RRB ALP CBT 1 2025 PYQs

Concept: Every letter moves back 8 places (wrapping around Z→A).

1. Position	KEV	CWN	UOF	MGX	?
   1st (−8)	K	C	U	M	E
   2nd (−8)	E	W	O	G	Y
   3rd (−8)	V	N	F	X	P

2. M − 8 = E, G − 8 = Y (7 − 8 + 26 = 25), X − 8 = P.

Short trick: Check only the middle letter: G − 8 = Y (G→F→…→Y backwards); only EYP has Y in the middle.

Answer: (A) EYP

Concept: Place the fixed person, then the blocks of two consecutive days.

1. C = Friday; one between C and B → B = Wednesday (Sunday not allowed).
2. Free: Mon, Tue, Thu, Sat, Sun. Consecutive pairs available: Mon–Tue and Sat–Sun.
3. A–D cannot end on Sunday → A–D = Mon–Tue; G–F = Sat–Sun.

4. Mon	Tue	Wed	Thu	Fri	Sat	Sun
   A	D	B	E	C	G	F

5. E = Thursday.

Short trick: Two blocks of 2 need two pairs of consecutive free days; the lone free day left (Thursday) must be E’s.

Answer: (C) Thursday

Concept: Find net east–west and net north–south displacement.

1. East–west: +51 − 56 + 5 = 0.
2. North–south: −56 + 63 = +7 (P is 7 km north of A).
3. So he must drive 7 km towards south.

Short trick: Opposite legs cancel: east 51 + 5 = west 56; north 63 − south 56 = 7 → 7 km south.

Answer: (C) 7 km to the south

Concept: Letters shift +8; number is cubed.

1. DM3: D+8 = L, M+8 = U, $3^3=27$ → LU27 ✓
2. AR12: A+8 = I, R+8 = Z, ${12}^3=1728$ ✓
3. DK13: D+8 = L, K+8 = S, ${13}^3=2197$ → LS2197.

Short trick: Only option A ends in a perfect cube of 13 (2197); unit digit of ${13}^3$ = $3^3$ → 7.

Answer: (A) LS2197

Concept: Check each statement alone, then both together.

1. (I): I is 3rd from the bottom. L, D adjacent with L above → (D, L) at positions 1–2 or 4–5. Tallest unknown.
2. (II) alone says only M > D – not enough.
3. Together: if D = 4, L = 5 then M > D is impossible → D = 1, L = 2. Positions 4 and 5 go to M and O in either order → tallest still unknown.

Short trick: After combining, two poles (M, O) still have no relation between them – so the tallest cannot be fixed.

Answer: (A) Data in both statements I and II together are not sufficient to answer the question.

Concept: Pattern needed: Vowel – Consonant – Consonant.

1. Check the letter after every vowel: U N M ✓, E C S ✓, U M U → M followed by U ✗, U T E ✗, E W X ✓, E Q A ✗, A Z S ✓, I O → O is vowel, O P L ✓.
2. Count = 5.

Short trick: Start only at vowels (U, U, U, E, E, A, I, O) – 8 checks instead of 33.

Answer: (A) 5

Concept: All A are B + All B are C ⇒ All A are C; “All B are C” also gives “Some C are B”.

1. All farmers ⊂ graduates ⊂ employees.
2. (I) Some employees are graduates – conversion of “All graduates are employees” ✓
3. (II) All farmers are employees ✓

Short trick: In an “All–All” chain, the outermost circle contains everything inside → both follow.

Answer: (B) Both conclusions (I) and (II) follow

Concept: Decode symbol by symbol, left to right.

1. W − Q: W is the daughter of Q (W is female).
2. Q * F: Q is the father of F → W and F are siblings.
3. F * E: F is the father of E.
4. So W is the sister of E’s father.

Short trick: W is a female of the generation just above E (father’s side) → father’s sister; “Mother” is ruled out since W is F’s sibling.

Answer: (D) Father's sister

Concept: Swap the signs first, then apply BODMAS.

1. After interchange: 18 + 36 × 10 ÷ 20 − 34.
2. 36 × 10 ÷ 20 = 18.
3. 18 + 18 − 34 = 2.

Short trick: Rewrite the whole expression once with new signs before calculating – avoids sign errors.

