RRB NTPC Graduate CBT 2 2024 PYQs

Concept: Remove all symbols ($, &, *, %) and then count positions.

1. Remaining: T 1 9 Z 7 A M S 1 D 7 → 11 elements.
2. 7th from right = $(11-7+1)=5$th from left.
3. 5th from left = 7

Trick: $k$th from right $=(n-k+1)$th from left.

Answer: (B) 7

Concept: Fix the definite positions first, then fill the rest with the remaining conditions.

1. Only two scored more than A → A is 3rd.
2. Only B scored less than D → B is 6th, D is 5th.
3. Left positions 1, 2, 4 for C, X, Y with C > X > Y → C 1st, X 2nd, Y 4th.
4. Only C scored more than X → one person.

Trick: Place the 'only' clues first – they fix exact ranks.

Answer: (B) One

Concept: Each letter of the first cluster is shifted forward by the same number of places.

1. M→U, P→X, Q→Y, O→W: each letter $+8$.
2. D→L, G→O, H→P, F→N: again each $+8$.
3. K+8 = S, N+8 = V, O+8 = W, M+8 = U → SVWU.

Trick: Check only the first letter of each option: all start with S, so test the second letter N+8 = V.

Answer: (B) SVWU

Concept: Use the fixed day (Q on Thursday) and the gap condition between U and P first.

1. Four people between U and P → they are on (Mon, Sat) or (Tue, Sun); Sunday is not allowed → U, P on Mon and Sat.
2. If U were Saturday, S would have to be Sunday and R Saturday – clash. So U = Mon, P = Sat.
3. R, S consecutive in the free days → R = Tue, S = Wed.
4. T and V take Fri, Sun; V not Friday → T = Fri, V = Sun. After P (Sat) only V → 1.

Trick: With 7 days, "4 between" leaves only two pairs: (1, 6) or (2, 7).

Answer: (C) 1

Concept: Ministers who are Managers but not Engineers = region common to Ministers and Managers only, outside the Engineers circle.

1. Region only in Ministers = 10 (not Managers).
2. Region in Managers and Engineers = 9 (not Ministers).
3. Region common to Ministers and Managers only = 8.

Trick: Read the question as "inside A and B, outside C" and shade just that region.

Answer: (B) 8

Concept: Look at the differences between consecutive terms.

1. Differences: $25-12=13$, $51-25=26$, $90-51=39$, $142-90=52$.
2. They are multiples of 13: $13\times 1,13\times 2,13\times 3,13\times 4$.
3. Next difference $=13\times 5=65$ → $142+65=207$.

Trick: Differences in a table of a number (13, 26, 39…) → just add the next multiple.

Answer: (A) 207

Concept: Decode each option; R must be the brother of a woman who is T's mother.

1. Option (C): P ÷ Q → P is father of Q; Q × R → Q is wife of R.
2. R – S → R is brother of S; S + T → S is mother of T.
3. So S is T's mother and R is her brother → R is T's mother's brother (maternal uncle).
4. In (B), R ÷ S makes R a father, and in (D), R × S makes R a wife – both wrong.

Trick: Look for the pattern "R – S + T" (R brother of S, S mother of T) in the options.

Answer: (C) P ÷ Q x R – S + T

Concept: Each position of the clusters moves forward by the same step.

1. First letters: J, R, Z, H, P, X – each $+8$ (with wrap-around).
2. Second letters: F, N, V, D, L, T – each $+8$.
3. Third letters: B, J, R, Z, ?, P → after Z comes Z+8 = H, so the fifth cluster should be PLH.
4. Given PLK breaks the pattern.

Trick: Check one position at a time; the odd letter shows the wrong cluster at once.

Answer: (C) PLK

Concept: Find the letter-gaps inside each pair: first cluster XY, second cluster PQ.

1. KO−NR: K+4 = O, K+3 = N, N+4 = R.
2. MQ−PT: M+4 = Q, M+3 = P, P+4 = T. AE−DH: A+4 = E, A+3 = D, D+4 = H.
3. GK−IP: G+4 = K but G+2 = I and I+7 = P – pattern broken.

Trick: Pattern is (+4) in each cluster and (+3) between clusters; GK−IP fails at once.

Answer: (D) GK−IP

Concept: Number the letters 1 2 3 4 and find how positions move.

1. WASH → HSWA: order 4 3 1 2. NEST → TSNE: same 4 3 1 2.
2. HSWA → WSAH: order 3 2 4 1 of the second word (NSET from TSNE too).
3. OILS → 4 3 1 2 = SLOI; SLOI → 3 2 4 1 = OLIS. Matches (D).
4. FOGS → 4 3 1 2 would be SGFO ✓, but SGFO → 3 2 4 1 = FGOS, not OGFS.

