RRB NTPC Graduate CBT 1 2024 PYQs

Concept: Start with the fixed day (S = Wednesday) and chain the 'immediately' clues.

1. S Wed → O Thu → U Fri.
2. T after U and before Q → T Sat, Q Sun.
3. P and R take Mon, Tue with R after P → P Mon, R Tue.
4. Between S (Wed) and Q (Sun): O, U, T → three.

Trick: Chain 'immediately after' clues first – they fix several days at once.

Answer: (D) Three

Concept: Vowel → next letter; consonant → previous letter.

1. BAD → A B C (has A); FIG → E J F (has E)
2. ICE → J B F (no vowel)
3. NOT → M P S (no vowel)
4. Clusters without a vowel: 2

Trick: A new vowel can come only from a consonant just after a vowel (B→A, F→E, J→I, P→O, V→U).

Answer: (A) Two

Concept: Pick the highest and lowest numbers, then the required digits.

1. Highest = 909 → third digit 9.
2. Lowest = 268 → first digit 2.
3. $2-9=-7$

Trick: 'A subtracted from B' means $B-A$.

Answer: (D) $-7$

Concept: Fix F, then T and E from the 'between' clues.

1. F = Fri (5). Two between T and F → T = Tue (2).
2. Four between E and T → E = Sun (7).
3. Free: Mon, Wed, Thu, Sat. U–S consecutive → U Wed, S Thu.
4. D not Monday → D Sat, C Mon. Between C (Mon) and D (Sat): T, U, S, F → four.

Trick: Count positions: 'n people between' means a gap of $n+1$ days.

Answer: (A) Four

Concept: Find the shift for each letter.

1. PIL → TMP: +4, +4, +4; NAP → RET: +4, +4, +4.
2. SWT → WAX: S + 4 = W, W + 4 = A, T + 4 = X ✓
3. NLI → JPM (−4, +4, +4), SPL → WLH (+4, −4, −4), BGM → GKQ (+5, +4, +4) ✗

Trick: Same +4 to every letter; remember W + 4 wraps to A.

Answer: (B) SWT : WAX

Concept: Apply the same change to each letter and to the number.

1. KF 17 → HB 6: K − 3 = H, F − 4 = B, 17 − 11 = 6.
2. KH 12 → HD 1: K − 3 = H, H − 4 = D, 12 − 11 = 1.
3. LP −6 → L − 3 = I, P − 4 = L, $-6-11=-17$ → IL −17.

Trick: Check the number first: only one option gives $-6-11=-17$.

Answer: (C) IL $-17$

Concept: Both sides of :: must follow the same letter shifts.

1. Try # = JPR: J + 2 = L, P + 1 = Q, R + 2 = T → pattern +2, +1, +2.
2. Apply to AJM: A + 2 = C, J + 1 = K, M + 2 = O → % = CKO ✓
3. Other options give different shifts on the two sides.

Trick: Find the rule from one option, then verify it on the other side.

Answer: (D) # = JPR, % = CKO

Concept: Track the net east–west and north–south movement.

1. South 3, left (east) 4, right (south) 4, left (east) 3, left (north) 7.
2. North–south: $-3-4+7=0$ → P is level with A.
3. East: $4+3=7$ km → P is 7 km east of A.
4. To return: 7 km towards West.

Trick: Net south and north cancel → distance is just the total east movement.

Answer: (C) 7 km; West

Concept: Check each condition, then code directly if none applies.

1. (i): first @ is a symbol but last + is also a symbol → not applied.
2. (ii): first is not a number → not applied. (iii): 2 is not a perfect square → not applied.
3. Direct codes: @ = F, 2 = T, 4 = B, 7 = P, + = R.

Trick: Both ends symbols → (i) and (ii) fail at once; only check (iii).

Answer: (D) FTBPR

Concept: Each letter is moved a fixed number of places forward in the alphabet.

1. MILK → TPSR: M(13)→T(20), I(9)→P(16), L(12)→S(19), K(11)→R(18): each $+7$.
2. Check POT → WVA: P→W, O→V, T(20)$+7=27-26=1$→A. ✓
3. NATION: N→U, A→H, T→A, I→P, O→V, N→U = UHAPVU.

