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RRB NTPC Undergraduate CBT 1 2025 · Shift 1

RRB NTPC Undergraduate CBT 1 7 May 2026 Shift 1 – Question Paper

100 questions · 100 marks · 90 minutes · +1 for a correct answer, −1/3 for a wrong one. With answer key and detailed solutions in Hindi and English.

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Paper pattern

SectionQuestionsMarks
General Awareness4040
Mathematics3030
General Intelligence and Reasoning3030

Sample questions from this paper

Q1.
By which Amendment Act were the words ‘socialist’, ‘secular’, and ‘integrity’ added to the Preamble of the Indian Constitution?
किस संशोधन अधिनियम द्वारा भारतीय संविधान की प्रस्तावना में ‘समाजवादी’, ‘पंथनिरपेक्ष’ और ‘अखंडता’ शब्द जोड़े गए?
  1. A42nd Amendment Act42वाँ संशोधन अधिनियम
  2. B52nd Amendment Act52वाँ संशोधन अधिनियम
  3. C32nd Amendment Act32वाँ संशोधन अधिनियम
  4. D62nd Amendment Act62वाँ संशोधन अधिनियम
Show answer

Concept: The Preamble has been amended only once.

  1. The 42nd Constitutional Amendment Act, 1976 (Indira Gandhi government, during the Emergency) inserted "Socialist", "Secular" and "Integrity" into the Preamble.
  2. The 52nd Amendment (1985) is the Anti-Defection Law – a common distractor.

Yaad rakhein: 42nd = "Mini Constitution" = S-S-I (Socialist, Secular, Integrity).

Answer: (A) 42nd Amendment Act

अवधारणा: प्रस्तावना में केवल एक बार संशोधन हुआ है।

  1. 42वें संविधान संशोधन अधिनियम, 1976 (इंदिरा गांधी सरकार, आपातकाल के दौरान) ने "समाजवादी", "पंथनिरपेक्ष" और "अखंडता" शब्द प्रस्तावना में जोड़े।
  2. 52वाँ संशोधन (1985) दल-बदल विरोधी कानून है – भ्रमित करने वाला विकल्प।

याद रखें: 42वाँ = "लघु संविधान" = S-S-I (Socialist, Secular, Integrity)।

उत्तर: (A) 42वाँ संशोधन अधिनियम

RRB NTPC Undergraduate CBT 1General AwarenessIndian Polity – Preamble
Q41.
A dealer sells a product at 15% profit. If he had bought it at 10% less and sold it for ₹126 less, he would have gained 20%. Find the cost price.
एक व्यापारी एक वस्तु को 15% लाभ पर बेचता है। यदि उसने इसे 10% कम में खरीदा होता और ₹126 कम में बेचा होता, तो उसे 20% लाभ होता। क्रय मूल्य ज्ञात कीजिए।
  1. A₹1,400
  2. B₹1,800
  3. C₹2,000
  4. D₹1,200
Show answer

Concept: Write both selling prices in terms of the cost price x and compare their difference with ₹126.

  1. Original: SP =1.15x.
  2. New CP =0.9x, gain 20% ⟹ new SP =1.2×0.9x=1.08x.
  3. Difference: 1.15x−1.08x=0.07x=126 ⟹ x=1800.

Trick: Successive % on CP: 0.9×1.2=1.08, so the gap is (115−108)%=7% of CP = ₹126.

Answer: (B) ₹1,800

अवधारणा: दोनों विक्रय मूल्य (SP) लागत मूल्य x के रूप में लिखें और अंतर को ₹126 के बराबर रखें।

  1. मूल: SP =1.15x।
  2. नया CP =0.9x, लाभ 20% ⟹ नया SP =1.2×0.9x=1.08x।
  3. अंतर: 1.15x−1.08x=0.07x=126 ⟹ x=1800।

ट्रिक: CP पर क्रमिक %: 0.9×1.2=1.08, अतः अंतर (115−108)%=7% CP का = ₹126।

उत्तर: (B) ₹1,800

RRB NTPC Undergraduate CBT 1MathematicsProfit and Loss
Q71.
Refer to the following series and answer the question. (Counting to be done from left to right only.) (all numbers are single digit numbers only.)
(Left) 9 2 3 1 4 5 6 8 5 4 3 2 1 9 3 4 5 6 7 8 1 2 9 8 3 4 5 2 6 8 2 (Right)
How many such even digits are there, each of which is immediately preceded by a perfect square and immediately followed by an odd digit? (NOTE: 1 is also a perfect square.)
निम्नलिखित श्रृंखला को देखिए और प्रश्न का उत्तर दीजिए। (गिनती केवल बाएँ से दाएँ की ओर की जानी है।) (सभी संख्याएँ केवल एक अंक की संख्याएँ हैं।)
(बायाँ) 9 2 3 1 4 5 6 8 5 4 3 2 1 9 3 4 5 6 7 8 1 2 9 8 3 4 5 2 6 8 2 (दायाँ)
ऐसे कितने सम अंक हैं, जिनमें से प्रत्येक के ठीक पहले एक पूर्ण वर्ग और ठीक बाद एक विषम अंक है? (नोट: 1 भी एक पूर्ण वर्ग है।)
  1. AThreeतीन
  2. BMore than threeतीन से अधिक
  3. CTwoदो
  4. DOneएक
Show answer

Concept: Check every even digit: the digit just before it must be a perfect square (1, 4, 9) and the digit just after it must be odd.

  1. Series: 9 2 3 1 4 5 6 8 5 4 3 2 1 9 3 4 5 6 7 8 1 2 9 8 3 4 5 2 6 8 2.
  2. 9–2–3 ✓, 1–4–5 ✓, 1–2–9 ✓, 9–8–3 ✓.
  3. Other even digits are preceded by 5, 6, 3, 7, 2 or 8 (not squares), so they fail.
  4. Total = 4, i.e. more than three.

Trick: Scan only the evens and look one step left for 1, 4 or 9 – this cuts the checking to a few digits.

Answer: (B) More than three

अवधारणा: हर सम अंक जाँचें: उसके ठीक पहले पूर्ण वर्ग (1, 4, 9) और ठीक बाद विषम अंक होना चाहिए।

  1. श्रृंखला: 9 2 3 1 4 5 6 8 5 4 3 2 1 9 3 4 5 6 7 8 1 2 9 8 3 4 5 2 6 8 2।
  2. 9–2–3 ✓, 1–4–5 ✓, 1–2–9 ✓, 9–8–3 ✓।
  3. बाकी सम अंकों से पहले 5, 6, 3, 7, 2 या 8 हैं (वर्ग नहीं), अतः वे नहीं गिने जाते।
  4. कुल = 4, यानी तीन से अधिक।

ट्रिक: केवल सम अंकों को देखें और एक कदम बाएँ 1, 4 या 9 खोजें – जाँच कुछ ही अंकों तक सिमट जाती है।

उत्तर: (B) More than three (तीन से अधिक)

RRB NTPC Undergraduate CBT 1General Intelligence and ReasoningNumber Series Counting

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