SSC CPO Paper I · 6,600 questions

SSC CPO Paper I 2020, 2022, 2023, 2024 PYQs

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6,600 questions.

Q5941.

What is the least number of soldiers that can be drawn up in troops of 10, 12, 15, 18 and 20 soldiers, and also in form of a solid square?

सैनिकों की वह न्यूनतम संख्या क्या है जिन्हें 10, 12, 15, 18 और 20 सैनिकों की टुकड़ियों में और साथ ही एक ठोस वर्ग के रूप में भी व्यवस्थित किया जा सके?

A400
B625
C900
D180

Show answer

Concept: The number must be a multiple of the LCM and a perfect square.

$LCM (10, 12, 15, 18, 20) = 180 = 2^{2} \times 3^{2} \times 5$ .
Make every power even: multiply by 5 → $900 = 30^{2}$ .

Trick: Check options: 400 and 625 are not divisible by 18; 180 is not a square.

Answer: (C) $900$

अवधारणा: संख्या LCM का गुणज और पूर्ण वर्ग दोनों होनी चाहिए।

$LCM = 180 = 2^{2} \times 3^{2} \times 5$ ।
सभी घात सम करें: 5 से गुणा → $900 = 30^{2}$ ।

ट्रिक: 400, 625 में 18 का भाग नहीं; 180 वर्ग नहीं।

उत्तर: (C) $900$

SSC CPO Paper IQuantitative AptitudeLCM – Perfect SquareSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5942.

The value of

- 7 \div [5 + 1 \div 2 - {4 + (4 of 2 \div 4) + (4 \div 4 of 2)}]

is:

- 7 \div [5 + 1 \div 2 - {4 + (4 of 2 \div 4) + (4 \div 4 of 2)}]

का मान है:

A $- \frac{7}{2}$
B $- 7$
C $\frac{7}{2}$
D $7$

Show answer

Concept: Solve innermost brackets first; “of” before ÷.

$(4 of 2 \div 4) = 8 \div 4 = 2$ ; $(4 \div 4 of 2) = 4 \div 8 = \frac{1}{2}$ .
${4 + 2 + \frac{1}{2}} = \frac{13}{2}$ ; $5 + 1 \div 2 = \frac{11}{2}$ .
Bracket $= \frac{11}{2} - \frac{13}{2} = - 1$ ; $- 7 \div (- 1) = 7$ .

Trick: Negative ÷ negative is positive – that rules out options (A) and (B).

Answer: (D) $7$

अवधारणा: सबसे भीतर का कोष्ठक पहले; “of” भाग से पहले।

$(4 of 2 \div 4) = 2$ ; $(4 \div 4 of 2) = \frac{1}{2}$ ।
${\dots} = \frac{13}{2}$ ; $5 + 1 \div 2 = \frac{11}{2}$ ।
कोष्ठक $= - 1$ ; $- 7 \div (- 1) = 7$ ।

ट्रिक: ऋण ÷ ऋण = धन।

उत्तर: (D) $7$

SSC CPO Paper IQuantitative AptitudeSimplification – BODMASSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5943.

A boy increases his speed to

\frac{9}{5}

times of his original speed. By doing this, he reaches his school 40 minutes before the usual time. How much time (in minutes) does he take usually?

एक लड़का अपनी चाल को अपनी मूल चाल का

\frac{9}{5}

गुना कर देता है। ऐसा करके, वह अपने स्कूल सामान्य समय से 40 मिनट पहले पहुँच जाता है। उसे सामान्यतः कितना समय (मिनट में) लगता है?

A120
B30
C90
D45

Show answer

Concept: For a fixed distance, time $\propto \frac{1}{speed}$ .

Speed ratio $5 : 9$ ⇒ time ratio $9 : 5$ .
Saving $= 4$ parts $= 40$ min ⇒ 1 part $= 10$ min.
Usual time $= 9 \times 10 = 90$ min.

Trick: Usual time $= \frac{saving}{1 - \frac{5}{9}} = \frac{40}{4 / 9} = 90$ .

