SSC CPO Paper I · 6,600 questions

SSC CPO Paper I 2020, 2022, 2023, 2024 PYQs

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6,600 questions.

Q6541.

A sum amounts to ₹7,562 in 4 years and to ₹8,469.44 in 5 years at a certain rate per cent per annum, when the interest is compounded yearly. The rate of interest is:

चक्रवृद्धि ब्याज वार्षिक रूप से संयोजित होने पर, एक निश्चित वार्षिक प्रतिशत दर पर कोई राशि 4 वर्षों में ₹7,562 और 5 वर्षों में ₹8,469.44 हो जाती है। ब्याज की दर है:

A $12 %$
B $15 %$
C $20 %$
D $8 %$

Show answer

Concept: Under yearly compounding, the amount of the next year $=$ previous amount $\times (1 + \frac{r}{100})$ .

Interest in 5th year $= 8469.44 - 7562 = 907.44$ .
$r = \frac{907.44}{7562} \times 100 = 12 %$ .

Trick: $\frac{8469.44}{7562} = 1.12$ directly gives $12 %$ .

Answer: (A) $12 %$

अवधारणा: वार्षिक चक्रवृद्धि में अगले वर्ष की राशि $=$ पिछली राशि $\times (1 + \frac{r}{100})$ ।

5वें वर्ष का ब्याज $= 8469.44 - 7562 = 907.44$ ।
$r = \frac{907.44}{7562} \times 100 = 12 %$ ।

ट्रिक: $\frac{8469.44}{7562} = 1.12$ से सीधे $12 %$ ।

उत्तर: (A) $12 %$

SSC CPO Paper IQuantitative AptitudeCompound InterestSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6542.

If A’s salary is 60% more than B’s salary, then by what percentage is B’s salary less than that of A?

यदि A का वेतन B के वेतन से 60% अधिक है, तो B का वेतन A के वेतन से कितने प्रतिशत कम है?

A $45 %$
B $37.5 %$
C $47.7 %$
D $33.3 %$

Show answer

Concept: If A is $r %$ more than B, then B is $\frac{r}{100 + r} \times 100 %$ less than A.

B $= 100$ , A $= 160$ .
B less than A by $\frac{60}{160} \times 100 = 37.5 %$ .

Trick: $60 % = \frac{3}{5}$ more ⇒ $\frac{3}{8}$ less $= 37.5 %$ .

Answer: (B) $37.5 %$

अवधारणा: यदि A, B से $r %$ अधिक है तो B, A से $\frac{r}{100 + r} \times 100 %$ कम है।

B $= 100$ , A $= 160$ ।
B, A से $\frac{60}{160} \times 100 = 37.5 %$ कम।

ट्रिक: $\frac{3}{5}$ अधिक ⇒ $\frac{3}{8}$ कम $= 37.5 %$ ।

उत्तर: (B) $37.5 %$

SSC CPO Paper IQuantitative AptitudePercentageSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6543.

(5 \sqrt{5} x^{3} - 3 \sqrt{3} y^{3}) \div (\sqrt{5} x - \sqrt{3} y) = (A x^{2} + B y^{2} + C x y)

, then the value of

(3 A + B - \sqrt{15} C)

is:

यदि

(5 \sqrt{5} x^{3} - 3 \sqrt{3} y^{3}) \div (\sqrt{5} x - \sqrt{3} y) = (A x^{2} + B y^{2} + C x y)

है, तो

(3 A + B - \sqrt{15} C)

का मान है:

Show answer

Concept: $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ .

Take $a = \sqrt{5} x$ , $b = \sqrt{3} y$ : $a^{3} = 5 \sqrt{5} x^{3}$ , $b^{3} = 3 \sqrt{3} y^{3}$ .
Quotient $= a^{2} + a b + b^{2} = 5 x^{2} + 3 y^{2} + \sqrt{15} x y$ ⇒ $A = 5, B = 3, C = \sqrt{15}$ .
$3 A + B - \sqrt{15} C = 15 + 3 - 15 = 3$ .

Trick: Spot $(\sqrt{5} x)^{3}$ and $(\sqrt{3} y)^{3}$ — then the quotient is the " $a^{2} + a b + b^{2}$ " factor.