Trick: After Z wrap around: subtract 26 when the position crosses 26.

Answer: (A) UHAPVU

Concept: Constant difference series.

1. $62-61.1=0.9$, $61.1-60.2=0.9$, … each term decreases by $0.9$.
2. Next term $=57.5-0.9=56.6$.

Trick: Same decimal steps → simple subtraction series.

Answer: (A) $56.6$

Concept: Find the operation that links each pair.

1. $54\to 59$: $54+5=59$.
2. $30\to 35$: $30+5=35$. ✓
3. So $11\to 11+5=16$.

Trick: Check the simplest difference first; here both pairs differ by $5$.

Answer: (B) $16$

Concept: Replace symbols, then apply BODMAS.

1. Given: $13-780\times 12÷16+32$.
2. Replace ($-\to \times$, $\times \to ÷$, $÷\to +$, $+\to -$): $13\times 780÷12+16-32$.
3. $780÷12=65$; $13\times 65=845$.
4. $845+16-32=829$.

Trick: Do the division first: $780÷12=65$, then the rest is quick.

Answer: (A) $829$

Concept: Check each condition on the group 4 7 3 9, then code the rest from the table.

1. Codes: 4 = H, 7 = J, 3 = K, 9 = N.
2. Condition (i): last element 9 is a number, not a symbol → not applicable.
3. Condition (ii): first 4 is even, last 9 is odd → first and last become '('.
4. Condition (iii): 7 and 3 are not perfect squares → not applicable. Middle stays J, K.
5. Code = ( J K (.

Trick: Test conditions on the first/last elements first — they usually decide the answer quickly.

Answer: (A) (JK(

Concept: Interchange the signs, then apply BODMAS.

1. Given: $54÷11+272\times 8-114$.
2. After swapping ($+\leftrightarrow -$, $\times \leftrightarrow ÷$): $54\times 11-272÷8+114$.
3. $54\times 11=594$; $272÷8=34$.
4. $594-34+114=674$.

Trick: Rewrite the whole expression first, then calculate — avoids sign mistakes.

Answer: (A) $674$

Concept: Each letter of the cluster moves +1.

1. 1st letters: J, K, L, M → N.
2. 2nd letters: G, H, I, J → K.
3. 3rd letters: M, N, O, P → Q.
4. Next term = NKQ.

Trick: Read the series column-wise: three separate +1 sequences.

Answer: (D) NKQ

Concept: Change each digit, then pick positions.

1. Number: 6 4 3 5 1 2 7. Even digits $+2$, odd digits $-1$.
2. New number: 8 6 2 4 0 4 6.
3. 2nd from left $=6$; 3rd from right $=0$ (from right: 6, 4, 0).
4. Sum $=6+0=6$.

Trick: Write the new number fully before counting positions from the right.

Answer: (D) $6$

Concept: 'Electricians who are architects but not dentists' = region in E and A only, outside D.

1. E ∩ A (both) contains $9+2=11$ persons.
2. The $2$ in the centre are also dentists, so exclude them.
3. Required $=9$.

Trick: 'Both but not the third' → the two-circle overlap region only, never the centre.

Answer: (C) $9$

Concept: Decode each symbol and build the family tree.

1. M + N: M is the mother of N. N × O: N is the wife of O.
2. O − P: O is the brother of P. P ÷ Q: P is the father of Q.
3. From Q: father = P → father's brother = O → his wife = N → her mother = M.
4. M is Q's father's brother's wife's mother.

Trick: Start from the person asked about (Q) and walk back along the chain.

Answer: (C) Father's brother's wife's mother

Concept: Track net north–south and east–west displacement (every left turn here is a 90° turn).

1. North 9 → left (west) 7 → left (south) 11 → left (east) 10 → left (north) 2.
2. North–south: $9-11+2=0$.
3. East–west: $10-7=3\text{km}$ east of A.
4. So P is 3 km east of A; to return he drives 3 km to the west.

Trick: Four left turns bring you back to the start direction — only the leftover east–west gap matters.

Answer: (A) 3 km to the west