RRB Technician Grade III 2024, 2025 PYQs

Concept: Find even digits with a perfect square (1, 4, 9) just before and an even digit just after.

1. 9 2 6 ✓; 1 2 6 ✓; 4 8 2 ✓
2. 9 8 6 ✓; 4 2 2 ✓
3. Total = 5

Trick: First mark every 1, 4, 9; then check only the digit right after each.

Answer: (B) Five

Concept: Letters common to both words take the digits common to both codes.

1. DUKE = 8123, DESK = 2314
2. Common letters D, E, K ↔ common digits 1, 2, 3
3. Leftover: U = 8 and S = 4

Trick: Cancel the common part; the leftover letter gets the leftover digit.

Answer: (B) 4

Concept: Shift each letter +1, then sort alphabetically.

1. DEARTHS → E F B S U I T
2. Sorted: B E F I S T U
3. 4th from right: U, T, S, I → I

Trick: In a 7-letter group, 4th from right = 4th from left (the middle).

Answer: (C) I

Concept: Track net north–south and east–west movement.

1. North 3, right → East 2, right → South 5, right → West 4, right → North 2
2. North–south: 3 − 5 + 2 = 0
3. East–west: 2 − 4 = 2 km west of A
4. So A is 2 km to the east of P

Trick: Four right turns bring you back to the start direction – just add the opposite legs.

Answer: (C) 2 km to the east

Concept: Number positions 1 (bottom) to 7 (top).

1. Two below D → D = 3; three between E and D → E = 7
2. Chain G > C > A > B > F fills 6, 5, 4, 2, 1
3. G = 6, C = 5, A = 4, B = 2, F = 1
4. Immediately above A is C

Trick: A 5-box chain into exactly 5 free slots forces a single order.

Answer: (A) C

Concept: Common letters match common digits; leftover matches leftover.

1. TYRE = 8526, BYTE = 5986
2. Common T, Y, E ↔ 5, 8, 6
3. Leftover: R = 2, B = 9

Trick: Strike out common digits 5, 8, 6 from 5986 → 9 left for B.

Answer: (A) 9

Concept: Number positions 1 (top) to 7 (bottom).

1. B = 3; three between D and B → D = 7
2. A below E but above B → E = 1, A = 2
3. G, C (just below G), F fill 4, 5, 6
4. Between C (5) and A (2): positions 3, 4 → two boxes

Trick: Place the fixed boxes first; blocks then fit only one way.

Answer: (A) Two

Concept: Replace letters by signs, then apply BODMAS.

1. $147÷3+51-16\times 3$
2. $=49+51-48$
3. $=52$

Yaad rakhein: Always do ÷ and × before + and −.

Answer: (A) 52

Concept: Link G to L through V.

1. G is mother of Y; Y is sister of V → G is mother of V
2. L is husband of V → V is L's wife
3. G = L's wife's mother (mother-in-law)

Trick: S (L's father) is extra information – ignore it.

Answer: (C) Wife's mother

Concept: Decode each symbol and move from G to K.

1. G × H: G is brother of H; H ÷ I: H is son of I → G is son of I
2. I − J: I is wife of J → G is son of J
3. J ÷ K: J is son of K
4. So G is K's son's son

Trick: G is male (he is a 'brother'), so 'son's son' fits; 'Mother's …' options are out.

Answer: (A) Son’s Son

Concept: Find consonant–consonant–vowel triplets.

1. J L O ✓
2. B G A ✓
3. Others fail (e.g. J in D J L is followed by a consonant; R in N R S is followed by S, not a vowel)
4. Total = 2

Trick: Look for vowels first, then check the two letters before each.

Answer: (C) Two

Concept: Check gaps between consecutive letters.

1. NPM: +2, −3
2. GIF: +2, −3; MOL: +2, −3
3. KHG: −3, −1 → odd

Trick: Three clusters move forward first; KHG moves backward at once.

Answer: (B) KHG

Concept: Find the letter-wise shift: +2, −2, −1.

1. KNG → MLF: +2, −2, −1
2. GRN → IPM: +2, −2, −1
3. JSN → LQM: J +2 L, S −2 Q, N −1 M ✓

Trick: Check the last letter (−1) first: BGM : DEK (M → K) and KHR : MFP (R → P) fail; then the middle (−2): IGH : KDG (G → D) fails.

Answer: (A) JSN : LQM

Concept: Every letter moves forward by 9.

1. EHLF → NQUO: E(5)→N(14), +9 each
2. JMQK: J→S, M→V, Q→Z, K→T
3. Answer: SVZT

Trick: J + 9 = S removes options starting with V; Q + 9 = Z picks SVZT.

Answer: (D) SVZT

Concept: Vowels → next letter; consonants → previous letter.

1. P→O, A→B, N→M, D→C, E→F, M→L, I→J, C→B
2. New group: O B M C F L J B
3. B appears twice

Trick: A (vowel) → B and C (consonant) → B both land on B.

Answer: (B) B

Concept: Common letters in two words share the common digits; the leftover letter gets the leftover digit.

1. SNOW → 1732, KNOW → 5317.
2. Common letters N, O, W ↔ common digits 1, 3, 7.
3. So S = 2 and K = 5.

Trick: Digit present in KNOW's code but not in SNOW's code = code of K → 5.

Answer: (B) 5

Concept: Compare each letter of the first cluster with the matching letter of the second.

1. QK → RL: +1, +1. HB → IC: +1, +1. MG → NH: +1, +1.
2. JD → LE: +2, +1 → different.

Trick: In the three alike pairs the second cluster is just the 'next letters' of the first — JD's next letters would be KE, not LE.

Answer: (C) JD - LE

Concept: Each letter moves back by the same number of places.

1. POK → GFB: P(16) − 9 = G(7), O − 9 = F, K − 9 = B.
2. FEA → WVR: F − 9 = W, E − 9 = V, A − 9 = R (wrapping round).
3. WVR → W − 9 = N, V − 9 = M, R − 9 = I → NMI.

Trick: −9 is the same as +17; or note WVR itself appears in the given pair, so just apply the same −9 to it.

Answer: (A) WVR−NMI

Concept: Track each position separately (mod 26).

1. 1st letters: S → H → W → L → A (each +15, i.e. −11).
2. 2nd letters: J → Y → N → C → R (+15).
3. 3rd letters: T → I → X → M → B (+15).
4. Missing term = ARB.

Trick: +15 = −11 in a circular alphabet; L(12) − 11 = A(1), C(3) + 15 = R(18), M(13) − 11 = B(2).

Answer: (B) ARB

Concept: Vowel → next letter; consonant → previous letter.

1. A → B, M → L, B → A, L → K, E → F, R → Q, S → R.
2. New group: B L A K F Q R.
3. All 7 letters are different → no letter appears twice.

Trick: Watch pairs like B→A and A→B or S→R and R→Q — they swap letters but don't create repeats here.

Answer: (B) Zero