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RRB NTPC Graduate CBT 1 2024 · Shift 3

RRB NTPC Graduate CBT 1 17 Jun 2025 Shift 3 – Question Paper

99 questions · 99 marks · 90 minutes · +1 for a correct answer, −1/3 for a wrong one. With answer key and detailed solutions in Hindi and English.

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Paper pattern

SectionQuestionsMarks
General Awareness4040
Mathematics2929
General Intelligence and Reasoning3030

Sample questions from this paper

Q1.
Who among the following has been appointed as 26th Chief Election Commissioner of India in February 2025?
फ़रवरी 2025 में निम्नलिखित में से किसे भारत के 26वें मुख्य चुनाव आयुक्त के रूप में नियुक्त किया गया है?
  1. ASanjay Malhotra
  2. BAshish Naithani
  3. CVineet Joshi
  4. DGyanesh Kumar
Show answer

Concept: The Chief Election Commissioner (CEC) heads the Election Commission of India (Article 324).

  1. Gyanesh Kumar took charge as the 26th CEC on 19 February 2025, succeeding Rajiv Kumar.
  2. He is the first CEC appointed under the CEC and Other ECs Act, 2023 (selection committee led by the PM).
  3. Sanjay Malhotra is the RBI Governor – a tempting but wrong option.

Yaad rakhein: 26th CEC – Gyanesh Kumar; 25th CEC – Rajiv Kumar.

Answer: (D) Gyanesh Kumar

अवधारणा: मुख्य चुनाव आयुक्त (CEC) भारत निर्वाचन आयोग का प्रमुख होता है (अनुच्छेद 324)।

  1. ज्ञानेश कुमार ने 19 फ़रवरी 2025 को राजीव कुमार के बाद 26वें CEC का पद संभाला।
  2. वे CEC एवं अन्य EC अधिनियम, 2023 के तहत नियुक्त पहले CEC हैं।
  3. संजय मल्होत्रा RBI गवर्नर हैं – यह विकल्प गलत है।

याद रखें: 26वें CEC – ज्ञानेश कुमार; 25वें – राजीव कुमार।

उत्तर: (D) ज्ञानेश कुमार

RRB NTPC Graduate CBT 1General AwarenessCurrent Affairs – Appointments
Q41.
A sum when invested at the rate of 12.5% simple interest per annum, amounts to ₹7,500 after 2 years. The simple interest (in ₹) for the given time period is:
एक धनराशि को 12.5% वार्षिक साधारण ब्याज की दर पर निवेश करने पर 2 वर्ष बाद वह ₹7,500 हो जाती है। दी गई समयावधि के लिए साधारण ब्याज (₹ में) है:
  1. A1,500
  2. B1,600
  3. C1,700
  4. D1,400
Show answer

Concept: SI=P×R×T100 and A=P+SI.

  1. SI for 2 years at 12.5% = 25% of P=P4.
  2. A=P+P4=5P4=7500⇒P=6000
  3. SI=7500−6000=1500

Trick: 12.5%=18; 2 years → 14 of P. So A = 5 parts = 7500, SI = 1 part = 1500.

Answer: (A) ₹1500

अवधारणा: SI=P×R×T100 तथा A=P+SI।

  1. 2 वर्ष में 12.5% की दर से SI = P का 25% = P4।
  2. A=5P4=7500⇒P=6000
  3. SI=7500−6000=1500

ट्रिक: 12.5%=18; 2 वर्ष → 14; मिश्रधन 5 भाग = 7500, SI = 1 भाग = 1500।

उत्तर: (A) ₹1500

RRB NTPC Graduate CBT 1MathematicsSimple Interest
Q70.
What will come in the place of the question mark (?) in the following equation, if ‘+’ is replaced by ‘−’ and ‘×’ and ‘÷’ are interchanged?
20 ÷ 5 + 8 × 2 + 1 = ?
यदि ‘+’ को ‘−’ से प्रतिस्थापित कर दिया जाए और ‘×’ तथा ‘÷’ को आपस में बदल दिया जाए, तो निम्नलिखित समीकरण में प्रश्न चिह्न (?) के स्थान पर क्या आएगा?
20 ÷ 5 + 8 × 2 + 1 = ?
  1. A95
  2. B85
  3. C80
  4. D90
Show answer

Concept: After changing signs, solve using BODMAS.

  1. Replace: ‘+’ → ‘−’, ‘×’ ↔ ‘÷’.
  2. New expression: 20×5−8÷2−1
  3. =100−4−1=95

Trick: Rewrite the whole expression first, then apply BODMAS – never solve while changing signs.

Answer: (A) 95

अवधारणा: चिह्न बदलकर BODMAS से हल करें।

  1. ‘+’ → ‘−’ तथा ‘×’ ↔ ‘÷’ करें।
  2. नया व्यंजक: 20×5−8÷2−1
  3. =100−4−1=95

ट्रिक: पहले पूरा व्यंजक दोबारा लिखें, फिर BODMAS लगाएँ।

उत्तर: (A) 95

RRB NTPC Graduate CBT 1General Intelligence and ReasoningMathematical Operations

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