Answer: (C) $90$

अवधारणा: निश्चित दूरी पर समय $\propto \frac{1}{चाल}$ ।

चाल अनुपात $5 : 9$ ⇒ समय अनुपात $9 : 5$ ।
बचत $= 4$ भाग $= 40$ मिनट ⇒ 1 भाग $= 10$ मिनट।
सामान्य समय $= 90$ मिनट।

ट्रिक: सामान्य समय $= \frac{40}{4 / 9} = 90$ ।

उत्तर: (C) $90$

SSC CPO Paper IQuantitative AptitudeSpeed, Time and DistanceSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5944.

The perimeter of a right triangle is 60 cm and its hypotenuse is 26 cm. What is the area (in cm²) of the triangle?

एक समकोण त्रिभुज का परिमाप 60 cm है और इसका कर्ण 26 cm है। त्रिभुज का क्षेत्रफल (cm² में) क्या है?

A60
B96
C90
D120

Show answer

Concept: Use $(a + b)^{2} = a^{2} + b^{2} + 2 a b$ with $a^{2} + b^{2} = 26^{2}$ .

$a + b = 60 - 26 = 34$ .
$2 a b = 34^{2} - 26^{2} = 1156 - 676 = 480 \Rightarrow a b = 240$ .
Area $= \frac{1}{2} a b = 120 {cm}^{2}$ .

Trick: Triplet 10-24-26 (= 2 × 5-12-13): area $= \frac{1}{2} \times 10 \times 24 = 120$ .

Answer: (D) $120$

अवधारणा: $(a + b)^{2} = a^{2} + b^{2} + 2 a b$ और $a^{2} + b^{2} = 26^{2}$ का प्रयोग।

$a + b = 34$ ।
$2 a b = 1156 - 676 = 480 \Rightarrow a b = 240$ ।
क्षेत्रफल $= \frac{1}{2} a b = 120 {cm}^{2}$ ।

ट्रिक: त्रिक 10-24-26: $\frac{1}{2} \times 10 \times 24 = 120$ ।

उत्तर: (D) $120$

SSC CPO Paper IQuantitative AptitudeRight Triangle – AreaSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5945.

Study the given histogram that shows the marks obtained by students in an examination and answer the question that follows (class frequencies read from the histogram are given below).

Marks	150–200	200–250	250–300	300–350	350–400	400–450
Number of students	30	45	60	35	40	35

The number of students who obtained less than 350 marks is what per cent more than the number of students who obtained 400 or more marks?
(correct to one decimal place)

दिए गए आयतचित्र (histogram) का अध्ययन कीजिए, जो एक परीक्षा में विद्यार्थियों द्वारा प्राप्त अंकों को दर्शाता है, और उसके बाद पूछे गए प्रश्न का उत्तर दीजिए (आयतचित्र से पढ़ी गई वर्ग बारंबारताएँ नीचे दी गई हैं)।

अंक	150–200	200–250	250–300	300–350	350–400	400–450
विद्यार्थियों की संख्या	30	45	60	35	40	35

350 से कम अंक प्राप्त करने वाले विद्यार्थियों की संख्या, 400 या अधिक अंक प्राप्त करने वाले विद्यार्थियों की संख्या से कितने प्रतिशत अधिक है?
(एक दशमलव स्थान तक सही)

A350%
B100%
C385.7%
D375.8%

Show answer

Concept: % more $= \frac{difference}{base} \times 100$ , base = students with 400 or more.

Less than 350: $30 + 45 + 60 + 35 = 170$ .
400 or more: $35$ .
More by $\frac{170 - 35}{35} \times 100 = \frac{135}{35} \times 100 \approx 385.7 %$ .

Trick: $\frac{170}{35} = 4.857$ times → $385.7 %$ more (subtract 100%).

Answer: (C) 385.7%

अवधारणा: % अधिक $= \frac{अंतर}{आधार} \times 100$ , आधार = 400 या अधिक वाले।

350 से कम: $170$ ।
400 या अधिक: $35$ ।
अधिक $= \frac{135}{35} \times 100 \approx 385.7 %$ ।

ट्रिक: $\frac{170}{35} = 4.857$ गुना → $385.7 %$ अधिक।

उत्तर: (C) 385.7%

SSC CPO Paper IQuantitative AptitudeData Interpretation – HistogramSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5946.