Answer: (C) $3$

अवधारणा: $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ ।

$a = \sqrt{5} x$ , $b = \sqrt{3} y$ लें: $a^{3} = 5 \sqrt{5} x^{3}$ , $b^{3} = 3 \sqrt{3} y^{3}$ ।
भागफल $= a^{2} + a b + b^{2} = 5 x^{2} + 3 y^{2} + \sqrt{15} x y$ ⇒ $A = 5, B = 3, C = \sqrt{15}$ ।
$3 A + B - \sqrt{15} C = 15 + 3 - 15 = 3$ ।

ट्रिक: $(\sqrt{5} x)^{3}$ और $(\sqrt{3} y)^{3}$ पहचानें — भागफल " $a^{2} + a b + b^{2}$ " होगा।

उत्तर: (C) $3$

SSC CPO Paper IQuantitative AptitudeAlgebraic IdentitiesSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6544.

Sunita invested ₹12,000 on simple interest at the rate of 10% p.a. to obtain a total amount of ₹20,400 after a certain period. For how many years did she invest to obtain the above amount?

सुनीता ने एक निश्चित अवधि के बाद ₹20,400 की कुल राशि प्राप्त करने के लिए 10% वार्षिक की दर से साधारण ब्याज पर ₹12,000 का निवेश किया। उपर्युक्त राशि प्राप्त करने के लिए उसने कितने वर्षों के लिए निवेश किया?

Show answer

Concept: $SI = \frac{P \times R \times T}{100}$ .

SI $= 20400 - 12000 = 8400$ .
$8400 = \frac{12000 \times 10 \times T}{100} = 1200 T \Rightarrow T = 7$ years.

Trick: One year’s interest $= 1200$ ; $\frac{8400}{1200} = 7$ .

Answer: (D) $7$

अवधारणा: $SI = \frac{P \times R \times T}{100}$ ।

साधारण ब्याज $= 20400 - 12000 = 8400$ ।
$8400 = \frac{12000 \times 10 \times T}{100} = 1200 T \Rightarrow T = 7$ वर्ष।

ट्रिक: एक वर्ष का ब्याज $= 1200$ ; $\frac{8400}{1200} = 7$ ।

उत्तर: (D) $7$

SSC CPO Paper IQuantitative AptitudeSimple InterestSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6545.

One side of a rhombus is 13 cm and one of its diagonals is 10 cm. What is the area of the rhombus (in cm²)?

एक समचतुर्भुज की एक भुजा 13 cm है और उसका एक विकर्ण 10 cm है। समचतुर्भुज का क्षेत्रफल (cm² में) कितना है?

A60
B90
C30
D120

Show answer

Concept: Diagonals of a rhombus bisect each other at right angles; area $= \frac{1}{2} d_{1} d_{2}$ .

Half diagonal $= 5$ ; other half $= \sqrt{13^{2} - 5^{2}} = 12$ .
Other diagonal $= 24$ .
Area $= \frac{1}{2} \times 10 \times 24 = 120$ cm $^{2}$ .

Trick: Triplet $5$ - $12$ - $13$ gives the other half-diagonal instantly.

Answer: (D) $120$

अवधारणा: समचतुर्भुज के विकर्ण एक-दूसरे को समकोण पर समद्विभाजित करते हैं; क्षेत्रफल $= \frac{1}{2} d_{1} d_{2}$ ।

आधा विकर्ण $= 5$ ; दूसरा आधा $= \sqrt{13^{2} - 5^{2}} = 12$ ।
दूसरा विकर्ण $= 24$ ।
क्षेत्रफल $= \frac{1}{2} \times 10 \times 24 = 120$ सेमी $^{2}$ ।

ट्रिक: त्रिक $5$ - $12$ - $13$ से दूसरा आधा विकर्ण तुरंत।

उत्तर: (D) $120$

SSC CPO Paper IQuantitative AptitudeMensuration – RhombusSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6546.

