Q&A: practice questions with answers

Concept: Facing the centre, 'left' is clockwise and 'right' is anticlockwise.

1. Place P; R immediately left of P; H third to the left of P.
2. I neighbours both H and Q; the seat between P-side and H is beside R, so I and Q go on H's other side.
3. J is not next to H ⇒ J sits beside P, S between R and H.
4. Third to the left of S: H, I, Q ⇒ Q

Trick: Fix the person named in most clues (P) first, then count seats.

Answer: (C) Q

Concept: Position from left $=$ Total $-$ position from right $+1$.

1. Alok from left $=30-12+1=19$
2. Aman is 16th from left
3. Between them $=19-16-1=2$

Trick: Between two people counted from the same end $=$ difference $-1$.

Answer: (B) 2

Concept: Apply the rule digit by digit (odd +3, even −1), then count repeated digits.

1. 6 2 4 3 5 1 4 → 5 1 3 6 8 4 3
2. Digit 3 appears twice; all others once
3. Only one digit repeats

Trick: Repeats in the original (4 twice) may vanish or new ones appear – always recount after changing.

Answer: (D) One

Concept: Drop every symbol and re-index only the digits from the left.

1. Digits only: 1, 2, 6, 7, 3, 4, 2, 5, 9, 0, 2, 3, 6, 8
2. Fifth from left = 3

Trick: Only the stretch up to the 5th digit matters: 1 $ 2 6 7 3 → fifth digit is 3.

Answer: (A) 3

Concept: Odd digits +1, even digits −2, keeping positions.

1. 7 4 3 1 8 5 6 → 8 2 4 2 6 6 4
2. Second from right = 6

Trick: Only change the needed digit: second from right is 5 (odd) → 6.

Answer: (D) 6

Concept: Each letter moves forward by the same step in the next term.

1. K→R→Y→F (+7, wrapping after Z); P→W→D→K (+7); V→C→J→Q (+7)
2. Next: F+7 = M, K+7 = R, Q+7 = X
3. Term = MRX

Trick: For wrap-around, subtract 26: Y(25)+7 = 32 − 26 = 6 = F.

Answer: (C) MRX

Concept: With jumbled digit codes, the common letter gets the common digit.

1. FATE → {2, 3, 5, 7}; TURN → {4, 1, 2, 6}
2. Common letter: T; common digit: 2
3. So T = 2

Trick: Common letter ↔ common digit.

Answer: (D) 2

Concept: Track first letters and second letters of the three pairs separately.

1. MT-OV-QS: first letters M→O→Q (+2, +2); second letters T→V→S (+2, −3)
2. OV-QX-SU: O→Q→S (+2, +2); V→X→U (+2, −3)
3. HO-JQ-LN: H→J→L (+2, +2); O→Q→N (+2, −3) ✓

Trick: Option A/B fail at the last letter (Q−3 = N, not M); D fails at G→I→L.

Answer: (C) HO-JQ-LN

Concept: Compare 1st→3rd and 2nd→4th letters by position.

1. SL-NQ: S−5 = N, L+5 = Q; XQ-SV: X−5 = S, Q+5 = V
2. VO-QT: V−5 = Q, O+5 = T
3. TM-OS: T−5 = O but M+6 = S (not +5) → odd

Trick: Rule −5 / +5; one gap breaking it marks the odd pair.

Answer: (A) TM-OS

Concept: Facing the centre, left = clockwise, right = anticlockwise. In a circle of 6, 'third to the right' is the opposite seat.

1. Arti third to the right of Pooja ⇒ Arti opposite Pooja.
2. Rajesh second to the left of Arti.
3. Neetu second to the left of Santosh ⇒ only possible with Santosh next to Arti (on the side away from Rajesh) and Neetu beside Arti on the other side; Heera fills the last seat.
4. Immediate right of Santosh = Heera

Trick: In 6 seats, 3rd left = 3rd right = opposite – place that pair first.

Answer: (C) Heera

Concept: Check consecutive differences.

1. Differences: 15, 20, 25, 30 (increase by 5)
2. Next difference $=35$
3. $125+35=160$

Trick: Differences in steps of 5 → next is 35.

