RRB NTPC Graduate CBT 1 2024 PYQs

Concept: Letters common to both words share the common digits; the leftover letter takes the leftover digit.

1. RIPE → 5, 9, 8, 7 and FIRE → 8, 7, 5, 1.
2. Common letters: R, I, E; common digits: 5, 8, 7.
3. Leftover letter in FIRE is F and leftover digit is 1, so F = 1.

Trick: Cancel common letters with common digits – the odd ones pair up.

Answer: (D) 1

Concept: Check the difference between consecutive terms.

1. $29-23=6,35-29=6,41-35=6,47-41=6$
2. Constant difference +6.
3. Next term $=47+6=53$

Trick: Equal gaps → arithmetic series; just add the gap.

Answer: (A) 53

Concept: Change each digit by the rule, then pick the required positions.

1. 3154872: odd digits +1 (3→4, 1→2, 5→6, 7→8); even digits −2 (4→2, 8→6, 2→0).
2. New number: 4 2 6 2 6 8 0
3. Second from left = 2, second from right = 8; difference $=8-2=6$

Trick: Write the new digits directly under the old ones to avoid mistakes.

Answer: (D) 6

Concept: Fix the definite clues first, then place blocks of people.

1. S = Tuesday; 3 people between S and V → V = Saturday.
2. T, P, U must be consecutive (T–P–U); the only 3 free consecutive days are Wed, Thu, Fri.
3. One person between T (Wed) and R → R = Monday (Friday is taken by U); Q = Sunday.

Trick: Place fixed persons, then fit the longest block into the only gap left.

Answer: (B) R

Concept: Find the shift from the given right pair, then apply the same to #.

1. Try # = POL: P−3 = M, O−3 = L, L−3 = I → MLI ✓
2. Apply −3 to LKH: L−3 = I, K−3 = H, H−3 = E → IHE
3. So # = POL and % = IHE.

Trick: Test each option quickly with the same letter-shift on both sides.

Answer: (C) # = POL, % = IHE

Concept: Facing the centre: right = anticlockwise, left = clockwise.

1. Fix G; A is third to the right of G.
2. C is second to the right of D and C is not next to G → the only fit is D second to the right of G and C second to the right of D (order G, _, D, A, C).
3. E is immediately left of B → B and E take the remaining adjacent seats; F sits between G and D.
4. From D moving left (clockwise): F, G, then B → 2 people between.

Trick: Draw the circle and fix the person with most clues first.

Answer: (B) Two

Concept: Identify the highest and lowest numbers, then pick the asked digits.

1. Numbers: 194, 932, 446, 225, 493
2. Highest = 932 → first digit 9; lowest = 194 → second digit 9
3. Sum $=9+9=18$

Trick: Compare only first digits to spot highest/lowest fast.

Answer: (C) 18

Concept: Check the order inside each cluster and the shift between the two clusters.

1. HI – CD, QR – LM, PQ – KL: each cluster is two consecutive letters in forward order, and the second cluster is 5 letters back (H−5 = C, Q−5 = L, P−5 = K).
2. LK – KJ: letters are in reverse order and the shift is only 1 (L−1 = K).
3. So LK – KJ is the odd one.

Trick: First check forward/backward order inside clusters – often enough to find the odd one.

Answer: (A) LK - KJ

Concept: Track the net east–west and north–south displacement.

1. North–south: $+9-10+1=0$, so P is on the same level as A.
2. East–west: $+7$ east then $8$ west → net $1\text{km}$ west of A.
3. To return, Mukesh must drive 1 km towards the east.

Trick: Add north, subtract south; add east, subtract west – net values give the answer.

Answer: (B) 1 km to the east

Concept: Four left turns starting north go: North → West → South → East → North.

1. North–south: $+8-12+4=0$ → P is level with A.
2. East–west: $9$ west then $11$ east → net $2\text{km}$ east of A.
3. So Radhe must drive 2 km towards the west to reach A.

Trick: Net east 2 km means the return trip is 2 km west.