4 - 2 \sin^{2} θ - 5 \cos θ = 0, 0^{\circ} < θ < 90^{\circ}

, then the value of

\cos θ + \tan θ

is:

यदि

4 - 2 \sin^{2} θ - 5 \cos θ = 0, 0^{\circ} < θ < 90^{\circ}

है, तो

\cos θ + \tan θ

का मान है:

A $\frac{2 - \sqrt{3}}{2}$
B $\frac{1 + 2 \sqrt{3}}{2}$
C $\frac{2 + \sqrt{3}}{2}$
D $\frac{1 - 2 \sqrt{3}}{2}$

Show answer

Concept: Replace $\sin^{2} θ = 1 - \cos^{2} θ$ to get a quadratic in $\cos θ$ .

$4 - 2 + 2 \cos^{2} θ - 5 \cos θ = 0 \Rightarrow 2 \cos^{2} θ - 5 \cos θ + 2 = 0$ .
$(2 \cos θ - 1) (\cos θ - 2) = 0 \Rightarrow \cos θ = \frac{1}{2}$ ( $\cos θ = 2$ impossible) ⇒ $θ = 60^{\circ}$ .
$\cos 60^{\circ} + \tan 60^{\circ} = \frac{1}{2} + \sqrt{3} = \frac{1 + 2 \sqrt{3}}{2}$ .

Trick: Put $θ = 60^{\circ}$ : $4 - 2 \times \frac{3}{4} - \frac{5}{2} = 0$ ✓.

Answer: (B) $\frac{1 + 2 \sqrt{3}}{2}$

अवधारणा: $\sin^{2} θ = 1 - \cos^{2} θ$ रखकर $\cos θ$ में द्विघात समीकरण बनाएँ।

$4 - 2 + 2 \cos^{2} θ - 5 \cos θ = 0 \Rightarrow 2 \cos^{2} θ - 5 \cos θ + 2 = 0$ ।
$(2 \cos θ - 1) (\cos θ - 2) = 0 \Rightarrow \cos θ = \frac{1}{2}$ ( $\cos θ = 2$ असंभव) ⇒ $θ = 60^{\circ}$ ।
$\cos 60^{\circ} + \tan 60^{\circ} = \frac{1}{2} + \sqrt{3} = \frac{1 + 2 \sqrt{3}}{2}$ ।

ट्रिक: $θ = 60^{\circ}$ रखें: $4 - 2 \times \frac{3}{4} - \frac{5}{2} = 0$ ✓।

उत्तर: (B) $\frac{1 + 2 \sqrt{3}}{2}$

SSC CPO Paper IQuantitative AptitudeTrigonometric EquationsSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6547.

The given pie chart represents the popularity of ice-cream flavours in the year 2015.

Flavour (2015)	Share
Chocolate	25.8%
Other	20.6%
Strawberry	20.5%
Butterscotch	16.6%
Vanilla	16.5%

In 2015, if the total sale of vanilla flavour is for ₹3,300, then the total sale (in ₹) for chocolate flavour is:

दिया गया पाई चार्ट वर्ष 2015 में आइसक्रीम के स्वादों की लोकप्रियता को दर्शाता है।

स्वाद (2015)	हिस्सा
चॉकलेट	25.8%
अन्य	20.6%
स्ट्रॉबेरी	20.5%
बटरस्कॉच	16.6%
वनीला	16.5%

2015 में, यदि वनीला स्वाद की कुल बिक्री ₹3,300 की है, तो चॉकलेट स्वाद की कुल बिक्री (₹ में) है:

A₹3,320
B₹4,120
C₹4,100
D₹5,160

Show answer

Concept: Sales are proportional to the percentage shares.

Vanilla $16.5 % \to$ ₹ $3300$ ⇒ $1 % \to$ ₹ $200$ .
Chocolate $25.8 % \to 25.8 \times 200 =$ ₹ $5160$ .

Trick: Chocolate $>$ Vanilla, so answer must exceed ₹3,300 by about $\frac{9.3}{16.5}$ — only ₹5,160 fits.

Answer: (D) ₹5,160

अवधारणा: बिक्री प्रतिशत हिस्सों के अनुपात में है।

Vanilla $16.5 % \to$ ₹ $3300$ ⇒ $1 % \to$ ₹ $200$ ।
Chocolate $25.8 % \to 25.8 \times 200 =$ ₹ $5160$ ।

ट्रिक: $1 %$ का मान निकालें, फिर किसी भी हिस्से से गुणा करें।

उत्तर: (D) ₹5,160

SSC CPO Paper IQuantitative AptitudeData Interpretation – Pie ChartSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6548.

