Q&A: practice questions with answers

Concept: Grope = search blindly with the hands.

1. In darkness she searched the bag by touch → groped.
2. Fumbled = searched clumsily with the hands → fits.
3. Threw, Observed (needs light), Arranged don't fit the sense.

Trick: 'In the darkness' rules out any seeing-word – think of hand actions only.

Answer: (B) Fumbled

Concept: List the real senses of 'content' and remove the odd one.

1. CONtent (noun) = subject matter of a book/programme.
2. conTENT (adj.) = satisfied, happy.
3. content (noun) = amount of a substance, e.g. fat content.
4. A vessel for liquids = container, a different word.

Trick: Don't be fooled by look-alike words: content ≠ container.

Answer: (D) A vessel or container used for holding liquids

Concept: Break a medical word into its parts: hemo + globin + o + pathy.

1. hemo (blood) + globin = hemoglobin.
2. Linking vowel 'o' + pathy (disease) → hemoglobinopathy.
3. (A) 'hema-', (B) '-apathy', (C) '-pathi' are wrong.

Trick: Disease words end in -opathy: neuropathy, myopathy, homeopathy.

Answer: (D) hemoglobinopathy

Concept: Root 'stratum' (layer) takes the combining form strati-, plus '-graphic'.

1. strati + graphic = stratigraphic (study of layers).
2. (A) strato-, (C) strate- use the wrong vowel.
3. (D) replaces 'ph' with 'f' and 'c' with 'k'.

Trick: Same root as 'stratification' – both carry 'strati'.

Answer: (B) stratigraphic

Concept: Check each part; the error is in the word derived from 'history'.

1. Part (2) 'histriography' drops the 'o' of histor-.
2. Correct: historiography (history + -ography).
3. thesis, clarity, insight, analytical approach are correct.

Trick: Keep the root intact: histor-y → histor-ical → histor-iography.

Answer: (C) (2)

Concept: Replace each symbol by its real sign, then apply BODMAS (÷ before −).

1. '!' = ÷ and '*' = − → $24÷9-4-6$.
2. $24÷9=\frac{8}{3}$.
3. $\frac{8}{3}-10=\frac{8-30}{3}=-\frac{22}{3}$.

Trick: Combine all subtractions first ($4+6=10$), then one step: $\frac{8}{3}-10$.

Answer: (A) $\frac{-22}{3}$

Concept: Equal and opposite moves cancel; only the leftover move decides the direction.

1. 5 km South and 5 km North cancel each other.
2. Only 7 km West remains.
3. So he is 7 km West of the start.

Trick: Net N–S = 5 − 5 = 0, net E–W = 7 W → pure West.

Answer: (D) West

Concept: Unfold step by step: each fold doubles every punch as a mirror image across the fold line.

1. Two folds (right→left, bottom→top) leave one quarter of the sheet.
2. Each cut on that quarter appears 4 times on opening – mirrored across the vertical and horizontal fold lines.
3. So the open sheet must show 4 of each shape placed symmetrically – this matches option (A).

Trick: Count first: 2 folds → every punch × 4. Reject any option where a shape appears fewer/more times or isn't mirror-symmetric.

Answer: (A) Figure (A)

Concept: Differences rise steadily (or the terms are 3 × perfect squares).

1. Differences: 15, 21, 27 → each +6.
2. Next difference = 33 → $75+33=108$.
3. Check: $3\times 2^2,3\times 3^2,3\times 4^2,3\times 5^2$, $3\times 6^2=108$.

Trick: All terms divisible by 3: 4, 9, 16, 25 → squares! Next $36\times 3=108$.

Answer: (B) 108

Concept: Fix the definite clues first (oldest, leap year), then fill the rest.

1. Years: 2002–2006. Rahul (oldest) = 2002.
2. Only leap year here is 2004 → Ramesh.
3. Reena can't be 2003/2006 → 2005.
4. Rohan & Ritu share 2003/2006; Ritu younger → Ritu 2006, Rohan 2003.

Trick: Leap year = divisible by 4 → in 2002–06 only 2004; that one clue locks Ramesh instantly.

Answer: (A) Rohan

Concept: Compare symbol by symbol – dots, hyphens and spaces count.

