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RRB NTPC Undergraduate CBT 1 2025 · Shift 2

RRB NTPC Undergraduate CBT 1 8 May 2026 Shift 2 – Question Paper

100 questions · 100 marks · 90 minutes · +1 for a correct answer, −1/3 for a wrong one. With answer key and detailed solutions in Hindi and English.

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Paper pattern

SectionQuestionsMarks
General Awareness4040
Mathematics3030
General Intelligence and Reasoning3030

Sample questions from this paper

Q1.
Which of the following is the most widely used irrigation method in India?
भारत में निम्नलिखित में से कौन-सी सिंचाई विधि सबसे अधिक व्यापक रूप से प्रयोग की जाती है?
  1. ASurface irrigationसतही सिंचाई (Surface irrigation)
  2. BSprinkler irrigationफव्वारा सिंचाई (Sprinkler irrigation)
  3. CDrip irrigationड्रिप (टपक) सिंचाई (Drip irrigation)
  4. DSubsurface irrigationउपसतही सिंचाई (Subsurface irrigation)
Show answer

Concept: Irrigation methods: surface (flood/furrow), sprinkler, drip and subsurface.

  1. Surface irrigation – water flows over the field by gravity through canals, wells and tube-wells – covers the overwhelming majority of India's irrigated area.
  2. Sprinkler and drip (micro-irrigation) are water-efficient but still cover only a small share, promoted under PMKSY "Per Drop More Crop".

Yaad rakhein: Most used = surface (flood); most efficient = drip.

Answer: (A) Surface irrigation

अवधारणा: सिंचाई विधियाँ: सतही (flood/furrow), फव्वारा (sprinkler), टपक (drip) और उप-सतही (subsurface)।

  1. सतही सिंचाई – नहर, कुएँ और नलकूप से पानी गुरुत्व द्वारा खेत में बहता है – भारत के सिंचित क्षेत्र के अधिकांश भाग में प्रयुक्त होती है।
  2. फव्वारा व टपक (सूक्ष्म सिंचाई) जल-कुशल हैं पर इनका हिस्सा अभी कम है; PMKSY "Per Drop More Crop" से प्रोत्साहित।

याद रखें: सबसे अधिक प्रयुक्त = सतही (flood); सबसे कुशल = टपक (drip)।

उत्तर: (A) सतही सिंचाई (Surface irrigation)

RRB NTPC Undergraduate CBT 1General AwarenessIrrigation methods in India
Q41.
If x=225+484, what is the value of x2−[(225)2+(32)2]?
यदि x=225+484 है, तो x2−[(225)2+(32)2] का मान क्या है?
  1. A0
  2. B484
  3. C120
  4. D100
Show answer

Concept: Simplify the surds first, then substitute. (225)2=225.

  1. x=225+484=15+22=37, so x2=1369.
  2. Bracket: (225)2+(32)2=225+1024=1249.
  3. x2−1249=1369−1249=120.

Trick: Squaring a square root just removes the root sign – no need to compute 225 for that term.

Answer: (C) 120

अवधारणा: पहले करणियों (surds) को सरल करें, फिर मान रखें। (225)2=225.

  1. x=225+484=15+22=37, अतः x2=1369.
  2. कोष्ठक: (225)2+(32)2=225+1024=1249.
  3. x2−1249=1369−1249=120.

ट्रिक: वर्गमूल का वर्ग करने पर केवल मूल चिह्न हट जाता है – उस पद के लिए 225 निकालने की ज़रूरत नहीं।

उत्तर: (C) 120

RRB NTPC Undergraduate CBT 1MathematicsSurds and simplification
Q71.
Which of the following letter-number clusters will replace the question mark (?) in the given series to make it logically complete?
HDK 10, LIO 15, PNS 20, TSW 25, ?
दी गई शृंखला में प्रश्नचिह्न (?) के स्थान पर निम्नलिखित में से कौन-सा अक्षर-संख्या समूह आएगा जिससे शृंखला तार्किक रूप से पूर्ण हो जाए?
HDK 10, LIO 15, PNS 20, TSW 25, ?
  1. AXYB 30
  2. BYYB 30
  3. CYXA 28
  4. DXXA 30
Show answer

Concept: Check each position of the letter cluster and the number separately.

  1. 1st letters H(8), L(12), P(16), T(20): +4 → X(24).
  2. 2nd letters D(4), I(9), N(14), S(19): +5 → 19+5=24 = X.
  3. 3rd letters K(11), O(15), S(19), W(23): +4 → 23+4=27→1 = A (wrap after Z).
  4. Numbers 10, 15, 20, 25: +5 → 30. Term = XXA 30.

Trick: Write positions A=1…Z=26 and count beyond 26 cyclically (27→1).

Answer: (D) XXA 30

अवधारणा: अक्षर-समूह की हर स्थिति और संख्या को अलग-अलग जाँचें।

  1. पहले अक्षर H(8), L(12), P(16), T(20): +4 → X(24)।
  2. दूसरे अक्षर D(4), I(9), N(14), S(19): +5 → 19+5=24 = X।
  3. तीसरे अक्षर K(11), O(15), S(19), W(23): +4 → 23+4=27→1 = A (Z के बाद फिर A)।
  4. संख्याएँ 10, 15, 20, 25: +5 → 30। पद = XXA 30।

ट्रिक: A=1…Z=26 लिखें और 26 के बाद चक्रीय गिनें (27→1)।

उत्तर: (D) XXA 30

RRB NTPC Undergraduate CBT 1General Intelligence and ReasoningAlphanumeric Series

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