RRB NTPC Graduate CBT 1 2024 PYQs

Concept: Check every number: the element just before it and just after it must both be symbols.

1. Qualifying numbers: * 6 @, @ 1 £, $ 7 #, # 6 %, * 5 €.
2. 8, 6 (after 8), 1, 9 fail because a neighbour is a number.
3. Count = 5.

Trick: Scan in groups of three (symbol–number–symbol) from left to right.

Answer: (B) 5

Concept: Facing the centre, 'left' means moving clockwise.

1. Place D. G is immediate left of D; A is 3rd to the left of D (D → G → _ → A).
2. Only B sits between H and A ⇒ B next to A on the far side, then H.
3. Remaining seats: one next to A and one next to D. C is not A's neighbour ⇒ C next to D, I next to A.
4. Third to the left of I: A, B, H ⇒ H.

Trick: Draw the circle and always move clockwise for 'left' when everyone faces the centre.

Answer: (D) H

Concept: Use the 'exactly 4 between' clue to fix Q and V (Mon = 1 … Sun = 7).

1. 4 between Q and V ⇒ (Mon, Sat) or (Tue, Sun). Neither on Monday ⇒ Q, V are Tue and Sun.
2. If Q = Sun, T = Sat; left Mon, Thu, Fri — no room for three consecutive P, S, R. ✗
3. So Q = Tue, T = Mon, V = Sun; P, S, R = Thu, Fri, Sat; U = Wed.
4. Before Q: only T ⇒ 1.

Trick: A block of three consecutive days (P-S-R) quickly rules out the wrong case.

Answer: (A) 1

Concept: Look at the differences between consecutive terms.

1. $872-2=870$, $870-4=866$, $866-6=860$, $860-8=852$
2. Next: $852-10=842$

Trick: Differences are consecutive even numbers 2, 4, 6, 8, 10.

Answer: (B) 842

Concept: Track each letter position of the clusters separately.

1. 1st letters: O, M, K, I → G (−2 each)
2. 2nd letters: Q, O, M, K → I (−2 each)
3. 3rd letters: J, H, F, D → B (−2 each)

Trick: All three positions move back by 2 together.

Answer: (A) GIB

Concept: Odd digit → +1, even digit → −2, then look for repeats.

1. 6318574 → 6−2, 3+1, 1+1, 8−2, 5+1, 7+1, 4−2
2. New number: 4426682
3. Repeated digits: 4, 2, 6 ⇒ three.

Trick: Write the new digits directly under the old ones to avoid mistakes.

Answer: (A) Three

Concept: The pair rule must be the same on both sides: # → USO and LJF → %.

1. Test option (C): LJF → IGC: L−3 = I, J−3 = G, F−3 = C.
2. Same rule: XVR → USO: X−3 = U, V−3 = S, R−3 = O. ✓
3. Other options fail (e.g., LJF → IZC is not a uniform shift).

Trick: Find the rule from the right side (LJF → %) and check the left side.

Answer: (C) # = XVR, % = IGC

Concept: Find how the middle number comes from the outer two.

1. $(14,66,19)$: $(14+19)\times 2=66$
2. $(43,134,24)$: $(43+24)\times 2=134$
3. $(6,42,15)$: $(6+15)\times 2=42$ ✓; others give $36\ne 35$, $98\ne 97$, $82\ne 81$

Trick: Middle = 2 × (first + third).

Answer: (C) (6, 42, 15)

Concept: A word common to two sentences gets the code common to both coded sentences.

1. 'relax' is the only word in both sentences.
2. 'pu' is the only code in both 'ha mi pu' and 'pu co lz'.
3. So relax = pu.

Trick: Common word ↔ common code.

Answer: (B) pu

Concept: Facing the centre: left = clockwise, right = anticlockwise.

1. Fix C; B is 3rd to the left of C.
2. F is 2nd to the left of E and E is not next to B ⇒ E sits immediately right of C, F immediately left of C.
3. D is immediate right of A ⇒ A and D take the two seats after B; G takes the seat between F and B.
4. Moving clockwise from G, the next person is B ⇒ B is to the immediate left of G.