1. (A) 'M.G. Road' has extra dots (master: MG Road).
2. (B) 'H.No.21' uses a dot instead of a hyphen.
3. (C) 'Sector B 4' has a space instead of a hyphen.
4. (D) matches exactly.

Trick: Check the punctuation-heavy parts first (H.No-21, B-4, MG) – differences hide there.

Answer: (D) H.No-21, Sector B-4, Green Valley, MG Road, Jaipur - 302015

Concept: Second differences are constant.

1. Differences: 12, 18, 24, 30 (each +6).
2. Next difference = 36.
3. $90+36=126$.

Trick: Divide by 6: 1, 3, 6, 10, 15 → triangular numbers; next $21\times 6=126$.

Answer: (A) 126

Concept: In each row the last number = product of the first three.

1. Row 1: $4\times 6\times 5=120$ ✓
2. Row 2: $3\times 5\times 6=90$ ✓
3. Row 3: $5\times 8\times ?=200\to 40\times ?=200\to ?=5$.

Trick: When the last number is large compared to the others, test multiplication first.

Answer: (C) 5

Concept: Find one rule that links the four numbers in every box.

1. Multiply the two upper numbers and add the lower-right one; the result is the lower-left number.
2. 1st box: $20+9=29$ ✓   2nd box: $35+5=40$ ✓
3. 3rd box: $18+?=25\to ?=7$.

Trick: Verify any rule on two boxes before applying it to the third.

Answer: (A) 7

Concept: Count single regions first, then combinations of 2, 3… regions.

1. Single small triangles: 6.
2. Triangles made of two parts: 3.
3. One large triangle formed by the top edge, the long slant line and the vertical line: 1.
4. Total = 6 + 3 + 1 = 10.

Trick: Label each small region with a number and list combinations – nothing gets double counted.

Answer: (B) 10

Concept: Label the points and count group by group (top part, middle crossing lines, base part, side flaps).

1. Top small section near apex: 3.
2. Whole figure and its two halves split by the central line: 3.
3. Triangles from the two long crossing lines: 10.
4. Lower part (inner line + base): 6; side flaps: 2.
5. Total = 3 + 3 + 10 + 6 + 2 = 24.

Trick: For symmetric figures, count one half carefully, double it, then add triangles that cross the axis.

Answer: (C) 24

Concept: Facing the centre, 'right' = anticlockwise.

1. Anticlockwise: S, _, Q, _, P (Q 2nd right of S, P 2nd right of Q).
2. R can't sit next to P → R between S and Q; T between Q and P.
3. Order (anticlockwise): S, R, Q, T, P → next after P is S.

Trick: With 5 seats, 'second to the right' twice = 4 steps = 1 step left. So P is just left of S, i.e. S is immediately right of P.

Answer: (D) S

Concept: Build the same arrangement; facing the centre, count right = anticlockwise.

1. Q is 2nd right of S, P is 2nd right of Q → S, _, Q, _, P.
2. R not next to P → S, R, Q, T, P (anticlockwise).
3. From R to the right: Q (1), T (2), P (3).

Trick: In 5 seats, 3rd to the right = 2nd to the left: from R going clockwise 2 seats → S, then P.

Answer: (B) P

Concept: Every Right or Left is a 90° turn; only the net turn (Lefts − Rights) matters.

1. North → West needs a net of one Left turn.
2. (B) R, L, R, L, L: 2 Rights, 3 Lefts → net 1 Left → West ✓ (N→E→N→E→N→W).
3. (A), (C) and (D) each have 3 Rights, 2 Lefts → net 1 Right → East.

Trick: Don't trace each turn – just count: net = L − R. Net 1 L = West, net 1 R = East.

Answer: (B) Right, Left, Right, Left, Left

Concept: The square is split by its diagonals into 4 identical triangular parts, each carrying the same design from its edge to the centre.

1. Design in each part (edge → centre): one thick bar, two thin parallel lines, small arcs at the tip.
2. The missing part is the bottom triangle: thick bar along the bottom edge, arcs at the top tip near the centre.
3. Without rotation, only option (C) shows this orientation.

Trick: Read the opposite (top) part and flip it top-to-bottom – that is exactly the missing piece.

Answer: (C) Figure (C)