Answer: (B) 160

Concept: Total $=$ position from left $+$ position from right $-1$.

1. Uma is midway: Navya 12th, Uma 19th ⇒ gap 7, so Dilip $=19+7=26$th from left
2. Dilip is 13th from right
3. Total $=26+13-1=38$

Trick: Midpoint rule: Dilip $=2\times 19-12=26$.

Answer: (D) 38

Concept: Check every symbol: the element just before it must be odd and the one just after it even.

1. % (8 before), * (% before), Ω (* before) – fail
2. # : 1 before (odd), 4 after (even) ✓
3. π (0 before), μ (9 before, 7 after – odd), Ω (8 before), # (Ω before), β (nothing after) – fail

Trick: Look for the pattern odd–symbol–even directly: only '1 # 4'.

Answer: (C) One

Concept: Write letter positions: first→second (+6), first→third (+10), third→fourth (−9).

1. FL-PG: 6, 12, 16, 7 → +6, +10, −9
2. HN-RI: 8, 14, 18, 9 ✓; DJ-NE: 4, 10, 14, 5 ✓
3. BH-LD: 2, 8, 12, 4 → last step −8 → odd

Trick: Check the last gap of each pair – three show −9, one shows −8.

Answer: (D) BH - LD

Concept: Plot each leg; facing west, a left turn means south; four left turns go W → S → E → N → W.

1. A → 20 km W; left (S) 18 km; left (E) 23 km; left (N) 25 km; left (W) 3 km → P
2. East–west: −20 + 23 − 3 = 0 ⇒ P is in line with A
3. North–south: −18 + 25 = 7 km north ⇒ go 7 km south

Trick: Net each axis separately: horizontal cancels, vertical leaves 7 km north.

Answer: (C) 7 km to the South

Concept: Build the family tree; parents of the same child are a couple.

1. H is the father of E and E is the son of N ⇒ N is H's wife.
2. A is H's sister.
3. So A is N's husband's sister (M, N's mother, is extra information).

Trick: Husband's sister = 'nanad' – the common child links H and N as a couple.

Answer: (D) Husband's sister

Concept: Step 1: letters 1, 2, 3, 4 → order 2, 3, 1, 4. Step 3: the original word reversed.

1. GAIN → AIGN (A I G N) → NIAG (GAIN reversed)
2. SINE → INSE → ENIS ✓
3. RICE → ICRE (I C R E) → ECIR (RICE reversed) ✓

Trick: Check the third word first – it must be the first word reversed; only RICE–ECIR and SEAT–TAES pass, and SAET fails step 1.

Answer: (D) RICE - ICRE - ECIR

Concept: Step 1: letters 1, 2, 3, 4 → order 1, 4, 3, 2. Step 3: the original word reversed.

1. MARK → MKRA → KRAM (MARK reversed)
2. PLAY → PYAL → YALP ✓
3. BUSH → BHSU (B H S U) → HSUB (BUSH reversed) ✓

Trick: Third word = first word reversed; middle word keeps the first letter and swaps 2nd and 4th.

Answer: (D) BUSH - BHSU - HSUB

Concept: In the plains a mature river flows slowly and swings in wide loops called meanders.

1. Water erodes the outer bank (faster flow) and deposits on the inner bank, so the loops keep growing.
2. The neck of a loop becomes very narrow; during a flood the river cuts straight across it.
3. The abandoned loop is left as a crescent-shaped lake – an oxbow lake.
4. Waterfalls and rapids form in the youthful (mountain) stage; rift valleys form by faulting, not by rivers.

Yaad rakhein: Meander → cut-off → oxbow lake: a typical landform of the lower course (e.g., Ganga plains).

Answer: (B) Formation of oxbow lakes

Concept: RLEGP was a centrally sponsored wage-employment programme for landless rural households.

1. It was launched on 15 August 1983 to give guaranteed employment of up to 100 days to at least one member of every landless household.
2. In 1989 RLEGP and NREP (1980) were merged into the Jawahar Rozgar Yojana (JRY).

Yaad rakhein: NREP – 1980, RLEGP – 1983, both merged into JRY – 1989.

Answer: (B) 15 August 1983