RRB NTPC Graduate CBT 1 2024 PYQs

Concept: Apply the rule to each digit of 1437586.

1. Odd +1: 1→2, 3→4, 7→8, 5→6
2. Even −2: 4→2, 8→6, 6→4
3. New number: 2 2 4 8 6 6 4
4. Highest − lowest $=8-2=6$

Trick: Only the extreme digits matter: 7 becomes 8 (max), 1 and 4 become 2 (min).

Answer: (A) 6

Concept: Look at the differences.

1. 901 → 900 → 897 → 892 → 885: differences −1, −3, −5, −7
2. Next difference −9
3. $885-9=876$

Trick: Subtracting consecutive odd numbers: $901-n^2$ pattern ($901-25=876$).

Answer: (B) 876

Concept: Find the operations between consecutive numbers.

1. 11 → 12 → 13 → 26: +1, +1, ×2
2. 19 → 20 → 21 → 42: +1, +1, ×2
3. 7 → 8 → 9 → 18: +1, +1, ×2 ✔
4. 9-10-11-24, 3-4-5-12, 4-5-6-10 fail at the last step.

Trick: Check the last step first: it must be exactly double.

Answer: (C) 7 - 8 - 9 - 18

Concept: Pattern needed: symbol – number – number.

1. Series: 6 @ 8 £ 5 @ $ 7 & 3 6 & # 9 # 1 * £ 5
2. Check numbers after a symbol: 8 (next £ ✘), 5 (next @ ✘), 7 (next & ✘), 3 (& 3 6 ✔), 9 (next # ✘), 1 (next * ✘), last 5 ✘.
3. Only one such number.

Trick: Scan only numbers that follow a symbol; then check the next item.

Answer: (D) One

Concept: Facing the centre: left = clockwise, right = anticlockwise.

1. H is immediate right of D. Counting left of H: D, two more, then I (three between).
2. C is three away from D on the other side; A is immediate right of G → G and A fill the seats next to D on the left, B takes the last seat.
3. Order clockwise from D: D, A, G, I, C, B, H.
4. From G going right (anticlockwise): A, then D → one person between.

Trick: Draw the circle and fix D first; all other clues hang on it.

Answer: (A) One

Concept: Pattern needed: number – symbol – number.

1. Series: 4 6 & 8 $ 7 & 3 9 # % 4 6 @ £ 5 Ω 9 # 1 * 7
2. ✔: 6 & 8, 8 $ 7, 7 & 3, 5 Ω 9, 9 # 1, 1 * 7
3. ✘: # % (9 # %), % (# % 4), @ (6 @ £), £ (@ £ 5)
4. Total = 6

Trick: Mark every symbol and check both neighbours.

Answer: (C) Six

Concept: Read the table, then test each condition on @ 9 7 8 3.

1. Direct codes: @ = W, 9 = C, 7 = Z, 8 = T, 3 = L.
2. (i) First is a symbol (@), last a number (3) → swap their codes: first = L, last = W.
3. (ii) does not apply (first is not an odd number). (iii) 9 is a square but 7 is not → no change.
4. Code: L C Z T W

Trick: Test conditions in order; only one usually applies.

Answer: (A) L C Z T W

Concept: When two words share a letter, the digit common to both codes is the code of that common letter.

1. MUTE → 3517 and EARS → 2458.
2. The only letter common to both words is E.
3. The only digit common to both codes is 5. So E = 5.

Trick: Common letter ↔ common digit – no need to decode the other letters.

Answer: (B) 5

Concept: Find the letter shifts in one pair and apply the same shifts to the other pair.

1. Try # = PQG: P − 3 = M, Q − 5 = L, G − 3 = D → MLD ✓ (pattern −3, −5, −3).
2. Apply to VAM: V − 3 = S, A − 5 = V (wrap: A → Z, Y, X, W, V), M − 3 = J → SVJ.
3. So # = PQG and % = SVJ.

Trick: Only option (C) gives MLD from # with a consistent pattern; check it on the right side.

Answer: (C) # = PQG, % = SVJ

Concept: Two 'Some' statements linked through a middle term never give a definite conclusion between the end terms.

1. Some deers are lions, some frogs are deers: frogs touch deers, but nothing fixes frogs with lions → (I) does not follow.
2. Some deers are lions, some horses are lions: deers and horses are linked only through lions (some + some) → (II) does not follow.
3. The diagram shows a valid case where neither overlap exists.

Trick: Some + Some = No conclusion.

Answer: (B) Neither conclusion (I) nor (II) follows.

Concept: Decode each symbol step by step and build the family tree from M to Q.