△ A B C

, BD

⟂

AC at D. E is a point on BC such that

∠ B E A = x^{\circ}

. If

∠ E A C = 46^{\circ}

and

∠ E B D = 60^{\circ}

, then the value of

x

is:

△ A B C

में, D पर BD

⟂

AC है। BC पर E एक ऐसा बिंदु है कि

∠ B E A = x^{\circ}

है। यदि

∠ E A C = 46^{\circ}

और

∠ E B D = 60^{\circ}

है, तो

x

का मान है:

A $72^{\circ}$
B $78^{\circ}$
C $68^{\circ}$
D $76^{\circ}$

Show answer

Concept: An exterior angle of a triangle equals the sum of the two interior opposite angles.

In $△ B D C$ : $∠ B D C = 90^{\circ}$ , $∠ D B C = 60^{\circ}$ ⇒ $∠ C = 30^{\circ}$ .
In $△ A E C$ , $∠ B E A$ is the exterior angle at E.
$x = ∠ E A C + ∠ E C A = 46^{\circ} + 30^{\circ} = 76^{\circ}$ .

Trick: Find the missing angle at C first, then use the exterior-angle rule.

Answer: (D) $76^{\circ}$

अवधारणा: त्रिभुज का बहिष्कोण दो अंतःसम्मुख कोणों के योग के बराबर होता है।

$△ B D C$ में: $∠ B D C = 90^{\circ}$ , $∠ D B C = 60^{\circ}$ ⇒ $∠ C = 30^{\circ}$ ।
$△ A E C$ में $∠ B E A$ , E पर बहिष्कोण है।
$x = ∠ E A C + ∠ E C A = 46^{\circ} + 30^{\circ} = 76^{\circ}$ ।

ट्रिक: पहले C पर कोण निकालें, फिर बहिष्कोण नियम लगाएँ।

उत्तर: (D) $76^{\circ}$

SSC CPO Paper IQuantitative AptitudeTriangles – Exterior AngleSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6549.

PA and PB are two tangents from a point P outside the circle with centre O. If A and B are points on the circle such that

∠ A P B = 128^{\circ}

, then

∠ O A B

is equal to:

O केंद्र वाले वृत्त के बाहर स्थित एक बिंदु P से PA और PB दो स्पर्श रेखाएँ हैं। यदि A और B वृत्त पर ऐसे बिंदु हैं कि

∠ A P B = 128^{\circ}

है, तो

∠ O A B

किसके बराबर है?

A $72^{\circ}$
B $52^{\circ}$
C $38^{\circ}$
D $64^{\circ}$

Show answer

Concept: Radius $⟂$ tangent, so in quadrilateral OAPB, $∠ A O B + ∠ A P B = 180^{\circ}$ .

$∠ A O B = 180^{\circ} - 128^{\circ} = 52^{\circ}$ .
OA = OB ⇒ $△ O A B$ is isosceles.
$∠ O A B = \frac{180^{\circ} - 52^{\circ}}{2} = 64^{\circ}$ .

Trick: $∠ O A B = \frac{∠ A P B}{2}$ always (here $\frac{128}{2} = 64$ ).

Answer: (D) $64^{\circ}$

अवधारणा: त्रिज्या $⟂$ स्पर्श रेखा, अतः चतुर्भुज OAPB में $∠ A O B + ∠ A P B = 180^{\circ}$ ।

$∠ A O B = 180^{\circ} - 128^{\circ} = 52^{\circ}$ ।
OA = OB ⇒ $△ O A B$ समद्विबाहु।
$∠ O A B = \frac{180^{\circ} - 52^{\circ}}{2} = 64^{\circ}$ ।

ट्रिक: $∠ O A B = \frac{∠ A P B}{2}$ हमेशा (यहाँ $\frac{128}{2} = 64$ )।

उत्तर: (D) $64^{\circ}$

SSC CPO Paper IQuantitative AptitudeCircles – TangentsSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6550.

The value of

\frac{6.35 \times 6.35 \times 6.35 + 3.65 \times 3.65 \times 3.65}{63.5 \times 63.5 + 36.5 \times 36.5 - 63.5 \times 36.5}

is equal to:

\frac{6.35 \times 6.35 \times 6.35 + 3.65 \times 3.65 \times 3.65}{63.5 \times 63.5 + 36.5 \times 36.5 - 63.5 \times 36.5}

का मान किसके बराबर है?

