if it is true in every possible diagram.

1. All cats are inside owls; some owls are rats – but the rats may lie in the part of owls outside cats.
2. So 'Some rats are cats' is not certain → (I) does not follow.
3. Bats are only kept away from rats; nothing stops bats from touching cats, so 'Some bats can be cats' is a valid possibility → (II) follows.

Trick: 'Can be' conclusions follow unless a 'No' statement blocks that exact pair.

Answer: (C) Only conclusion (II) follows

Concept: Find a letter-wise rule from # to DTF and apply it to URQ.

1. Option (C): CQG → DTF: C+1=D, Q+3=T, G−1=F.
2. Apply to URQ: U+1=V, R+3=U, Q−1=P → VUP.
3. Both pairs follow (+1, +3, −1).

Trick: Reverse the rule on DTF (−1, −3, +1) to get # = CQG directly.

Answer: (C) # = CQG, % = VUP

Concept: Track each position of the clusters separately.

1. 1st letters: U, S, Q, O → −2 each → M
2. 2nd letters: N, L, J, H → −2 → F
3. 3rd letters: P, N, L, J → −2 → H; answer MFH

Trick: All three letters drop by 2 – just subtract 2 from each letter of OHJ.

Answer: (B) MFH

Concept: Look at the differences between consecutive terms.

1. Differences: $273-224=49$, $224-180=44$, $180-141=39$, $141-107=34$
2. They decrease by 5 each time, so next difference $=29$
3. Next term $=107-29=78$

Trick: Second-level difference constant (−5) → continue the pattern.

Answer: (B) 78

Concept: When people face the centre, moving clockwise is to their left and anticlockwise is to their right.

1. Fix F; A is third to the right of F.
2. G cannot sit next to F. Testing G's remaining seats, only G just right of A works (C then sits second to the left of G, i.e. next to A); E and D take the two seats between F and G with D to the right of E.
3. Order clockwise: F, D, E, G, A, C, B.
4. C sits next to A in the clockwise direction, i.e. to A's immediate left.

Trick: Facing centre: Left = clockwise; place the fixed person first and test only the conditions that lock seats.

Answer: (D) To the immediate left

Concept: Write the positions of letters and find the jump within and between terms.

1. DJP = 4, 10, 16 (each letter +6).
2. Each next term shifts every letter by +3: DJP → GMS → JPV → MSY.
3. MSY + 3 = P(16), V(22), B(25+3 = 28 − 26 = 2).

Trick: After Z, wrap around: Y + 3 = B.

Answer: (A) PVB

Concept: Place the fixed person first, then use 'exactly n between' clues to lock positions.

1. V = Tuesday; 2 people between V and P → P = Friday.
2. S–T and R–Q are consecutive pairs in Mon, Wed, Thu, Sat, Sun.
3. S–T = Wed–Thu, R–Q = Sat–Sun gives one person (P) between T and R ✓; the other way gives 3 ✗.
4. U = Monday. Before S (Wed): U, V → 2 people.

Trick: Pairs (S–T, R–Q) can only sit in back-to-back free days – test the two slots.

Answer: (D) 2

Concept: Check each part separately: the two letters and the number.

1. SS 14 → WP −4: S + 4 = W, S − 3 = P, 14 − 18 = −4.
2. CE 10 → GB −8: C + 4 = G, E − 3 = B, 10 − 18 = −8.
3. QG 1 → Q + 4 = U, G − 3 = D, 1 − 18 = −17 → UD −17.

Trick: Pattern: (+4, −3, −18).

Answer: (B) UD −17

Concept: Identify the highest and lowest numbers, then pick the required digits.

1. Highest = 951 → first digit 9.
2. Lowest = 127 → third digit 7.
3. Third digit of lowest − first digit of highest = 7 − 9 = −2.

Trick: Read the order carefully: 'A subtracted from B' means B − A.

Answer: (D) −2

Concept: Apply the rule digit by digit: odd → +1, even → −2.

1. 5214637 → 5+1=6, 2−2=0, 1+1=2, 4−2=2, 6−2=4, 3+1=4, 7+1=8.
2. New number: 6022448.
3. Repeated digits: 2 (twice) and 4 (twice) → two digits.

Trick: Odd + 1 always becomes even; just track repeats at the end.

Answer: (C) Two

Concept: Draw a family tree: ♂/♀ for gender, horizontal line for marriage, vertical line for children.

1. I is the husband of J, and H is their daughter.
2. G is H's husband, i.e. J's daughter's husband (son-in-law).
3. F is G's brother → F is J's daughter's husband's brother.

Trick: Start from the person in the answer (J) and walk to F: daughter → her husband → his brother.

Answer: (D) Daughter's husband's brother