Answer: (B) 2 km to the west

Concept: Find the letter shifts between the clusters of each triad.

1. KG-NJ-PR: K+3 = N, N+2 = P; G+3 = J, J+8 = R. MI-PL-RT follows the same.
2. OK-RN-TV: O+3 = R, R+2 = T; K+3 = N, N+8 = V ✓
3. Others fail, e.g. OK-RN-TU has N+7 = U.

Trick: Write the pattern as (+3, +2) for first letters and (+3, +8) for second letters.

Answer: (D) OK-RN-TV

Concept: Draw the least-overlap Venn diagram satisfying all statements.

1. All keys are doors → keys circle lies inside doors, so “Some keys are doors” is definitely true – Conclusion I follows.
2. Only some doors are cupboards, so “All doors are cupboards” is not certain – Conclusion II does not follow.

Trick: “All A are B” always gives “Some A are B” (and “Some B are A”).

Answer: (D) Only conclusion (I) follows.

Concept: Check every number: its left neighbour and right neighbour must both be numbers.

1. Series: 2 8 6 $ 4 * € 1 9 5 # 2 % 4 % © # 5 * 7 % *
2. 8 (between 2 and 6) ✓ and 9 (between 1 and 5) ✓
3. All other numbers have a symbol on at least one side.

Trick: Look only at runs of three or more consecutive numbers: “2 8 6” and “1 9 5” → middle digits count.

Answer: (B) 2

Concept: Number positions 1 (bottom) to 7 (top) and fix definite clues.

1. Three boxes below D → D at position 4.
2. Two between D and U → U at 1 or 7; only G above T → G = 7, T = 6, so U = 1.
3. F above E above S in positions 2, 3, 5 → S = 2, E = 3, F = 5.
4. Second from bottom = S.

Trick: “Only G above T” fixes the top two at once.

Answer: (A) S

Concept: Replace letters with signs and solve using BODMAS.

1. (C) $32÷8-30+16\times 4$
2. $=4-30+64=38$ ✓
3. Check (A): $32\times 8+30-16÷4=282$ ✗

Trick: Start with the option whose division gives a small whole number.

Answer: (C) 32 P 8 S 30 R 16 Q 4

Concept: Arrange the digits in increasing order and count from the left.

1. Digits of 4917523: 4, 9, 1, 7, 5, 2, 3
2. Ascending: 1, 2, 3, 4, 5, 7, 9
3. Third from the left = 3

Trick: Third from left in ascending order = third smallest digit.

Answer: (D) 3

Concept: Track each letter position separately using place values (A = 1 … Z = 26).

1. 1st letters: X → R → L → F → Z (each −6, F−6 wraps to Z)
2. 2nd letters: C → W → Q → K → E (each −6)
3. 3rd letters: H → B → V → P → J (each −6)

Trick: All three positions move −6 – just shift FKP back by 6: ZEJ.

Answer: (B) ZEJ

Concept: Interchange the signs first, then apply BODMAS.

1. New expression: $127\times 7-324÷4+47$
2. $=889-81+47$
3. $=855$

Trick: Rewrite the whole expression with new signs before calculating.

Answer: (A) 855

Concept: Fix the positions given by "only" conditions from the top and the bottom first.

1. "Only A is above C" → A is 1st (top) and C is 2nd.
2. "Only F is between C and E" → F is 3rd, E is 4th.
3. "Only B is below G" → B is 7th (bottom), G is 6th; D gets the 5th place.
4. Boxes above E: A, C, F = 3.

Trick: "Only X above Y" means X is at the very top and Y is just below it.

Answer: (B) 3

Concept: Find the highest and lowest of the given numbers, then use their first digits.

1. Numbers: 236, 758, 230, 563, 263.
2. Highest $=758$ (first digit 7); lowest $=230$ (first digit 2).
3. $7-2=5$.

Trick: Compare first digits first, then the second digits only for a tie (230 vs 236).

Answer: (A) 5