RRB Technician Grade III 2024, 2025 PYQs

Concept: Use the “only” clues to fix exact positions from top and bottom.

1. Only A is above E ⇒ A at top, E second.
2. Only F between E and B ⇒ F third, B fourth.
3. Only P below M ⇒ P at bottom, M just above it.
4. L takes the remaining place (5th from top). Between L and P: only M.

Trick: “Only X is above Y” fixes X at top and Y at 2nd immediately.

Answer: (A) One

Concept: Look at consecutive differences/ratios; here two operations alternate.

1. $36\times 2=72$, $72-27=45$
2. $45\times 2=90$, $90-27=63$
3. $63\times 2=126$, $126-27=99$

Trick: When numbers go up and down alternately, test “$\times$ then −” pattern.

Answer: (B) 99

Concept: For each symbol check: left neighbour odd number AND right neighbour a symbol.

1. Symbols followed by a symbol: * (before £) and & (before %).
2. * is preceded by 1 (odd) ✓
3. & is preceded by 5 (odd) ✓
4. Others fail (e.g. @ → followed by 8). Total = 2.

Trick: First find “symbol-symbol” pairs, then check only their left neighbour.

Answer: (B) Two

Concept: Trace the path with right turns: North → East → South → West.

1. A to 10 km North.
2. Right: 3 km East; Right: 6 km South (now 4 km north of A’s level).
3. Right: 3 km West ⇒ back on A’s north line, 4 km north of A (this is B).
4. To return to A: 4 km South.

Trick: East 3 and West 3 cancel; net north $=10-6=4$ km.

Answer: (D) 4 km South

Concept: Find the operation linking 1st → 2nd → 3rd number in both given sets.

1. $3\times 4=12$, $12\times 3=36$
2. $8\times 4=32$, $32\times 3=96$
3. Option: $12\times 4=48$, $48\times 3=144$ ✓

Trick: Third number $=12\times$ first: $12\times 12=144$.

Answer: (D) (12, 48, 144)

Concept: Write letter positions and compare the moves within each pair.

1. LH-KN: L(12)−4=H(8); L−1=K(11); K+3=N(14).
2. NJ-MP and JF-IL follow the same: −4, −1, +3.
3. QM-PR: Q(17)−4=M(13); Q−1=P(16); P+3=S(19), but given R(18) ✗

Trick: Check only one relation (e.g. 2nd letter of first cluster +6 = last letter): H+6=N, J+6=P, F+6=L, M+6=S≠R.

Answer: (D) QM-PR

Concept: Start with the most definite clue (“only P to the right of Q”) and fill the row facing north.

1. Only P is right of Q ⇒ Q at 6th, P at 7th (from left).
2. One person between E and Q ⇒ E at 4th.
3. Two between A and E ⇒ A at 1st.
4. B, R, F in 2nd, 3rd, 5th with B left of R left of F ⇒ A B R E F Q P. 3rd from right = F.

Trick: Facing north: your right = the right end of the row.

Answer: (B) F

Concept: Compare positions: in each triad the first letters go +1, +2 and the second letters go +2, +6.

1. PL-QN-ST: P→Q (+1)→S (+2); L→N (+2)→T (+6).
2. JF-KH-MN: J→K→M; F→H (+2)→N (+6) ✓
3. MI-NK-PQ: M→N→P; I→K (+2)→Q (+6) ✓
4. Other options give +7 in the last step (e.g. O→V).

Trick: Also in each first pair, 2nd letter = 1st letter −4 (P−4=L, M−4=I).

Answer: (A) MI-NK-PQ

Concept: Condition: symbol with an even number just before it AND a symbol just after it.

1. Even numbers in the series: only 8 (in “5 8 $ 7”).
2. The symbol after 8 is $, which is followed by 7 (a number) ✗
3. No other symbol has an even number before it. Count = 0.

Trick: Start from the rarer condition — here even numbers are very few.

Answer: (A) None

Concept: Find odd digits whose both neighbours are also odd (odd–odd–odd triplets).

