Q&A: practice questions with answers

Concept: Faces seen together in any view are adjacent, so they can never be opposite.

1. In the first view N appears beside A and T.
2. In the second view N appears beside S and H.
3. So N is adjacent to A, T, S, H — the only face left for N's opposite is I.

Trick: Find the letter common to both views; whichever single letter never appears with it is its opposite.

Answer: (C) N

Concept: Each cluster moves back by 2 letters; first letters of clusters jump back by 10.

1. Inside every term: Z→X→V, P→N→L, F→D→B (−2 each).
2. First letters: Z(26) → P(16) → F(6) → V(22) → ? : each is −10 (6 − 10 = −4 → 26 − 4 = 22).
3. Next first letter = 22 − 10 = 12 = L.
4. L, then −2, −2 → L J H.

Trick: Once the first letter is known, only option (B) has the −2, −2 internal gap starting from L.

Answer: (B) LJH

Concept: When codes are jumbled, letters common to two words share the digits common to their codes.

1. SOUL and LOST share S, O, L; codes 6415 and 6548 share 6, 4, 5.
2. In SOUL the extra letter is U; in 6415 the extra digit is 1.
3. Hence U = 1.

Trick: Strike out common letters and common digits — the leftovers pair up directly.

Answer: (B) 1

Concept: Swap the signs first, then solve using BODMAS.

1. After swapping (× ↔ +, − ↔ ÷): $51-30+36÷6\times 6$
2. Division: $36÷6=6$; multiplication: $6\times 6=36$
3. $51-30+36=57$

Trick: Rewrite the whole expression with new signs before calculating — most errors come from swapping only some signs.

Answer: (B) 57

Concept: Compare the forward gaps between consecutive letters of each cluster.

1. RWD: R→W +5, W→D +7 (wrapping after Z).
2. FKR: +5, +7; DIP: +5, +7.
3. JOD: J→O +5 but O→D is +15 — pattern breaks.

Trick: Write letter positions (J=10, O=15, D=4) and check the second gap; the one that differs is odd.

Answer: (A) JOD

Concept: Two things change in every step — the positions of the letters B, N, K and the direction of the arrow; track them separately.

1. The letters B, N, K shift one corner in a fixed cycle; the 4th figure repeats the 1st, so the 5th repeats the 2nd arrangement (K, B, N).
2. The arrow turns 45° anticlockwise each step: east → north-east → north → north-west → next is west (pointing left).
3. Only option (C) shows K, B, N with a horizontal arrow pointing left.

Trick: When a figure repeats after a fixed number of steps, copy the matching earlier figure for the letters and only work out the arrow.

Answer: (C)

Concept: Fix definite positions first (seat numbers 1–7 from the left, all facing north).

1. Three people left of L → L = seat 4.
2. Only F right of G → G = 6, F = 7.
3. Three between G and K → K = 2.
4. E < N < H in remaining seats 1, 3, 5 → E = 1, N = 3, H = 5.
5. Between E(1) and N(3): only K → one person.

Trick: Persons between = difference of seat numbers − 1 = 3 − 1 − 1 = 1.

Answer: (B) One

Concept: Differences rise by 1 at each step.

1. Differences: +10, +11, +12, +13
2. Next difference = +14
3. 496 + 14 = 510

Trick: Last digits 0, 0, 1, 3, 6 grow by 0, 1, 2, 3 → next grows by 4 → ends in 0; only 510 and 500 qualify, and 500 is too small.

Answer: (C) 510

Concept: A vertical mirror swaps left and right; top and bottom stay unchanged.

1. The ball on top and the stem below lie on the central line — they do not change.
2. The wings differ: hollow on the left, solid on the right in the figure.
3. In the image they swap: solid wing on the left, hollow on the right — this is option (A).
4. (B) is the original figure itself; (C) and (D) make both wings alike.

Trick: Focus only on the one asymmetric part of the figure and flip it sideways.

Answer: (A)

Concept: Chain the 'All' statements and check against the 'No' statement.

1. Beats ⊂ Music ⊂ Rhythms, and Rhythms have nothing common with Tunes.
2. I: Beats are inside Rhythms, so no beat can be a tune — follows.
3. II: All beats are rhythms ⇒ Some rhythms are beats (conversion) — follows.

