RRB NTPC Graduate CBT 1 2024 PYQs

Concept: Fix the fixed clues first (D, A, F), then place the pair B–E in the remaining floors.

1. D is on an odd floor except 5, so D = 1 or 3.
2. D + A = 5: if D = 1, A = 4; if D = 3, A = 2.
3. Exactly 3 people between A and F: A = 4 gives no valid F (needs 0 or 8), so D = 3, A = 2, F = 6.
4. Floors left: 1, 4, 5. B is immediately above E, so E = 4, B = 5 and C = 1.
5. Only F (floor 6) is above B, so 1 person.

Trick: In floor puzzles, test both cases of a sum clue; the case that breaks the "gap" clue is rejected at once.

Answer: (D) 1

Concept: Draw the least-overlap Venn diagram; a conclusion follows only if it is true in every possible diagram.

1. All curtain are screen and all curtain are blinder, so the curtain circle lies inside both screen and blinder.
2. Hence some blinder (the curtain part) are screen – Conclusion II definitely follows.
3. Drape only overlaps blinder; it can lie completely outside curtain, so "Some drape are curtain" is not certain – Conclusion I does not follow.

Trick: Two "All" statements with the same subject (All A are B, All A are C) always give "Some B are C".

Answer: (D) Only conclusion (II) follows

Concept: Look at the differences between consecutive terms.

1. Differences: $1012-1010=2$, $1010-1000=10$, $1000-998=2$, $998-988=10$.
2. Pattern alternates $-2,-10$; next is $-2$: $988-2=986$.
3. Check: $986-10=976$ ✓.

Trick: Alternating differences are common – always verify with the term after the blank.

Answer: (D) 986

Concept: Identify the highest and lowest numbers, pick the asked digits, then operate in the stated order.

1. Numbers: 983, 986, 481, 941, 167. Highest $=986$, lowest $=167$.
2. Third digit of highest $=6$; first digit of lowest $=1$.
3. "6 subtracted from 1" means $1-6=-5$.

Trick: "X subtracted from Y" $=Y-X$ – read the order carefully.

Answer: (C) $-5$

Concept: Identify the highest and lowest numbers, pick the asked digits, then operate in the stated order.

1. Numbers: 951, 474, 717, 497, 127. Highest $=951$, lowest $=127$.
2. First digit of highest $=9$; third digit of lowest $=7$.
3. "9 subtracted from 7" means $7-9=-2$.

Trick: "X subtracted from Y" $=Y-X$; a negative answer is expected here.

Answer: (C) $-2$

Concept: Apply the rule digit by digit, write the new number, then read positions.

1. 9368547 → 9 (odd) $-2=7$, 3 $\to 1$, 6 (even) $+1=7$, 8 $\to 9$, 5 $\to 3$, 4 $\to 5$, 7 $\to 5$.
2. New number: 7179355.
3. Third from left $=7$; third from right $=3$.
4. Sum $=7+3=10$.

Trick: Only the needed positions matter: 3rd from left is 6 → 7, 3rd from right is 5 → 3.

Answer: (B) 10

Concept: A letter common to both words gets the digit common to both codes.

1. FIGS → 3648 and ICED → 1285.
2. The only common letter is I; the only common digit is 8.
3. Hence I = 8.

Trick: Common letter ↔ common digit – no need to decode the other letters.

Answer: (B) 8

Concept: Track the net east–west and north–south displacement.

1. From A: 21 km south, left → 7 km east, left → 26 km north, left → 11 km west, left → 5 km south.
2. North–south: $-21+26-5=0$, so P is on the same level as A.
3. East–west: $7-11=-4$, so P is 4 km west of A.
4. To return to A he must drive 4 km towards the east.

Trick: Add all east–west moves and all north–south moves separately; the sign tells the direction.

Answer: (A) 4 km to the east

Concept: Build a family tree from the clues and read the relation.

1. B is the father of C; Q is the sister of C, and T is Q's only sister – so C, Q, T are siblings and B is their father.
2. T is the child of S, so S is also a parent of C, Q and T.
3. M is the son of S's only son – S's only son is C, so S is a parent; S is the mother (female) and B is the father.
4. Hence S is B's wife.

Trick: Two different parents of the same children (one is "father") → the other is the mother, i.e. the wife.

Answer: (B) Wife

Concept: Track the net east–west and north–south displacement.

1. From M: 1 km south, right → 3 km west, left → 3 km south, left → 4 km east, left → 4 km north.
2. North–south: $-1-3+4=0$, so N is level with M.
3. East–west: $-3+4=1$, so N is 1 km east of M.
4. To reach M he must drive 1 km towards the west.

Trick: Facing south, a right turn means west; facing west, a left turn means south.

Answer: (A) 1 km towards the west

Concept: Number positions 1 (top) to 7 (bottom) and place the definite boxes first.