△ A B C

, D is the median from A to BC. AB = 6 cm, AC = 8 cm, and BC = 10 cm. The length of median AD (in cm) is:

△ A B C

में, D, A से BC पर माध्यिका है। AB = 6 cm, AC = 8 cm और BC = 10 cm है। माध्यिका AD की लंबाई (cm में) है:

A4.5
B5
C4
D3

Show answer

Concept: $6^{2} + 8^{2} = 10^{2}$ , so $∠ A = 90^{\circ}$ ; the median to the hypotenuse equals half the hypotenuse.

$36 + 64 = 100$ ⇒ right angle at A, BC is the hypotenuse.
$A D = \frac{B C}{2} = 5$ cm.

Trick: Apollonius check: $A D^{2} = \frac{2 (36 + 64) - 100}{4} = 25$ .

Answer: (B) $5$

अवधारणा: $6^{2} + 8^{2} = 10^{2}$ , अतः $∠ A = 90^{\circ}$ ; कर्ण पर माध्यिका = कर्ण का आधा।

$36 + 64 = 100$ ⇒ A पर समकोण।
$A D = \frac{B C}{2} = 5$ cm।

ट्रिक: अपोलोनियस जाँच: $A D^{2} = \frac{200 - 100}{4} = 25$ ।

उत्तर: (B) $5$

SSC CPO Paper IQuantitative AptitudeTriangle – MedianSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5947.

The HCF of two numbers is 29, and the other two factors of their LCM are 15 and 13. The larger of the two numbers is:

दो संख्याओं का HCF 29 है, और उनके LCM के अन्य दो गुणनखंड 15 और 13 हैं। दोनों में से बड़ी संख्या है:

A435
B377
C406
D464

Show answer

Concept: Numbers $= HCF \times$ each co-prime factor.

Numbers $= 29 \times 13 = 377$ and $29 \times 15 = 435$ .
Larger $= 435$ .

Trick: Larger number = HCF × larger factor.

Answer: (A) $435$

अवधारणा: संख्याएँ $= HCF \times$ सहअभाज्य गुणनखंड।

$29 \times 13 = 377$ और $29 \times 15 = 435$ ।
बड़ी संख्या $= 435$ ।

ट्रिक: बड़ी संख्या = HCF × बड़ा गुणनखंड।

उत्तर: (A) $435$

SSC CPO Paper IQuantitative AptitudeHCF and LCMSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5948.

A 64 cm wide path is made around a circular garden having a diameter of 10 metres. The area (in m²) of the path is closest to:
(Take

π = \frac{22}{7}

)

10 मीटर व्यास वाले एक वृत्ताकार बगीचे के चारों ओर 64 cm चौड़ा एक पथ बनाया गया है। पथ का क्षेत्रफल (m² में) निकटतम है:
(

π = \frac{22}{7}

लीजिए)

Show answer

Concept: Area of a path around a circle $= π (R^{2} - r^{2}) = π (R + r) (R - r)$ , where $R = r + width$ .

$r = \frac{10}{2} = 5 m$ , width $= 64 cm = 0.64 m$ , so $R = 5.64 m$ .
Area $= \frac{22}{7} \times (5.64 + 5) \times (5.64 - 5) = \frac{22}{7} \times 10.64 \times 0.64$ .
$= \frac{22}{7} \times 6.8096 \approx 21.4 m^{2}$ .
None of the options 10, 11, 15, 9 is close to $21.4$ . (A value near 10 would need a path only $32 cm$ wide: $\frac{22}{7} \times 10.32 \times 0.32 \approx 10.4$ .)

Trick: Use $(R + r) (R - r)$ instead of squaring decimals: $10.64 \times 0.64 \approx 6.81$ , then $\times \frac{22}{7} \approx 21.4$ .