Trick: 'All A are B' always gives 'Some B are A' — a quick definite conclusion.

Answer: (A) Both conclusions (I) and (II) follow.

Concept: Row 2 faces north (its left = page left); row 1 faces south (its left = page right). Number places 1–4 from page left.

1. S third to the left of R → S = 1, R = 4 in row 2.
2. R's neighbour (place 3) faces M → M = 3 in row 1.
3. L third to the right of N (south-facing) → L = 1, N = 4; so O = 2 (right of M ✓).
4. O not facing P → P = 3, Q = 2 in row 2. Q faces place 2 of row 1 = O.

Trick: For south-facing people, 'right' means towards the page's left — reverse directions once and keep them reversed.

Answer: (C) O

Concept: Find the shift for each letter position and apply it.

1. UMCP → ZOEU: shifts +5, +2, +2, +5 (QBXK → VDZP confirms).
2. Apply to EJAH: E→J (+5), J→L (+2), A→C (+2), H→M (+5).
3. So EJAH → JLCM.

Trick: Check just the first letter: E→J (+5); only option (C) begins with J.

Answer: (C) JLCM

Concept: Every letter moves forward by the same number (+14), wrapping after Z.

1. B(2) → P(16) = +14; Y(25) + 14 = 39 − 26 = 13 = M ✓.
2. N(14) + 14 = 28 → 2 = B; K(11) + 14 = 25 = Y.
3. H(8) + 14 = 22 = V; F(6) + 14 = 20 = T → BYVT.

Trick: +14 is the same as −12; e.g. T − 12 = H, so reverse checks are quick.

Answer: (C) BYVT

Concept: With jumbled codes, match the uncommon letter to the uncommon digit.

1. BASH = 5431, HASE = 1234.
2. Common letters A, S, H ↔ common digits 1, 3, 4.
3. HASE has extra E; 1234 has extra 2 → E = 2.

Trick: Cancel what is common in both words and both codes — the leftovers give the answer instantly.

Answer: (C) 2

Concept: A 7-letter unit 'stolbri' repeats; the full series is that unit three times over.

1. Block 1: s t o l b r i + block 2 starts s t → blanks r, i, s, t.
2. Given o l b r i completes block 2; block 3 begins s t then blanks o, l, b; given r i ends it.
3. Blanks in order: r i s t o l b.

Trick: Spot a repeating word in the series ('stolbri'); fill blanks by copying it.

Answer: (B) ristolb

Concept: Letters seen together are neighbours; the letter never seen with a face is its opposite.

1. A appears in both views: with L, D in one and with Z, I in the other.
2. So A touches L, D, Z, I.
3. The only letter not seen with A is N → N is opposite A.

Trick: Common letter in both views + the one letter missing from its company = opposite pair.

Answer: (C) A

Concept: When simple differences fail, split into odd-place and even-place terms.

1. Odd places: 7, 25, 61 — gaps 18, 36 (doubling).
2. Even places: 17, 53, ? — first gap 36, next gap 72.
3. 53 + 72 = 125.

Trick: Differences 10, 8, 28, 8 alternate oddly → always try alternate terms next.

Answer: (D) 125

Concept: Sort the word's letters alphabetically and compare position-wise.

1. LIGHTER: L I G H T E R
2. Sorted: E G H I L R T
3. No position has the same letter in both rows → zero.

Trick: Check only plausible matches: the first letter must be the smallest (E) and last the largest (T) — L and R fail, and the middle ones all shift.

Answer: (B) Zero

Concept: Decode each symbol pair from left to right.

1. M + N: M is N's brother (M male).
2. N − O: N is O's sister → M, N, O are siblings.
3. O × P: O is P's mother.
4. So M is the brother of P's mother.

Trick: Only the link from M to P matters; ignore 'P ÷ Q'.

Answer: (D) Mother's brother

Concept: Decide pair-wise: subset, overlap or separate.

1. Every sister is a female → Sister inside Female.
2. Some doctors are female, some are not → Doctor partly overlaps Female.
3. A sister can be a doctor → Doctor also cuts the Sister circle.
4. Diagram: small circle in big circle, third circle crossing both.

Trick: Professions (doctor, teacher) usually overlap gender/relation classes.

Answer: (C)