Trick: Fix the rule on one triad, verify on the second, then test options only.

Answer: (D) OILS - SLOI - OLIS

Concept: Find one operation that converts the first number into the second in both pairs.

1. $11\times 6+2=68$.
2. $14\times 6+2=86$.
3. Option (B): $17\times 6+2=104$ ✓. (A) gives 103, (C) and (D) would need $18\times 6+2=110$.

Trick: Difference of second numbers $86-68=18$ for difference 3 in first numbers → multiplier $=6$.

Answer: (B) 17, 104

Concept: Place A at the origin, east = +x, north = +y, and track both journeys.

1. Namesh: west 4 → $(-4,0)$; left (south) 5 → $(-4,-5)$; left (east) 6 → B $=(2,-5)$.
2. P $=(16,0)$. Rimit: east 3 → $(19,0)$; right (south) 5 → $(19,-5)$; left (east) 3 → Q $=(22,-5)$.
3. B and Q are on the same line $y=-5$: BQ $=22-2=20\text{km}$.

Trick: Both end 5 km south, so only the east–west gap matters.

Answer: (C) 20 km

Concept: A course of action follows if it practically tackles a cause stated in the problem.

1. Cause 1 – excessive fishing: regulating fishing for some months lets fish breed and recover → I follows.
2. Cause 2 – industrial pollution: treating waste before discharge removes the pollution → II follows.
3. Both actions address the two stated causes directly.

Trick: One action per cause mentioned in the statement → both follow.

Answer: (D) Both I and II follow

Concept: Row 2 faces north (its left = west); Row 1 faces south (its left = east). Number columns 1–4 from west to east.

1. U third to the left of Y → U at 1, Y at 4 (Row 2).
2. Person facing P is Y's neighbour → column 3, so P is at 3 (Row 1).
3. D third to the right of O (Row 1 faces south) → O at 4, D at 1; A right of P → A at 2.
4. A is not facing W → column 2 of Row 2 is F, W at 3. So F faces A.

Trick: For south-facing people, "right" is your left on paper – flip directions for Row 1.

Answer: (C) A

Concept: Find the common operation in both given pairs.

1. $6\times 6-2=34$.
2. $8\times 6-2=46$.
3. $10\times 6-2=58$.

Trick: Increase of 2 in the first number raised the second by 12 → multiplier 6.

Answer: (D) 58

Concept: Place people with the fixed rank first, then fit the chain of comparisons.

1. C is shorter than exactly one person → C is 2nd tallest; C < B → B is tallest.
2. Chain: A > D > F > E fills ranks 3 to 6.
3. Order: B > C > A > D > F > E → taller than D: B, C, A = 3.

Trick: "Shorter than exactly one" means rank 2 from the top.

Answer: (C) 3

Concept: Remove the numbers first, write the new series, then count from the right.

1. Numbers removed: 4, 7, 5, 2, 3, 6.
2. New series: D & A $ Z G R % W @ # V & F Y.
3. From the right: Y(1), F(2), &(3), V(4), #(5), @(6), W(7).

Trick: Count from the right end directly, skipping digits as you go – no need to rewrite the whole series.

Answer: (D) W

Concept: A word common to two sentences takes the code common to them.

1. "knowledge" is in sentences 1 and 2 → common code xp.
2. "power" is in sentences 2 and 3 → common code vr.
3. Sentence 2: knowledge is power = zk xp vr → is = zk.

Trick: Remove the known codes from the sentence containing the target word.

Answer: (C) zk

Concept: Start with S on Tuesday, then place the two consecutive pairs (T, U) and (Q, R).

1. Two people between S (Tue) and P → P = Fri (going back is impossible).
2. Free days: Mon, Wed, Thu, Sat, Sun. Consecutive free pairs: (Wed, Thu) and (Sat, Sun).
3. If T, U = Wed, Thu and Q, R = Sat, Sun: between U (Thu) and Q (Sat) only P → 1 ✓. The other way, U = Sun and Q = Wed have 3 between ✗.
4. V = Mon. Q = Sat → after Q only R → 1.

Trick: Locate consecutive free slots first – they fix both pairs at once.

Answer: (D) 1

Concept: To name the shortest of 5 people, every person must be compared so that one is below all others.

1. I alone: A < E, K < F – two separate chains; D not mentioned → not enough.
2. II alone: only K > A → not enough.
3. I + II: A < K < F and A < E, so A is below F, K, E – but D is never compared, so A or D could be shortest.

Trick: Any person missing from all statements makes "shortest/tallest" impossible to decide.

Answer: (A) Data in statements I and II together are NOT sufficient to answer the question