Answer: The area of the path as printed is about $21.4 m^{2}$ , so no option fits; this question was treated as a bonus question.

अवधारणा: वृत्त के चारों ओर पथ का क्षेत्रफल $= π (R^{2} - r^{2}) = π (R + r) (R - r)$ , जहाँ $R = r + चौड़ाई$ ।

$r = \frac{10}{2} = 5 m$ , चौड़ाई $= 64 cm = 0.64 m$ , अतः $R = 5.64 m$ ।
क्षेत्रफल $= \frac{22}{7} \times (5.64 + 5) \times (5.64 - 5) = \frac{22}{7} \times 10.64 \times 0.64$ ।
$= \frac{22}{7} \times 6.8096 \approx 21.4 m^{2}$ ।
विकल्प 10, 11, 15, 9 में से कोई भी $21.4$ के निकट नहीं है। (लगभग 10 का मान तभी आता जब पथ केवल $32 cm$ चौड़ा होता: $\frac{22}{7} \times 10.32 \times 0.32 \approx 10.4$ ।)

ट्रिक: दशमलव का वर्ग करने के बजाय $(R + r) (R - r)$ लें: $10.64 \times 0.64 \approx 6.81$ , फिर $\times \frac{22}{7} \approx 21.4$ ।

उत्तर: छपे हुए प्रश्न के अनुसार पथ का क्षेत्रफल लगभग $21.4 m^{2}$ है, अतः कोई भी विकल्प सही नहीं बैठता; इस प्रश्न को बोनस प्रश्न माना गया।

SSC CPO Paper IQuantitative AptitudeMensuration – Circular PathSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5949.

When a number is successively divided by 3, 4 and 7, the remainders obtained are 2, 3 and 5, respectively. What will be the remainder when 84 divides the same number?

जब किसी संख्या को क्रमिक रूप से 3, 4 और 7 से विभाजित किया जाता है, तो प्राप्त शेषफल क्रमशः 2, 3 और 5 हैं। उसी संख्या को 84 से विभाजित करने पर शेषफल क्या होगा?

Show answer

Concept: Build the number backwards from the last quotient $k$ .

Last step: $7 k + 5$ ; previous: $4 (7 k + 5) + 3 = 28 k + 23$ .
Number $= 3 (28 k + 23) + 2 = 84 k + 71$ .
Divided by $84$ ( $= 3 \times 4 \times 7$ ) → remainder $71$ .

Trick: Remainder $= r_{1} + d_{1} r_{2} + d_{1} d_{2} r_{3} = 2 + 3 \times 3 + 12 \times 5 = 71$ .

Answer: (A) $71$

अवधारणा: अंतिम भागफल $k$ से पीछे की ओर संख्या बनाएँ।

अंतिम चरण: $7 k + 5$ ; पिछला: $28 k + 23$ ।
संख्या $= 84 k + 71$ ।
84 से भाग → शेष $71$ ।

ट्रिक: शेष $= 2 + 3 \times 3 + 12 \times 5 = 71$ ।

उत्तर: (A) $71$

SSC CPO Paper IQuantitative AptitudeNumber System – Successive DivisionSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5950.

Let A and B be two towers with same base. From the midpoint of the line joining their feet, the angles of elevation of the tops of A and B are 30° and 60°, respectively. The ratio of the heights of B and A is:

मान लीजिए A और B समान आधार पर स्थित दो मीनारें हैं। उनके पादों को मिलाने वाली रेखा के मध्य-बिंदु से A और B के शिखरों के उन्नयन कोण क्रमशः 30° और 60° हैं। B और A की ऊँचाइयों का अनुपात है:

A1 : 3
B3 : 1
C1 : 2
D $1 : \sqrt{3}$

Show answer

Concept: From the midpoint M both feet are at the same distance $d$ , so height $= d \tan θ$ .

$h_{A} = d \tan 30^{\circ} = \frac{d}{\sqrt{3}}$ ; $h_{B} = d \tan 60^{\circ} = \sqrt{3} d$ .
$\frac{h_{B}}{h_{A}} = \frac{\sqrt{3}}{1 / \sqrt{3}} = 3$ → $3 : 1$ .

