RRB NTPC Undergraduate CBT 2 2024 PYQs

Concept: Draw the Venn diagram: Bulbs lie fully inside Magnets and partly overlap Lights.

1. Some bulbs are lights, and those bulbs are also magnets → at least some magnets are lights. (I) follows.
2. All bulbs are magnets → "Some magnets are bulbs" (conversion of "All"). (II) follows.

Trick: "Some A are B" + "All A are C" → "Some C are B" always follows.

Answer: (C) Both conclusions (I) and (II) follow.

Concept: A word common to two sentences gets the code common to both.

1. bell poet visit → js vx gu
2. yard visit queen → aw ks js
3. Common word "visit" ↔ common code "js".

Trick: Match common word with common code – order of codes does not matter.

Answer: (D) js

Concept: Find the rule linking the three numbers (a, b, c).

1. (5, 14, 24): $5\times 2+4=14$, $14+2\times 5=24$.
2. (3, 10, 16): $3\times 2+4=10$, $10+2\times 3=16$.
3. Rule: $b=2a+4$, $c=b+2a$.
4. (7, 18, 32): $7\times 2+4=18$, $18+14=32$ ✔. Others fail, e.g. (9, 14, 24): $2\times 9+4=22\ne 14$.

Trick: Check the first link ($2a+4$) on options first – only (B) survives.

Answer: (B) (7, 18, 32)

Concept: Interchange the signs on both sides, then use BODMAS.

1. New equation: $3\times 2-15÷3+5=?-10$.
2. LHS: $6-5+5=6$.
3. $?-10=6\Rightarrow ?=16$.

Trick: Don't forget the "+" on the right side also changes to "−".

Answer: (D) 16

Concept: Fix the certain positions first (7 seats, numbered from the left).

1. Three left of E → E is 4th.
2. Only O right of G → G = 6th, O = 7th.
3. Three between G and F → F = 2nd.
4. Left seats 1, 3, 5 for D, Q, P with D left of Q left of P → D = 1, Q = 3, P = 5.
5. Between D and P: F, Q, E = 3 people.

Trick: People between = difference of positions − 1 = $5-1-1=3$.

Answer: (D) Three

Concept: Look at the differences between consecutive terms.

1. Differences: $1,4,9,16,25$ = $1^2,2^2,3^2,4^2,5^2$.
2. Next difference $=6^2=36$.
3. $112+36=148$.

Trick: Slowly growing differences 1, 4, 9 … → perfect squares.

Answer: (C) 148

Concept: Facing the centre, "right" means moving anticlockwise.

1. T is immediate right of L; K and T have two people between (from K's right) → K is second to the left of L.
2. Three people between L and S (from L's right) → S is fourth to the right of L.
3. Remaining three seats: two adjacent (for R then J on its right) and one for I.
4. Order to the right of I: L, T, R, J → 4th to the right of I is J.

Trick: Number seats in the "right" direction: L = 0, T = 1, S = 4, K = 5 → R = 2, J = 3, I = 6; $6+4=10\equiv 3$ → J.

Answer: (B) J

Concept: Replace letters by signs, then apply BODMAS.

1. $138\times 2+24÷4-8$
2. $=276+6-8$
3. $=274$

Trick: Do × and ÷ first: 276 and 6, then $282-8$.

Answer: (C) 274

Concept: Each step moves the last letter to the front.

1. BATH → H + BAT = HBAT → T + HBA = THBA.
2. TOYS → S + TOY = STOY → Y + STO = YSTO.
3. ABLE → E + ABL = EABL → L + EAB = LEAB ✔.
4. LOVE → OVEL moves the first letter to the end – wrong pattern.

Trick: Check if the 2nd term starts with the last letter of the 1st – only ABLE → EABL does.

Answer: (C) ABLE – EABL – LEAB

Concept: Decode each symbol and draw the family tree.

1. S + G → S is the son of G.
2. G & J → G is the father of J; so S and J are siblings.
3. J # K → J is the sister of K; so K is also G's child.
4. K x T → K is the wife of T.
5. S is the brother of T's wife → wife's brother.

Trick: S (male) and K are children of the same father G; K is T's wife.

Answer: (D) Wife's brother

Concept: Track net East–West and North–South displacement from Y.

1. Moves: S 13, W 59, S 49, E 21, N 37, E 38, S 23.
2. East–West: $-59+21+38=0$ → Z is directly in line with Y.
3. North–South: $-13-49+37-23=-48$ → Z is 48 km south of Y.
4. To return, drive 48 km towards north.