1. M + N: M is the mother of N.
2. N ÷ O: N is the father of O.
3. O × P: O is the wife of P; P – Q: P is the brother of Q.
4. Going from Q: Q's brother P → P's wife O → O's father N → N's mother M.

Trick: Read the chain backwards from Q to M and name each link in order.

Answer: (A) Brother's wife's father's mother

Concept: Track each position of the three-letter groups separately.

1. 1st letters: N, P, R, T → +2 each → next V.
2. 2nd letters: K, M, O, Q → +2 each → next S.
3. 3rd letters: R, T, V, X → +2 each → next Z.
4. Next term = VSZ.

Trick: Every letter moves +2 – just add 2 to each letter of TQX.

Answer: (C) VSZ

Concept: Look for the pattern symbol – symbol – number, scanning left to right.

1. & % 4 → % is preceded by a symbol and followed by a number ✓.
2. * £ 5 → £ is preceded by a symbol and followed by a number ✓.
3. Others fail: e.g. 9 & % (preceded by number), 8 $ 7 (preceded by number), 3 Ω (followed by nothing).
4. Count = 2.

Trick: First mark every symbol followed by a number, then keep only those with a symbol before them.

Answer: (A) Two

Concept: Check the differences between consecutive terms.

1. 215 − 187 = 28, 187 − 161 = 26, 161 − 137 = 24, 137 − 115 = 22, 115 − 95 = 20.
2. Differences fall by 2 each time, so the next difference is 18.
3. $95-18=77$.

Trick: Differences 28, 26, 24, 22, 20, 18.

Answer: (C) 77

Concept: Fix people with sure positions first, then fill the remaining floors.

1. F is even, not 6 → 2 or 4. F + C = 3 → F = 2, C = 1.
2. D + F = 7 → D = 5.
3. Left: floors 3, 4, 6. B immediately above A → A = 3, B = 4; E = 6.
4. Between B (4) and F (2): only A → one person.

Trick: Start with the 'sum = 3' clue – only 1 + 2 works.

Answer: (D) One

Concept: Track net east–west and north–south movement from A.

1. East 11; right → south 5; right → west 12; right → north 10; right → east 1.
2. East–west: $11-12+1=0$ → P is directly in line with A.
3. North–south: $-5+10=+5$ → P is 5 km north of A.
4. So from P he must drive 5 km towards the south.

Trick: Four right turns in a row bring you back to the original direction (east) – just add the signed distances.

Answer: (B) 5 km to the south

Concept: Place the fixed person first, then fit the pairs into the remaining days.

1. S = Friday. Two people between S and R → R = Tuesday (Friday + 3 goes beyond Sunday).
2. P and M are consecutive (P, then M) and before Friday, Tuesday taken → P = Wednesday, M = Thursday.
3. O immediately before N: free days Monday, Saturday, Sunday → O = Saturday, N = Sunday.
4. Remaining day for Q: Monday.

Trick: Fit the consecutive pairs first; the leftover single day belongs to Q.

Answer: (C) Monday

Concept: When facing the centre, a person's left is clockwise and right is anticlockwise.

1. Fix R. Three between R and Q from R's left → Q is 4th clockwise from R.
2. T is a neighbour of Q and of U. If T, U lie between R and Q, then V (3 seats to the right of U, i.e. 4th clockwise) and S (right of V) clash with Q. So T and U come after Q: R, _, _, _, Q, T, U clockwise.
3. V is 4th from U to its right → V is 2nd clockwise from R; S (immediate right of V) is 1st; P takes the last seat.
4. Clockwise: R, S, V, P, Q, T, U. From P to the right (anticlockwise): V, S, R, U, then T → 4 people between.

Trick: With 7 seats, '3 between one way' = '2 between the other way' – use it to cross-check.

Answer: (A) 4

Concept: Find the change in each letter and in the number.

1. RD 14 → UF 10: R + 3 = U, D + 2 = F, 14 − 4 = 10.
2. CR 10 → FT 6: C + 3 = F, R + 2 = T, 10 − 4 = 6 ✓.
3. ON 1 → O + 3 = R, N + 2 = P, 1 − 4 = −3 → RP −3.

Trick: Rule = (+3, +2, −4); only option (C) has first letter R and second letter P.

Answer: (C) RP −3

Concept: Swap the signs first, then apply BODMAS.

1. After interchange: $66\times 8+231÷11-14$.
2. $66\times 8=528$, $231÷11=21$.
3. $528+21-14=535$.

Trick: Rewrite the whole expression with new signs before calculating – avoids mixing up.

Answer: (D) 535