1. Only F is above E → F = 1, E = 2. Four boxes between E and D → D = 7.
2. Positions 3–6 remain for G, S, T, U. T and U have two boxes between them → T, U take 3 and 6; G, S take 4 and 5 (G immediately above S).
3. U is not immediately above G, so U ≠ 3 → U = 6, T = 3.
4. Order: F, E, T, G, S, U, D → fourth from top = G.

Trick: A "gap of 2" pair inside a block of 4 must sit at the two ends of that block.

Answer: (B) G

Concept: Total $=$ rank from top $+$ rank from bottom $-1$.

1. Total $=36+18-1$.
2. $=53$ students.

Trick: Subtract 1 because Vinod is counted in both ranks.

Answer: (B) 53

Concept: Place the people whose positions are fixed first (all face north, so left = left of the line).

1. Only M sits to the left of N → M = 1, N = 2.
2. Four people between M and L → L = 6.
3. D, E, F, G go to 3, 4, 5, 7. F is between G and D (G _F_ D), and G is not next to L, so G ≠ 5, 7 → G = 3, F = 4, D = 5.
4. E = 7, the extreme right.

Trick: When a block of three (G F D) must fit, check which free slots are consecutive.

Answer: (C) E

Concept: Track each letter position of the clusters separately.

1. First letters: E, F, G, ?, I → +1 each → H.
2. Second letters: N, L, J, ?, F → −2 each → H.
3. Third letters: U, S, Q, ?, M → −2 each → O.
4. Missing cluster = HHO.

Trick: Split the clusters into columns and the pattern is visible at once.

Answer: (A) HHO

Concept: Use alphabet positions (A = 1 … Z = 26) and find the gaps between consecutive letters (wrap Z → A).

1. KEBW: K(11) −6 → E(5) −3 → B(2) −5 → W (wrap).
2. QKHC: Q(17) −6 → K(11) −3 → H(8) −5 → C(3). FZWR: F(6) −6 → Z (wrap) −3 → W(23) −5 → R(18).
3. WQNJ: W(23) −6 → Q(17) −3 → N(14) −4 → J(10) – last gap is −4, not −5.

Trick: Learn EJOTY (5, 10, 15, 20, 25) to get letter positions fast.

Answer: (A) WQNJ

Concept: All face north; fix M first, then R, L and finally the I–J–K block.

1. No one to the right of M → M = 7. Three between M and R → R = 3. Two between R and L → L = 6.
2. Free seats: 1, 2, 4, 5. J is immediately right of I, so I–J = 1–2 or 4–5; K is third to the left of I, so I = 4, J = 5, K = 1.
3. N = 2. Row: K, N, R, I, J, L, M.
4. Between N (2) and L (6): R, I, J → three people.

Trick: People between seats $p$ and $q$ $=|p-q|-1=6-2-1=3$.

Answer: (D) Three

Concept: Write the direct codes, then check each condition in order on the first, second, third and last elements.

1. 5#64%: direct codes 5 → A, # → N, 6 → P, 4 → K, % → G, i.e. A N P K G.
2. Condition (i): first element 5 is a number, last element % is a symbol → interchange their codes → G N P K A.
3. Condition (ii) fails (last is not an odd number); condition (iii) fails (# is not a number).
4. Code = GNPKA.

Trick: Test the conditions on the given string before writing codes – only the matching one changes the result.

Answer: (C) GNPKA

Concept: Apply the rule to each digit and read the required position.

1. 1865374: 1 (odd) $+1=2$, 8 (even) $-1=7$, 6 $\to 5$, 5 $\to 6$, 3 $\to 4$, 7 $\to 8$, 4 $\to 3$.
2. New number: 2756483.
3. Third digit from the left $=5$.

Trick: Only the third digit matters: 6 is even → $6-1=5$.

Answer: (C) 5

Concept: Find the rule from the complete pair (or the internal pattern) and test options.

1. Inside DZT: D −4 → Z, Z −6 → T; inside QMG: Q −4 → M, M −6 → G. Both clusters use the gaps −4, −6.
2. Option B: YUO → Y −4 → U, U −6 → O ✓ and VRL → V −4 → R, R −6 → L ✓.
3. Also the pairs match: YUO +5 each → DZT, and QMG +5 each → VRL.

Trick: Pair rule "+5 to each letter" works both sides: Y→D, U→Z, O→T and Q→V, M→R, G→L.

Answer: (B) # = YUO, % = VRL

Concept: Apply the rule to each digit, then find the highest and lowest digits.

1. 1862547: 1 $\to 2$, 8 $\to 6$, 6 $\to 4$, 2 $\to 0$, 5 $\to 6$, 4 $\to 2$, 7 $\to 8$.
2. New number: 2640628.
3. Highest $=8$, lowest $=0$; difference $=8-0=8$.

Trick: Watch for 2 → 0: a zero often becomes the lowest digit.

Answer: (B) 8