Trick: After a right turn while facing south you face west; after a left turn while facing west you face south.

Answer: (D) 48 km towards north

Concept: Track net displacement from A.

1. Moves: W 32, S 30, E 49, N 46, W 17.
2. East–West: $-32+49-17=0$.
3. North–South: $-30+46=16$ → P is 16 km north of A.
4. To return, drive 16 km to the south.

Trick: Four left turns from west go W → S → E → N → W.

Answer: (C) 16 km to the south

Concept: Combine both statements and check whether one stick is surely the longest.

1. (I): A > M > N – says nothing about C and G.
2. (II): G > N > C – says nothing about A and M.
3. Together: both A and G are longer than N, but A vs G is unknown.
4. The longest could be A or G → not sufficient.

Trick: Two chains meeting only at a lower member (N) never fix the top.

Answer: (B) Both statements I and II together are not sufficient to answer the question.

Concept: Number the positions 1 (bottom) to 7 (top), fix the certain boxes first, then test whether the remaining clues give one unique stack.

1. Only two boxes below G $\Rightarrow$ G = 3. Only one box above V $\Rightarrow$ V = 6. One box between V and U $\Rightarrow$ U = 4 (position 8 does not exist).
2. Free positions 1, 2, 5, 7 are for X, W, E, F.
3. The clue "X is kept immediately above P" names a box P that is not among the seven boxes (U, V, W, X, E, F, G), so it cannot be applied.
4. With only "W below E" left, several stacks are possible (bottom to top): W, X, G, U, F, V, E gives 4 boxes between E and X; W, F, G, U, X, V, E gives 1; W, X, G, U, E, V, F gives 2; X, W, G, U, E, V, F gives 3.
5. Every option can occur, so the answer is not unique as printed.
6. If the clue had been "X is kept immediately above F", the stack would be F, X, G, U, W, V, E and the answer would be Four (A).

Note: When a clue names an item outside the given set, check whether the other clues alone fix the arrangement. In the exam, every candidate gets full marks (bonus) for such a question.

Answer: Bonus – no option is correct as printed; full marks to all.

Concept: Compare each letter of the first cluster with the matching letter of the second (A = 1 … Z = 26).

1. QR – WX: Q(17) + 6 = W, R(18) + 6 = X.
2. AB – GH: +6, +6. IJ – OP: +6, +6.
3. MN – SV: M(13) + 6 = S, but N(14) + 8 = V(22) ✘.

Trick: In the pattern, the second cluster is also two consecutive letters; SV is not.

Answer: (C) MN – SV

Concept: Track each position separately.

1. 1st letter: M, O, Q, S → U (+2).
2. 2nd letter: I, K, M, O → Q (+2).
3. 3rd letter: D, F, H, J → L (+2).
4. Number: 6, 12, 18, 24 → 30 (+6).

Trick: All letters jump +2; only (A) has U, Q, L with 30.

Answer: (A) UQL 30

Concept: Track each letter position separately (A = 1 … Z = 26, wrap-around allowed).

1. 1st letters: U, R, O, L → I (−3 each).
2. 2nd letters: L, H, D, Z → V (−4 each; D − 4 wraps to Z).
3. 3rd letters: E, Z, U, P → K (−5 each).
4. Answer cluster: IVK.

Trick: Steps −3, −4, −5 for the three positions; only (A) starts with I and ends with K.

Answer: (A) IVK

Concept: Convert both positions to the same end: position from left = Total − position from right + 1.

1. Mohit from left $=48-14+1=35$th.
2. Harini is 15th from left.
3. People between $=35-15-1=19$.

Trick: Since $14+15=29<48$, they do not overlap: between $=48-(14+15)=19$.

Answer: (A) 19

Concept: Compare 1st letter with 1st, 2nd with 2nd (A = 1 … Z = 26, wrap-around allowed).

1. YH – CE: Y + 4 = C, H − 3 = E.
2. CL – GI: C + 4 = G, L − 3 = I.
3. AJ – EG: A + 4 = E, J − 3 = G.
4. HN – TV: H + 12 = T, N + 8 = V ✘.

Trick: In three pairs the second letter goes back (H→E, L→I, J→G); only in HN – TV it goes forward.

Answer: (B) HN – TV

Concept: Decode each symbol and build the family tree.

1. W × Z → W is the son of Z.
2. Z + Y → Z is the father of Y.
3. Y ÷ X → Y is the daughter of X.
4. X – Z → X is the wife of Z.
5. X is the wife of W's father → X is W's mother.

Trick: The father's wife (also mother of his other child) = mother.

Answer: (A) Mother