Trick: $\frac{\tan 60^{\circ}}{\tan 30^{\circ}} = 3$ always.

Answer: (B) 3 : 1

अवधारणा: मध्य बिंदु M से दोनों मीनारों के पाद की दूरी $d$ समान, अतः ऊँचाई $= d \tan θ$ ।

$h_{A} = \frac{d}{\sqrt{3}}$ ; $h_{B} = \sqrt{3} d$ ।
$\frac{h_{B}}{h_{A}} = 3$ → $3 : 1$ ।

ट्रिक: $\frac{\tan 60^{\circ}}{\tan 30^{\circ}} = 3$ हमेशा।

उत्तर: (B) 3 : 1

SSC CPO Paper IQuantitative AptitudeHeights and DistancesSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5951.

Select the most appropriate option to substitute the underlined segment in the given
sentence. If there is no need to substitute it, select ‘No substitution required’.
She is being waited for you for two hours.

Ahad wait
Bhas been waiting
CNo substitution required
Dhave been waited

Show answer

Concept: An action that started in the past and is still continuing, with a period of time (for two hours), takes the Present Perfect Continuous: has/have + been + V-ing.

Subject She is singular → has been.
She is the one who is waiting (active), so the verb must be waiting, not passive being waited.
Correct: She has been waiting for you for two hours.
had wait is a wrong form; have been waited is passive and plural.

Trick: for + period / since + point of time with an ongoing action → has/have been + V-ing.

Answer: (B) has been waiting

अवधारणा: जो काम past में शुरू होकर अभी भी चल रहा है और साथ में समय-अवधि (for two hours) दी हो, वहाँ Present Perfect Continuous लगता है: has/have + been + V-ing.

Subject She singular है → has been.
इंतज़ार She स्वयं कर रही है (active), इसलिए waiting चाहिए, passive being waited नहीं।
सही वाक्य: She has been waiting for you for two hours.
had wait गलत रूप है; have been waited passive और plural है।

ट्रिक: for + अवधि / since + समय-बिंदु और काम जारी हो → has/have been + V-ing.

उत्तर: (B) has been waiting

SSC CPO Paper IEnglish ComprehensionSentence Improvement – TenseSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5952.

Select the most appropriate ANTONYM of the given word.
SUAVE

Abrisk
Brude
Ccharming
Dpolite

Show answer

Concept: Suave means smooth, polished and charming in manner (especially a man).

Opposite of polished, gracious behaviour = rude (impolite, ill-mannered).
charming and polite are close to synonyms of suave.
brisk means quick and active – unrelated.

Yaad rakhein: Suave ≈ sophisticated, urbane; its antonyms: rude, crude, boorish.

Answer: (B) rude

अवधारणा: Suave का अर्थ है – शिष्ट, सौम्य और आकर्षक व्यवहार वाला।

शिष्ट व्यवहार का विलोम = rude (असभ्य, अशिष्ट)।
charming (आकर्षक) और polite (विनम्र) तो suave के पर्यायवाची जैसे हैं।
brisk = तेज़/फुर्तीला – संबंध नहीं।

याद रखें: Suave ≈ sophisticated, urbane; विलोम: rude, crude, boorish.

उत्तर: (B) rude

SSC CPO Paper IEnglish ComprehensionAntonymsSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5953.

Select the most appropriate synonym of the given word.
COVETED

Adesired
Bdespised
Ccovered
Drenounced

Show answer

Concept: Coveted means greatly wanted or longed for (e.g. a coveted award).

Closest meaning = desired.
despised (hated) and renounced (given up) are opposite in sense.
covered is only a look-alike word (trap).

Trick: Covet = to desire strongly what someone else has – so coveted = much desired.