A0.1
B10
C1
D0.01

Show answer

Concept: $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ .

Let $a = 6.35$ , $b = 3.65$ ; denominator $= 100 (a^{2} + b^{2} - a b)$ .
Value $= \frac{(a + b) (a^{2} - a b + b^{2})}{100 (a^{2} - a b + b^{2})} = \frac{a + b}{100}$ .
$= \frac{10}{100} = 0.1$ .

Trick: Watch the decimal shift: denominator numbers are $10$ times larger, so squares are $100$ times.

Answer: (A) $0.1$

अवधारणा: $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ ।

$a = 6.35$ , $b = 3.65$ ; हर $= 100 (a^{2} + b^{2} - a b)$ ।
मान $= \frac{(a + b) (a^{2} - a b + b^{2})}{100 (a^{2} - a b + b^{2})} = \frac{a + b}{100}$ ।
$= \frac{10}{100} = 0.1$ ।

ट्रिक: दशमलव पर ध्यान दें: हर की संख्याएँ $10$ गुना, अतः वर्ग $100$ गुना।

उत्तर: (A) $0.1$

SSC CPO Paper IQuantitative AptitudeAlgebraic Identities – SimplificationSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6551.

Select the most appropriate word to fill in the blank.
Let us know ______ you change your mind.

Ahowever
Balthough
Csuppose
Din case

Show answer

Concept: ‘In case’ is a conjunction meaning ‘if it happens that’; it introduces a possible future situation.

The sentence asks someone to inform us if a certain thing happens: Let us know in case you change your mind.
‘however’ and ‘although’ show contrast – no contrast here.
‘suppose’ starts a hypothesis/question, not a condition attached to a request.

Trick: Request + possible event → ‘in case / if’.

Answer: (D) in case

अवधारणा: ‘In case’ एक conjunction है जिसका अर्थ है ‘यदि ऐसा हो जाए’; यह किसी संभावित स्थिति को बताता है।

वाक्य का अर्थ: यदि तुम अपना मन बदलो तो हमें बता देना – Let us know in case you change your mind.
‘however’ और ‘although’ विरोध (contrast) बताते हैं – यहाँ विरोध नहीं है।
‘suppose’ कल्पना/प्रश्न शुरू करता है, अनुरोध के साथ शर्त नहीं जोड़ता।

ट्रिक: अनुरोध + संभावित घटना → ‘in case / if’।

उत्तर: (D) in case

SSC CPO Paper IEnglish ComprehensionFill in the BlanksSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6552.

Select the most appropriate meaning of the given idiom.
A dry run

Aa rehearsal
Ba poor harvest
Ca slow run
Da run on dry ground

Show answer

Concept: The idiom ‘a dry run’ means a practice or trial performance before the real event.

Example: We did a dry run of the ceremony a day before.
It has nothing to do with harvest, running slowly or dry ground – those are literal readings.

Yaad rakhein: Dry run = rehearsal / trial run.

Answer: (A) a rehearsal

अवधारणा: मुहावरा ‘a dry run’ का अर्थ है असली कार्यक्रम से पहले किया गया अभ्यास (पूर्वाभ्यास)।

उदाहरण: We did a dry run of the ceremony a day before. – समारोह से एक दिन पहले पूर्वाभ्यास किया।
फसल, धीमी दौड़ या सूखी ज़मीन – ये शाब्दिक अर्थ हैं, मुहावरे का नहीं।

याद रखें: Dry run = rehearsal (पूर्वाभ्यास)।

उत्तर: (A) a rehearsal

SSC CPO Paper IEnglish ComprehensionIdioms and PhrasesSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6553.

Select the most appropriate word to fill in the blank.
I’m sure I ______ them at the party last night.

Awas seeing
Bsaw
Cam seeing
Dhave seen

Show answer

Concept: A completed action at a definite past time (‘last night’) takes the Simple Past tense.

‘last night’ is a fixed past time marker → I saw them.
‘have seen’ (Present Perfect) cannot be used with a definite past time.
‘see’ is a stative verb, so continuous forms ‘was seeing / am seeing’ are wrong here.

