RRB Technician Grade III 2024, 2025 PYQs

Concept: The word common to both sentences has the common code.

1. 'mind your business' → gv tr fy
2. 'your turn now' → cb gv kq
3. Common word 'your' = common code gv

Trick: Spot the code present in both lines: gv.

Answer: (B) gv

Concept: Find the shift rule followed by three pairs.

1. DF − BD: −2, −2
2. OQ − MO: −2, −2; UW − SU: −2, −2
3. IK − FK: −3, 0 → odd one

Trick: In the other pairs the 2nd cluster's last letter = 1st cluster's first letter (DF−BD, OQ−MO); IK−FK breaks it.

Answer: (D) IK−FK

Concept: Number positions 1 (bottom) to 7 (top) and place fixed clues first.

1. Five below E → E = 6
2. One box between C and E → C = 4
3. C not below G, and G above B above A → A = 1, B = 2, G = 3
4. F not top → F = 5, D = 7
5. Below F (5) is C (4)

Trick: Start with the exact clue (E at 6) — it locks C, then the A–B–G chain fits only below C.

Answer: (C) C

Concept: Track each letter position separately.

1. 1st: C, F, I, L → O (+3)
2. 2nd: H, K, N, Q → T (+3)
3. 3rd: M, K, I, G → E (−2)

Trick: First letter O leaves OTE and OLI; second letter T confirms OTE.

Answer: (A) OTE

Concept: Number seats 1–7 from the left (facing north) and fix definite positions first.

1. D 6th from right → seat 2; three between F and D → F = 6
2. E between Q and N (block Q–E–N), K two left of N
3. Only fit: K = 1, N = 3, E = 4, Q = 5, A = 7
4. Order: K D N E Q F A → third to left of A (7) = seat 4 = E

Trick: Try N's possible seats; the K–N gap of 2 plus the Q–E–N block works only with N = 3.

Answer: (C) E

Concept: Facing the centre: left = clockwise, right = anticlockwise.

1. Fix D. F is 2nd to the left of D, and E is 3rd to the left of F, which puts E just to the right of D
2. Only J sits between F and G, so J and G go on the side of F away from D; K takes the seat between D and F (K is then not next to E ✓)
3. Clockwise order: D, K, F, J, G, E
4. Going right (anticlockwise) from G: J, F, then K, so 2 people sit between them

Trick: In a 6-seat circle, '3rd to the left' = '3rd to the right' (directly opposite), so E is opposite F.

Answer: (A) Two

Concept: Total = rank from top + rank from bottom − 1.

1. Total = 22 + 10 − 1
2. = 31

Yaad rakhein: Subtract 1 because Nehal is counted twice, once from each end.

Answer: (D) 31

Concept: Track the net East–West and North–South movement.

1. West 32 → left (South) 51 → right (West) 66 → right (North) 14 → right (East) 45 → left (North) 37
2. West–East: −32 − 66 + 45 = −53, so Z is 53 km west of Y
3. South–North: −51 + 14 + 37 = 0, so no vertical gap
4. To return to Y: drive 53 km towards the east

Trick: North–south cancels out (51 = 14 + 37), so just add up the east–west parts.

Answer: (C) 53 km towards east

Concept: Vowels → next letter, consonants → previous letter.

1. L→K, A→B, R→Q, K→J, I→J, S→R, H→G
2. New group: K B Q J J R G
3. Only J appears exactly twice, so the count is 1

Trick: A repeat can come only when a consonant's −1 lands on a vowel's +1: K−1 = J = I+1.

Answer: (C) 1

Concept: Shift each letter by +1, then sort the new letters alphabetically.

1. BESWARM → C F T X B S N
2. Sorted: B C F N S T X
3. 4th from right: X, T, S, N, so the answer is N

Trick: With 7 letters, 4th from the right = 4th from the left (the middle one) = N.

Answer: (D) N

Concept: Each term is double the previous term.

1. $13\times 2=26$, $26\times 2=52$, … $208\times 2=416$

Trick: The answer must be even (it is double of something), so 415 and 417 are out right away.

Answer: (B) 416

Concept: Find the net displacement from A.

1. North 5 → left (West) 6 → left (South) 7 → left (East) 8 → left (North) 2
2. East–West: −6 + 8 = +2, so P is 2 km east of A
3. North–South: 5 − 7 + 2 = 0
4. To return to A: 2 km to the west

Trick: Four left turns bring him back to facing north; just net the opposite pairs (W 6 vs E 8; N 5 + 2 vs S 7).

Answer: (A) 2 km to the west

Concept: For each digit, check: previous digit even AND next digit odd.

1. Scan for an even digit followed by X and then an odd digit
2. 2 5 1, 6 8 3, 4 9 7, 2 6 1, 6 1 7
3. Total = 5

Trick: First mark every even digit, then check only the two digits that come after it. This is faster than checking every position.

Answer: (C) Five

Concept: Check the gaps between letter positions.

1. KNL: 11 → 14 → 12 (+3, −2)
2. NQO: 14 → 17 → 15 (+3, −2); RUS: 18 → 21 → 19 (+3, −2)
3. MHG: 13 → 8 → 7 (−5, −1), which does not fit

Trick: In three clusters the 3rd letter is just after the 1st (K-L, N-O, R-S). MHG breaks this.

Answer: (A) MHG

Concept: Decode each symbol and link the relations step by step.

1. A + B: A is the daughter of B
2. B @ H: B is the father of H, so A is H's sister
3. H # K: H is the mother of K; K ÷ T: K is the wife of T
4. H is T's wife's mother, so A is T's wife's mother's sister

Trick: Read from T backwards: T → wife K → her mother H → H's sister A.

Answer: (B) Wife's mother's sister

Concept: Letters common to both words share the common digits.

1. CURL = 4386, LURE = 5846
2. Common letters U, R, L ↔ common digits 4, 8, 6
3. Left over: C = 3 and E = 5

Trick: Cancel the common digits. The extra digit in LURE (5) belongs to its extra letter E.

Answer: (A) 5

Concept: Replace the letters with signs, then apply BODMAS.

1. $4\times 5-20÷2+17=?-3$
2. $20-10+17=27$
3. $?-3=27\Rightarrow ?=30$

Trick: Do ÷ and × first: $20÷2=10$ and $4\times 5=20$. Then remember to add 3 back on the right side.

Answer: (D) 30

Concept: Find the change in each letter's position from the first to the second cluster.

1. ZRD → WPC: Z−3 = W, R−2 = P, D−1 = C
2. WET → TCS: −3, −2, −1
3. YDG → VBF: Y−3 = V, D−2 = B, G−1 = F ✓

Trick: Check the last letter first (−1): only P→N (−2) and G→F (−1) are candidates, and YDG→VBF fits fully.

Answer: (D) YDG : VBF

Concept: The digit must be odd, the one before it odd, and the one after it even.

1. Look for the pattern odd → odd → even
2. 7 1 4, 9 5 2, 1 3 2
3. Total = 3

Trick: Look for two odd digits in a row; then just check whether the next digit is even (e.g. 3 9 5 counts only 5, not 9).

Answer: (D) Three

Concept: Replace the letters with signs, then apply BODMAS.

1. $5\times 2-10÷2+12=?-3$
2. $10-5+12=17$
3. $?=17+3=20$

Trick: Solve the left side, then add the 3 that is subtracted on the right.

Answer: (B) 20