1. “2 7 5 1 3 4”: 5 (7 before, 1 after) ✓; 1 (5 before, 3 after) ✓
2. “4 1 9 3”: 9 (1 before, 3 after) ✓
3. Other odd runs like “3 7 4” or “9 5 2” break the rule.
4. Count = 3.

Trick: Look for runs of three or more odd digits; each inner digit counts.

Answer: (C) 3

Concept: Find the operation from the complete pair in an option and apply it to both sides.

1. Rule: second number $=\frac{\text{first}}{4}$
2. $76÷4=19$ ✓ and $92÷4=23$ ✓
3. Other options fail, e.g. $98÷4$ is not 19.

Trick: Since $92\to Y$ and $X\to 19$ use the same rule, test $X=4\times 19=76$.

Answer: (C) X = 76, Y = 23

Concept: Letters common to both words share the digits common to both codes.

1. REVS → 6942; ORES → 6421
2. Common letters R, E, S ↔ common digits 6, 4, 2
3. Left over: V ↔ 9 (and O ↔ 1)

Trick: Remove the common part; the leftover letter takes the leftover digit.

Answer: (B) 9

Concept: Swap the signs first, then apply BODMAS.

1. After swapping: $35÷7-2\times 6+13$
2. $=5-12+13$
3. $=6$

Trick: Rewrite the whole expression with new signs before calculating.

Answer: (B) 6

Concept: Replace letters by operators, then use BODMAS.

1. $16+24÷3\times 8-5$
2. $24÷3=8$, $8\times 8=64$
3. $16+64-5=75$

Trick: Division and multiplication are done left to right before + and −.

Answer: (A) 75

Concept: All face north; fix definite positions first, then neighbours.

1. B third from right ⇒ B at 5th (from left).
2. Only one person left of D ⇒ D at 2nd.
3. F right of B, left of G ⇒ F 6th, G 7th.
4. E is neighbour of both C and D ⇒ E 3rd, C 4th, A 1st. Row: A D E C B F G ⇒ 5 people between A and G.

Trick: “E is neighbour of C and D” means E sits between them.

Answer: (B) Five

Concept: Decode each symbol from left to right and draw the family tree.

1. A + B: A is sister of B (A is female).
2. B − C: B is son of C.
3. C × D: C is husband of D ⇒ D is mother of A and B.
4. D ÷ E: D is daughter of E ⇒ A is daughter of E’s daughter.

Trick: Mark gender with each code (sister/daughter = female) to fix the final relation.

Answer: (C) Daughter’s daughter

Concept: Letters common to both words share the digits common to both codes.

1. REPS → 9631; EARS → 6914
2. Common letters R, E, S ↔ common digits 9, 6, 1
3. Left over: A ↔ 4 (and P ↔ 3)

Trick: Remove the common part; the leftover letter takes the leftover digit.

Answer: (D) 4

Concept: Draw the Venn diagram; a conclusion follows only if it is true in every possible diagram.

1. Door and Lock are separate; Lock and Key are separate.
2. Door and Key may or may not overlap ⇒ I (No door is a key) is not certain.
3. “No door is a lock” is the same as “No lock is a door” ⇒ II follows.

Yaad rakhein: “No A is B” can always be reversed to “No B is A”. Two negative statements give no definite link between the end terms.

Answer: (B) Only conclusion II follows

Concept: A valid course of action should solve the stated problem practically, without being extreme.

1. Problem: traffic jam due to illegal parking at drop-off time.
2. I: Deploying security to monitor parking and clear jams directly tackles it ⇒ follows.
3. II: Banning all car drops is extreme and impractical; parents can drop children legally ⇒ does not follow.

Trick: Reject actions with “ban/stop all” type extreme words unless the situation demands it.

Answer: (B) Only I follows

Concept: Check each letter position of the clusters separately.

1. 1st letters: O, Q, S, U → +2 → W
2. 2nd letters: R, T, V, X → +2 → Z
3. 3rd letters: N, P, R, T → +2 → V

Trick: Every letter moves +2, so just add 2 to each letter of UXT.

Answer: (B) WZV