Trick: After fixing the two 'fixed-gap' pairs, only one seat is left — fill it and read the answer.

Answer: (B) To the immediate left

Concept: Letters common to both words share the common digits; the leftover letter takes the leftover digit.

1. PANT → 6129 and TAPE → 2956.
2. Common letters P, A, T ↔ common digits 6, 2, 9.
3. Left in TAPE: letter E; left in 2956: digit 5. So E = 5.

Trick: Cancel common letters and common digits – what remains pairs up directly.

Answer: (D) 5

Concept: When everyone faces the centre, moving to a person’s left means moving clockwise.

1. Fix B; C is 3rd to the left of B.
2. A is 2nd to the left of G, and G is not next to C → only G at the seat just right of B works, giving A at B’s immediate left.
3. D is immediate left of E → E and D take the two seats after C; F sits between A and C.
4. From A going left: F, C, then E → 2 people between.

Trick: Draw the circle first, place the fixed pair (B, C), then try each possible seat for G.

Answer: (B) Two

Concept: Draw the least-overlap Venn diagram and check each conclusion.

1. “All fruits are bananas” → fruit circle lies inside banana circle, so “Some fruits are bananas” is definitely true (I follows).
2. “All green are leaves” → green circle lies inside leaves, so “Some green are leaves” is definitely true (II follows).

Trick: “All A are B” always gives “Some A are B” and “Some B are A”.

Answer: (C) Both conclusions (I) and (II) follow

Concept: Replace each sign with its meaning, then apply BODMAS.

1. $11-91\times 7÷83+27\to 11\times 91÷7+83-27$
2. $91÷7=13$, $11\times 13=143$
3. $143+83-27=199$

Trick: Rewrite the whole expression with the new signs before calculating.

Answer: (D) 199

Concept: Decode each symbol step by step and build a family tree.

1. M + N → M is sister of N (M female).
2. N − O → N is brother of O.
3. O × P → O is wife of P.
4. P ÷ Q → P is father of Q, so O is mother of Q.
5. M is sister of N, who is brother of O → M is O’s sister = Q’s mother’s sister.

Trick: Mark gender as soon as a relation reveals it (sister, wife → female).

Answer: (A) Mother’s Sister

Concept: Place fixed information first, then the blocks.

1. R = Wednesday. Three people between R and Q → Q = Sunday (going back is impossible).
2. T, S, V are consecutive (T-S-V). Free days: Mon, Tue, Thu, Fri, Sat → only Thu-Fri-Sat fits, so S = Friday.
3. Three between P and S → P = Monday; U = Tuesday.

Trick: A 3-person block needs three consecutive free days – that usually fixes it at once.

Answer: (B) Q

Concept: Identify the highest and lowest numbers, then pick the asked digits.

1. Highest = 862 → third digit = 2.
2. Lowest = 205 → first digit = 2.
3. $2+2=4$

Trick: Compare first digits only to find highest (8) and lowest (2).

Answer: (D) 4

Concept: A letter common to both words is coded by the digit common to both codes.

1. COAT → 2486 and PALE → 5712.
2. The only common letter is A.
3. The only common digit in 2486 and 5712 is 2, so A = 2.

Trick: One common letter ↔ one common digit.

Answer: (C) 2

Concept: Find the gaps between consecutive letters using alphabet positions.

1. MQL: M→Q (+4), Q→L (−5)
2. RVQ: R→V (+4), V→Q (−5)
3. KOJ: K→O (+4), O→J (−5)
4. OSM: O→S (+4), S→M (−6) ✗

Trick: Pattern +4, −5 means the third letter is just one before the first (L before M, Q before R, J before K) – OSM breaks it.

Answer: (D) OSM

Concept: Track net East–West and North–South movement from A.

1. East 12 → left (North) 9 → left (West) 13 → left (South) 12 → left (East) 1.
2. East–West: $12-13+1=0$ → P is directly in line with A.
3. North–South: $9-12=-3$ → P is 3 km south of A.
4. To return, drive 3 km towards the north.

Trick: Add east, subtract west; add north, subtract south.

Answer: (D) 3 km to the north