RRB ALP CBT 1 2025 PYQs

Concept: Decode left to right (+ = male, − = female).

1. S @ M: S is the sister of M (S female).
2. M − H: M is the son of H.
3. H # Y: H is the daughter of Y (H female).
4. Y % U: Y is the father of U ⇒ H and U are siblings; H is U's sister.
5. S is H's daughter ⇒ S is U's sister's daughter.

Short trick: S → (sister of M) → M is H's son → so S is H's daughter; H is U's sister ⇒ sister's daughter (U's gender is not needed).

Answer: (A) Sister's daughter

Concept: Interchange the signs, then follow BODMAS.

1. After interchange: $5÷39\times 39-39+5$
2. $5÷39\times 39=5$
3. $5-39+5=-29$

Short trick: ÷39 and ×39 cancel, leaving $5-39+5=-29$.

Answer: (A) -29

Concept: Draw the minimum (least-overlap) Venn diagram.

1. Buttons and Pigs each touch Mangoes, but need not touch each other ⇒ (I) "Some buttons are pigs" is not definite.
2. Only "some" mangoes are buttons, so (II) "All mangoes are buttons" does not follow.

Short trick: "Some + Some = No conclusion" between the two end terms; and a "some" premise can never give an "all" conclusion.

Answer: (B) Neither conclusion (I) nor (II) follows.

Concept: Compare letter by letter.

1. N→T, Q→W, M→S, I→O: each +6
2. D→J, H→N, K→Q, F→L: each +6
3. L+6 = R, O+6 = U, P+6 = V, S+6 = Y ⇒ RUVY

Short trick: Only the first letter decides between Q… and R…: L+6 = R; then O+6 = U picks RUVY over RVUY.

Answer: (B) RUVY

Concept: A word common to two sentences has the code common to both codes.

1. "book" is the only common word.
2. "qr" is the only common code.
3. book = qr

Short trick: Common word ↔ common code – just spot the repeated code.

Answer: (B) qr

Concept: Look for symbol–letter–symbol.

1. Letters and symbols alternate from Ω onwards: Ω T & R $ S @ B * L % N # P £ D Ω G $
2. T, R, S, B, L, N, P, D, G all qualify ⇒ 9 letters
3. K (first) and M (last) do not.

Short trick: The series is a perfect alternation, so every inner letter qualifies – clearly more than three.

Answer: (C) More than three

Concept: Check the differences.

1. Differences: 4, 5, 6, 7, 8
2. Next difference = 9
3. ? = 55 + 9 = 64

Short trick: Differences increase by 1 each time: +4, +5, +6, … → +9.

Answer: (D) 64

Concept: Find the shift for each position.

Short trick: Pattern +4, +3, +4, +3. Second letter O+3 = R narrows to JRYU / IRYW; first letter F+4 = J → JRYU.

Answer: (B) JRYU

Concept: Facing north: left and right are our own left and right. Number seats 1–7 from the left.

1. E is at the right end (7); three between E and D ⇒ D = 3.
2. Two between D and A ⇒ A = 6 (seat 0 does not exist).
3. B _ _ F pattern: F 3rd to the left of B and G immediately right of B ⇒ only B = 4, G = 5, F = 1 fits.
4. C = 2. Between B (4) and E (7): G and A ⇒ 2 persons.

Short trick: Between seats p and q there are $|p-q|-1$ persons: $7-4-1=2$.

Answer: (B) 2

Concept: Find the rule inside each cluster and between clusters.

1. PN – QO: P−2 = N; P+1 = Q, N+1 = O ✓
2. MK – NL: M−2 = K; +1 → N, L ✓
3. FD – GE: F−2 = D; +1 → G, E ✓
4. RP – BJ: R−2 = P but R → B and P → J do not follow +1 ✗

Short trick: In the three alike pairs the second cluster is just the first cluster shifted +1. RP → SQ would fit, not BJ.

Answer: (B) RP - BJ

Concept: Shift every letter −1, then sort A→Z.

1. Sorted: B C D G J N R
2. 2nd from right = N

Short trick: Sorting first and shifting later gives the same result: SHOCKED sorted = C D E H K O S; 2nd from right = O → O−1 = N.

Answer: (B) N

Concept: Place fixed clues, then the block.

1. Gauri = Mon; three between Gauri and Kunti ⇒ Kunti = Fri.
2. Block Jack–Hina–Isha needs 3 consecutive free days ⇒ Tue–Wed–Thu.
3. Sat and Sun remain; Lali not on Sunday ⇒ Lali = Saturday.

Short trick: After Mon and Fri are taken, the only 3-day gap is Tue–Thu; so Lali gets Sat/Sun and "not last day" gives Saturday.

Answer: (C) Saturday

Concept: Number positions 1 (bottom) to 7 (top).

1. P = 3. One box between P and M, M ≠ 1 ⇒ M = 5.
2. Three between M and R ⇒ R = 1.
3. Free slots: 2, 4, 6, 7. O just below Q needs two adjacent free slots ⇒ O = 6, Q = 7; one box between O and N ⇒ N = 4.
4. S = 2. Second from top = position 6 = O.

Short trick: Free slots after P, M, R: 2, 4, 6, 7. The Q-over-O pair needs two adjacent slots ⇒ 6–7 → O at 6 (second from top).

Answer: (A) O

Concept: Replace letters by signs, then BODMAS.

1. $70÷2-5\times 3+18$
2. $=35-15+18$
3. $=38$

Short trick: Do ÷ and × first: 35 and 15; then 35 − 15 + 18 = 38.

Answer: (B) 38

Concept: Treat the two letters and the number separately.

Short trick: Number +13 → 16 leaves JS 16 and IS 16; N−4 = J picks JS 16.

Answer: (C) JS 16

Concept: Both statements only separate Rugs from the other two sets.

1. Lamps and Doors are both outside Rugs; they may or may not overlap.
2. So neither "No doors are lamps" nor "Some lamps are doors" is certain.

Short trick: "No + No = No conclusion" between the two end terms (Lamps and Doors).

Answer: (D) Neither conclusion (I) nor (II) follows.

Concept: Find the operation in the given pairs.

1. 112 − 12 = 100; 34 − 12 = 22 ⇒ rule: subtract 12
2. (A) 55 − 13 = 42 ✗; (B) 15 − 12 = 3 ✓; (C) 23 − 11 = 12 ✗; (D) 43 − 20 = 23 ✗

Short trick: Just compute first − second for each option; only (B) gives 12.

Answer: (B) 15 - 3

Concept: Try U = 3 and U = 5 (odd, not 1).

1. U = 5: B = 6, A = 4; P = 3; D–K need two adjacent floors among 1, 2 with D ≠ 1 ✗.
2. U = 3: B = 4, A = 2; P = 1 or 5. D–K must be 5–6 ⇒ P = 1.
3. Order (1→6): P, A, U, B, D, K ⇒ Floor 2 = A.

Short trick: "A just below U" and U = 3 directly gives A = 2 – once U = 5 fails for the D–K pair.

Answer: (A) A

Concept: Check the steps between letters (with wrap-around Z→A).

Short trick: Three clusters move −6 then −5; for CVR, C−6 would be W, not V – odd.

Answer: (A) CVR

Concept: Shift each letter −1, then arrange Z→A.

1. Reverse alphabetical: Z Q M M D A
2. From the right: A (1st), D (2nd), M (3rd)

Short trick: Reverse order read from the right = normal order from the left: A D M M Q Z → 3rd = M.

Answer: (B) M