Trick: yesterday / last night / ago → Simple Past (V2).

Answer: (B) saw

अवधारणा: निश्चित भूतकाल (‘last night’) में पूरी हुई क्रिया के लिए Simple Past लगता है।

‘last night’ निश्चित भूतकाल का संकेत है → I saw them।
Present Perfect ‘have seen’ निश्चित भूतकाल के साथ नहीं आता।
‘see’ stative verb है, इसलिए ‘was seeing / am seeing’ गलत हैं।

ट्रिक: yesterday / last night / ago → Simple Past (V2)।

उत्तर: (B) saw

SSC CPO Paper IEnglish ComprehensionFill in the BlanksSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6554.

Select the most appropriate synonym of the given word.
FOUNDATION

Atop
Bbuilding
Cbase
Dstructure

Show answer

Concept: FOUNDATION means the lowest supporting part on which something rests; its synonym is ‘base’.

‘base’ = bottom support – same meaning.
‘top’ is the opposite; ‘building’ and ‘structure’ are what stand on the foundation.

Yaad rakhein: Foundation = base, basis, groundwork.

Answer: (C) base

अवधारणा: FOUNDATION का अर्थ है नींव – सबसे नीचे का आधार; इसका पर्यायवाची ‘base’ है।

‘base’ = आधार – समान अर्थ।
‘top’ विपरीत है; ‘building’ और ‘structure’ नींव पर खड़े होते हैं, नींव नहीं हैं।

याद रखें: Foundation = base, basis, groundwork (नींव)।

उत्तर: (C) base

SSC CPO Paper IEnglish ComprehensionSynonymsSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6555.

Select the most appropriate word which means the same as the group of words given. Extreme mental or physical suffering

Aecstasy
Bacute
Crapture
Dagony

Show answer

Concept: ‘Agony’ means extreme physical or mental pain/suffering.

Example: He was in agony after the injury.
‘ecstasy’ and ‘rapture’ mean extreme joy – the opposite.
‘acute’ is an adjective (severe/sharp), not a noun for suffering.

Yaad rakhein: Agony = extreme pain; ecstasy = extreme joy.

Answer: (D) agony

अवधारणा: ‘Agony’ का अर्थ है अत्यधिक शारीरिक या मानसिक पीड़ा।

उदाहरण: He was in agony after the injury.
‘ecstasy’ और ‘rapture’ का अर्थ अत्यधिक आनंद है – उल्टा।
‘acute’ विशेषण (तीव्र) है, पीड़ा के लिए संज्ञा नहीं।

याद रखें: Agony = घोर पीड़ा; ecstasy = परम आनंद।

उत्तर: (D) agony

SSC CPO Paper IEnglish ComprehensionOne Word SubstitutionSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6556.

Select the wrongly spelt word.

Acapacity
Bpupil
Cablity
Dteacher

Show answer

Concept: Check each word letter by letter against its standard spelling.

capacity, pupil, teacher – all correct.
‘ablity’ misses the letter ‘i’ after ‘b’; correct spelling: ability.

Trick: Words ending in ‘-ility’: ab-il-ity, poss-ib-ility, abil-ity.

Answer: (C) ablity (correct: ability)

अवधारणा: हर शब्द की वर्तनी को मानक spelling से मिलाइए।

capacity, pupil, teacher – सभी सही हैं।
‘ablity’ में ‘b’ के बाद ‘i’ छूट गया है; सही spelling: ability।

ट्रिक: ‘-ility’ वाले शब्द: ab-il-ity, poss-ib-ility।

उत्तर: (C) ablity (सही: ability)

SSC CPO Paper IEnglish ComprehensionSpelling ErrorSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6557.

Select the most appropriate meaning of the given idiom.
Little by little

Aa few
Bnot much
Conly once
Dgradually

Show answer

Concept: ‘Little by little’ means slowly, in small amounts or stages – i.e. gradually.

Example: Little by little, his health improved.
‘a few’ and ‘not much’ refer to quantity; ‘only once’ refers to frequency – none shows step-by-step change.

Yaad rakhein: Little by little = bit by bit = step by step = gradually.