Answer: (B) 2

Concept: Facing north: left = left end, right = right end. Fix absolute positions first.

1. 3 to the right of J → J = 4. 2 to the left of P → P = 3.
2. K third to the right of P → K = 6. M immediately left of P → M = 2.
3. Remaining 1, 5, 7: L–O with three between → (1, 5). O ≠ 1 (immediate left of M) → O = 5, L = 1, N = 7.

Short trick: The question is answered by one clue: “M sits to the immediate left of P”.

Answer: (B) M

Concept: Decode each symbol from left to right.

1. D # M: D is the daughter of M.
2. M + S: M is the wife of S → D is S’s daughter.
3. S @ P: S is the brother of P.
4. P − R: P is the father of R.
5. D = daughter of R’s father’s brother (cousin).

Short trick: Go from R upward: R → father P → P’s brother S → S’s daughter D.

Answer: (B) Father's brother's daughter

Concept: Each position follows its own step.

1. 1st: T U V W → X (+1).
2. 2nd: K L M N → O (+1).
3. 3rd: B G L Q → V (+5).
4. Answer XOV.

Short trick: First two letters must be X, O → only XOV.

Answer: (D) XOV

Concept: Check each statement alone.

1. (I): C is taller than only two poles; I < C and N < I ⇒ these two are N and I, so N < I < C ⇒ N is the shortest ✓
2. (II): H > L says nothing about the others ✗

Short trick: “Taller than only two” + two poles named below it → those are the bottom two; the lower of them is the shortest.

Answer: (A) Data in statement I alone is sufficient to answer the question while data in statement II is not

Concept: Pattern needed: Consonant – Vowel – Vowel.

1. Vowels in the series: U (N U Y), O (R O N), A (W A at the end).
2. U is followed by Y (consonant), O by N, and A is the last letter.
3. No vowel is followed by a vowel → count = 0.

Short trick: Only 3 vowels exist and none sits next to another vowel → None.

Answer: (A) None

Concept: Find the common operation in both pairs.

1. 14 + 12 = 26; 32 + 12 = 44 → rule: add 12.
2. 29 + 12 = 41 ✓; 40 → 52 (not 54); 56 → 68 (not 69); 70 → 82 (not 83).

Short trick: Just subtract: only 41 − 29 = 12.

Answer: (A) 29 - 41

Concept: Two “Some” statements give no definite link between the end terms.

1. (I) “No Russian is American” directly contradicts “Some Americans are Russians” ✗
2. (II) “All Indians are Russians” – Indians and Russians are not connected definitely ✗
3. A possible diagram where both fail is shown above.

Short trick: Some + Some ⇒ no conclusion between the end terms; and a conclusion opposite to a statement can never follow.

Answer: (C) Neither conclusion (I) nor (II) follows.

Concept: Facing the centre: left = clockwise, right = anticlockwise. Number seats 0–6 clockwise.

1. A = 0; E second to the left of A → E = 2.
2. G third to the right of E → G = 6; G second to the left of C → C = 4.
3. F third to the left of B: only B = 5, F = 1 works; D = 3.
4. From C going left (clockwise): B, G, then A → two persons between.

Short trick: G is 2nd to the left of C and A is just next to G → between C and A on the left side: B and G = 2.

Answer: (A) Two

Concept: Find one rule for both given pairs.

1. $41\times 4+1=165$ ✓; $18\times 4+1=73$ ✓
2. $122\times 4+1=489$.

Short trick: 4 × 122 = 488 → answer must be 488 + 1 = 489 (only option ending in 9 just above 488).

Answer: (A) 489

Concept: Letters common to both words take the digits common to both codes.

1. CROW = {2, 9, 1, 6}; WORK = {6, 1, 5, 2}.
2. Common letters R, O, W ↔ common digits 2, 1, 6.
3. Left-over: C = 9 and K = 5.

Short trick: K appears only in WORK; the only digit of 6152 not in 2916 is 5.

Answer: (C) 5

Concept: Check the gaps inside and between the clusters.

1. HL−JN: H+4=L, H+2=J, J+4=N.
2. MQ−OS and TX−VZ: same +4, +2, +4.
3. NR−OV: N+4=R but N+1=O, O+7=V ✗

Short trick: Compare first letters only: H→J, M→O, T→V are +2, but N→O is +1.

Answer: (B) NR−OV