RRB Technician Grade III 2024, 2025 PYQs

Concept: The only common letter takes the only common digit.

1. PART = 7642, TWIN = 1356.
2. Common letter: T; common digit: 6.
3. So T = 6.

Trick: One common letter + one common digit = direct answer.

Answer: (A) 6

Concept: Number positions from top (1) to bottom (7).

1. Five boxes above E → E = 6th.
2. Two between F and E → F = 3rd.
3. G below D, above F → D = 1st, G = 2nd.
4. C just above A → C = 4th, A = 5th; B = 7th.
5. Between B (7) and A (5): E → one.

Trick: Positions: D, G, F, C, A, E, B (top to bottom).

Answer: (B) One

Concept: Facing north: left end = position 1.

1. Two to the right of D → D = 5th. L immediate left of D → L = 4th.
2. Two between D and E → E = 2nd.
3. Two between J and L → J = 1st or 7th. If J = 7th, K-F can't sit together; so J = 1st.
4. K, F = 6th, 7th → C = 3rd.

Trick: Order: J E C L D K F.

Answer: (A) C

Concept: Each letter position moves +6.

1. 1st letters: P → V → B → H → N.
2. 2nd letters: I → O → U → A → G.
3. 3rd letters: O → U → A → G → M.
4. Answer: NGM.

Trick: Each term's 2nd letter = 1st letter + 19 (i.e. −7) and 3rd = 2nd + 6; simply add +6 down each column.

Answer: (B) NGM

Concept: Apply the same letter shifts and number change.

1. LN 17 → HJ 23: both letters −4, number +6.
2. SU 5 → OQ 11: same rule.
3. NP 9 → J L 15.

Trick: Number +6 leaves JL 15 and KL 15; N − 4 = J → JL 15.

Answer: (C) JL 15

Concept: Find the rule linking the three numbers.

1. (2, 10, 38): $2+8=10$; $10\times 4-2=38$.
2. (4, 12, 46): $4+8=12$; $12\times 4-2=46$ ✓.
3. (7, 15, 58): $7+8=15$; $15\times 4-2=58$ ✓.

Trick: First check 2nd = 1st + 8: only (7, 15, 58) and (5, 13, 54) pass; $13\times 4-2=50\ne 54$.

Answer: (A) (7, 15 , 58)

Concept: Decode each symbol step by step.

1. Q @ W: Q is sister of W. W + R: W is son of R.
2. R # G: R is wife of G. G ÷ H: G is father of H.
3. W and H are both children of G and R; Q is W's sister → Q is H's sister.

Trick: Q, W and H are siblings – same generation, so only 'Sister' fits.

Answer: (B) Sister

Concept: Swap + ↔ ÷ and − ↔ ×, then apply BODMAS.

1. $536÷67-9\times 22+283$
2. $=8-198+283$
3. = 93

Trick: $536÷67=8$ ($67\times 8=536$) – a clean division confirms the swap is right.

Answer: (A) 93

Concept: Decode each symbol step by step.

1. A + B: A is daughter of B. B # H: B is mother of H → A is H's sister.
2. H @ K: H is father of K.
3. K ÷ T: K is wife of T → H is T's wife's father.
4. A = T's wife's father's sister.

Trick: Go backwards from T: T → wife K → her father H → his sister A.

Answer: (D) Wife's father's sister

Concept: A vowel preceded by a vowel needs two vowels side by side.

1. Vowels in the series: O (after M) and O (after Z).
2. Both are preceded by consonants (M, Z).
3. No vowel is preceded by a vowel → none.

Trick: If no two vowels are adjacent, the answer is 'None' immediately.

Answer: (D) None

Concept: Decode each symbol and build the chain from Z to N.

Solution:

1. Z o C → Z is father of C
2. C ≥ L → C is wife of L
3. L @ M → L is brother of M; M x N → M is daughter of N, so L is N's son
4. C = N's son's wife; Z = her father → Z is N's son's wife's father

Trick: Read the chain backwards from N: son (L) → wife (C) → father (Z).

Answer: (C) Son's wife's father

Concept: A word common to two sentences gets the code common to both.

Solution:

1. 'share' appears in both sentences
2. Codes common to 'tn dp bk' and 'ps tn hv' = tn
3. share = tn

Trick: Just find the repeated word and the repeated code — no need to decode the rest.

Answer: (C) tn

Concept: Find the letter shifts from the first group to the second.

Solution:

1. W → V (−1), R → P (−2), T → Q (−3)
2. G → F (−1), U → S (−2), A → X (−3)
3. NXR: N − 1 = M, X − 2 = V, R − 3 = O → MVO ✓

Trick: Check the last letter first (−3): only option D gives R → O.

Answer: (D) NXR : MVO

Concept: Trace the relation from Bheem through his wife.

Solution:

1. Vidhi is Bheem's wife
2. Harshita and Vidhi are sisters; Ganesh is father of Harshita → Vidhi's father
3. Suraj is Ganesh's brother → Vidhi's uncle
4. So Suraj = Bheem's wife's father's brother

Trick: Start from Bheem: wife (Vidhi) → father (Ganesh) → brother (Suraj).

Answer: (C) Wife's father's brother

Concept: Locate both letters, then count letters between them in the A–Z alphabet.

Solution:

1. 5th from left: L F Q T G → G
2. 3rd from right: H, N, K → K
3. Between G and K in alphabet: H, I, J → 3

Trick: Letters between two letters = difference of positions − 1: K(11) − G(7) − 1 = 3.

Answer: (B) Three

Concept: Find the position gaps in each cluster.

Solution:

1. EJH: 5 → 10 → 8 (+5, −2)
2. PUS: 16 → 21 → 19 (+5, −2); QVT: 17 → 22 → 20 (+5, −2)
3. UHG: 21 → 8 → 7 — does not follow

Trick: Second letter is 5 ahead of the first in three clusters; in UHG it is behind.

Answer: (A) UHG

Concept: Swap the signs as told, then apply BODMAS.

Solution:

1. After swap: $7\times 2-64÷8+8$
2. $=14-8+8$
3. $=14$

Trick: Rewrite the full expression first; don't swap mentally while calculating.

Answer: (B) 14

Concept: Replace letters by signs, then use BODMAS.

Solution:

1. $71+45\times 5-15÷5\times 6+13-74+69$
2. $45\times 5=225$; $15÷5\times 6=18$
3. $71+225-18+13-74+69=286$

Trick: Last-digit check: $1+5-8+3-4+9=6$ → answer ends in 6 → 286 or 246; then exact sum gives 286.

Answer: (A) 286

Concept: Check each vowel's left and right neighbours.

Solution:

1. Vowels: E (B _ X ✓), I (X _ O ✗), O (I _ R ✗), O (M _ T ✓)
2. Qualifying vowels: E and the last O
3. Count = 2

Trick: Only vowels need checking — scan for A, E, I, O, U and look at both sides.

Answer: (B) Two

Concept: Each letter shifts by the same amount.

Solution:

1. B → Z, Y → W, R → P: each −2
2. H → F, E → C, Z → X: each −2
3. SIV → QGT (each −2) ✓

Trick: Check only the first letter (−2): S → Q fits A; G → D, M → L fail.

Answer: (A) SIV : QGT