Answer: (D) gradually

अवधारणा: ‘Little by little’ का अर्थ है धीरे-धीरे, थोड़ा-थोड़ा करके – यानी gradually।

उदाहरण: Little by little, his health improved. – धीरे-धीरे उसकी तबीयत सुधरी।
‘a few’ और ‘not much’ मात्रा बताते हैं; ‘only once’ आवृत्ति बताता है।

याद रखें: Little by little = bit by bit = gradually (क्रमशः)।

उत्तर: (D) gradually

SSC CPO Paper IEnglish ComprehensionIdioms and PhrasesSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6558.

Select the most appropriate option to substitute the underlined segment in the given sentence. If there is no need to substitute it, select ‘No substitution required’.
Had I a rich person, I would share my wealth.

ANo substitution required
BI am
CHad I been
DWere I

Show answer

Concept: For an unreal/imaginary present condition we use the subjunctive ‘were’ for all subjects; with inversion it becomes ‘Were I …’ (= If I were …).

Main clause ‘I would share’ shows an imaginary present (Type 2 conditional).
‘Had I’ wrongly uses ‘had’ as main verb; ‘Had I been’ would need ‘would have shared’ (Type 3).
‘I am’ makes no condition. So: Were I a rich person, I would share my wealth.

Trick: If I were … would + V1 → inversion: Were I …

Answer: (D) Were I

अवधारणा: वर्तमान की काल्पनिक शर्त में सभी subjects के साथ ‘were’ आता है; inversion में ‘If I were’ = ‘Were I’।

Main clause ‘I would share’ काल्पनिक वर्तमान (Type 2 conditional) दर्शाता है।
‘Had I’ गलत है; ‘Had I been’ के साथ ‘would have shared’ (Type 3) चाहिए।
‘I am’ से शर्त नहीं बनती। सही: Were I a rich person, I would share my wealth.

ट्रिक: If I were … would + V1 → Were I …

उत्तर: (D) Were I

SSC CPO Paper IEnglish ComprehensionSentence ImprovementSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6559.

Select the most appropriate option to substitute the underlined segment in the given sentence. If there is no need to substitute it, select ‘No substitution required’.
Because she didn’t love him, she had to marry him.

ADespite
BNo substitution required
CSince
DAlthough

Show answer

Concept: The two clauses contrast each other, so a concession conjunction (‘although’) followed by a clause is needed.

Not loving him and still having to marry him is a contrast, not a cause → ‘Because/Since’ are illogical.
‘Despite’ is a preposition; it takes a noun/gerund, not a full clause (‘despite not loving him’).
Correct: Although she didn’t love him, she had to marry him.

Trick: Although + clause; Despite + noun/V-ing.

Answer: (D) Although

अवधारणा: दोनों clauses में विरोध है, इसलिए clause के साथ आने वाला ‘although’ चाहिए।

प्यार न करना और फिर भी शादी करना – यह विरोध है, कारण नहीं → ‘Because/Since’ अतार्किक।
‘Despite’ preposition है; इसके बाद noun/gerund आता है, पूरा clause नहीं।
सही: Although she didn’t love him, she had to marry him.

ट्रिक: Although + clause; Despite + noun/V-ing।

उत्तर: (D) Although

SSC CPO Paper IEnglish ComprehensionSentence ImprovementSSC CPO Paper I 2020 · 23 Nov Shift 1

Q6560.

Select the wrongly spelt word.

Aumbrella
Boccurring
Csediment
Dexprimant

Show answer

Concept: Check each word against its standard spelling.

umbrella, occurring (double r), sediment – all correct.
‘exprimant’ is wrong; correct spelling: experiment (ex-per-i-ment).

Trick: Split into syllables: ex-PER-i-MENT.

Answer: (D) exprimant (correct: experiment)

अवधारणा: हर शब्द को उसकी मानक spelling से मिलाइए।

umbrella, occurring (दो r), sediment – सभी सही हैं।
‘exprimant’ गलत है; सही spelling: experiment (ex-per-i-ment)।

ट्रिक: Syllables में तोड़ें: ex-PER-i-MENT।

उत्तर: (D) exprimant (सही: experiment)

SSC CPO Paper IEnglish ComprehensionSpelling ErrorSSC CPO Paper I 2020 · 23 Nov Shift 1