Answer: (A) desired

अवधारणा: Coveted का अर्थ है – जिसे पाने की बहुत इच्छा हो, लालायित (जैसे a coveted award)।

सबसे निकट अर्थ = desired (वांछित)।
despised (घृणित) और renounced (त्यागा हुआ) उल्टे अर्थ वाले हैं।
covered केवल मिलता-जुलता दिखने वाला शब्द है (जाल)।

ट्रिक: Covet = किसी चीज़ की तीव्र लालसा करना – इसलिए coveted = बहुत चाहा गया।

उत्तर: (A) desired

SSC CPO Paper IEnglish ComprehensionSynonymsSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5954.

Select the most appropriate option to substitute the underlined segment in the given
sentence. If there is no need to substitute it, select ‘No substitution required’.
The train was delayed in order to an accident.

Asince
Bowing to
CNo substitution required
Dbecause

Show answer

Concept: Before a noun (an accident) we need a prepositional phrase of cause such as owing to / due to / because of. In order to shows purpose and takes a verb.

an accident is a noun phrase, not a clause.
since and because are conjunctions – they need a full clause (subject + verb) after them.
So only owing to fits: The train was delayed owing to an accident.

Trick: Cause + noun → owing to / because of; cause + clause → because / since; purpose + verb → in order to.

Answer: (B) owing to

अवधारणा: noun (an accident) से पहले कारण बताने के लिए owing to / due to / because of लगता है। In order to उद्देश्य बताता है और उसके बाद verb आती है।

an accident noun phrase है, clause नहीं।
since और because conjunctions हैं – इनके बाद पूरा clause (subject + verb) चाहिए।
इसलिए केवल owing to सही: The train was delayed owing to an accident.

ट्रिक: कारण + noun → owing to / because of; कारण + clause → because / since; उद्देश्य + verb → in order to.

उत्तर: (B) owing to

SSC CPO Paper IEnglish ComprehensionSentence Improvement – Prepositional phraseSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5955.

Select the most appropriate meaning of the given idiom.
Bear the brunt of

Abreed jealousy
Bassume an identity
Cbear discrimination
Dbear the maximum fury

Show answer

Concept: Bear the brunt of = to receive the worst or main part of an attack, anger or difficulty.

Brunt = the chief force or shock of something unpleasant.
Example: The coastal villages bore the brunt of the cyclone.
So the meaning is ‘bear the maximum fury’; the other options do not match.

Yaad rakhein: Brunt = main impact; bear the brunt = suffer the heaviest blow.

Answer: (D) bear the maximum fury

अवधारणा: Bear the brunt of = किसी हमले, गुस्से या कठिनाई का सबसे बड़ा/मुख्य प्रहार झेलना।

Brunt = किसी अप्रिय चीज़ का मुख्य ज़ोर/आघात।
उदाहरण: The coastal villages bore the brunt of the cyclone.
अर्थ है ‘सबसे अधिक प्रकोप सहना’ – बाकी विकल्प मेल नहीं खाते।

याद रखें: Brunt = मुख्य आघात; bear the brunt = सबसे भारी चोट सहना।

उत्तर: (D) bear the maximum fury

SSC CPO Paper IEnglish ComprehensionIdioms and PhrasesSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5956.

Identify the segment in the sentence which contains a grammatical error.
The two trains gave the illusion of been stationary.

AThe two
Bof been stationary
Cthe illusion
Dtrains gave

Show answer

Concept: After a preposition (of) a verb takes the -ing (gerund) form. Been is a past participle and cannot follow of directly.

of been stationary ✗ → of being stationary ✓.
Correct: The two trains gave the illusion of being stationary.
Other segments are correct.

Trick: Preposition + verb → always V-ing (of being, without going, before leaving).

Answer: (B) of been stationary

अवधारणा: Preposition (of) के बाद verb का -ing (gerund) रूप आता है। Been past participle है, यह सीधे of के बाद नहीं आ सकता।

of been stationary ✗ → of being stationary ✓।
सही वाक्य: The two trains gave the illusion of being stationary.
बाकी भाग सही हैं।

ट्रिक: Preposition + verb → हमेशा V-ing (of being, without going, before leaving)।

उत्तर: (B) of been stationary

SSC CPO Paper IEnglish ComprehensionSpot the Error – GerundSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5957.

Select the most appropriate synonym of the given word.
SHOVE

Ashout
Bpoke
Cpull
Dhalt

Show answer

Concept: Shove means to push roughly or suddenly.

Among the options, the closest is poke (to push/prod sharply).
pull is the opposite direction of force; halt = stop; shout = cry loudly.

Yaad rakhein: Shove ≈ push, thrust, jostle, poke.

Answer: (B) poke

अवधारणा: Shove का अर्थ है – ज़ोर से या अचानक धक्का देना।

विकल्पों में सबसे निकट poke (कोंचना/धक्का देना) है।
pull = खींचना (उल्टा), halt = रुकना, shout = चिल्लाना।

याद रखें: Shove ≈ push, thrust, jostle, poke.

उत्तर: (B) poke

SSC CPO Paper IEnglish ComprehensionSynonymsSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5958.

Select the most appropriate synonym of the given word.
LOFTY

Ahumble
Bsilent
Cplain
Dtowering

Show answer

Concept: Lofty means very tall / of great height (also: noble, elevated).

Closest meaning = towering (very high).
humble and plain are nearly opposite; silent is unrelated.

Trick: Loft = upper storey → lofty = high up.

Answer: (D) towering

अवधारणा: Lofty का अर्थ है – बहुत ऊँचा (उदात्त/उच्च भी)।

सबसे निकट अर्थ = towering (गगनचुंबी, बहुत ऊँचा)।
humble (विनम्र) और plain (साधारण) लगभग विलोम हैं; silent असंबद्ध है।

ट्रिक: Loft = ऊपरी मंज़िल → lofty = ऊँचा।

उत्तर: (D) towering

SSC CPO Paper IEnglish ComprehensionSynonymsSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5959.

Select the most appropriate meaning of the given idiom.
The sword of Damocles

Aa rare artifact
Ban authentic sword
Can impending threat
Da poignant weapon

Show answer

Concept: The sword of Damocles = a danger that may strike at any moment; an impending threat.

From a Greek tale: Damocles sat on a throne with a sword hanging above him by a single hair.
It shows that power and good fortune carry constant danger.
So it means ‘an impending threat’, not a real or rare sword.

Yaad rakhein: Sword hanging by a hair over the head = ever-present danger.

Answer: (C) an impending threat

अवधारणा: The sword of Damocles = सिर पर लटकता खतरा; कभी भी आ सकने वाला संकट।

यूनानी कथा: Damocles सिंहासन पर बैठा था और उसके ऊपर एक बाल से तलवार लटक रही थी।
अर्थ – सत्ता और सौभाग्य के साथ हमेशा खतरा रहता है।
इसलिए अर्थ ‘an impending threat’ है, कोई असली तलवार नहीं।

याद रखें: सिर पर बाल से लटकी तलवार = हमेशा मौजूद खतरा।

उत्तर: (C) an impending threat

SSC CPO Paper IEnglish ComprehensionIdioms and PhrasesSSC CPO Paper I 2020 · 24 Nov Shift 3

Q5960.

Select the most appropriate one-word substitution for the given group of words.
A person of evil reputation

Aicon
Bnotorious
Cfamous
Drenowned

Show answer

Concept: A person or thing well known for something bad is notorious.

famous and renowned mean well known for good reasons.
icon = a person admired as a symbol.
Evil reputation → notorious (e.g. a notorious criminal).

Trick: Famous = good fame; notorious = bad fame (infamous).

Answer: (B) notorious

अवधारणा: जो व्यक्ति/वस्तु किसी बुरी बात के लिए प्रसिद्ध हो, वह notorious (कुख्यात) कहलाता है।

famous और renowned = अच्छी वजह से प्रसिद्ध।
icon = प्रतीक के रूप में सराहा जाने वाला व्यक्ति।
बुरी प्रतिष्ठा → notorious (जैसे a notorious criminal)।

ट्रिक: Famous = सुख्यात; notorious = कुख्यात (infamous)।

उत्तर: (B) notorious

SSC CPO Paper IEnglish ComprehensionOne Word SubstitutionSSC CPO Paper I 2020 · 24 Nov Shift 3