RRB ALP CBT 1 2025 PYQs

Concept: SP = CP × (1 + markup) × (1 − d₁) × (1 − d₂).

1. Take CP = 100 → MP = 140.
2. After 10%: 126; after 5%: 119.7.
3. Profit = 19.7%.

Short trick: Net discount = 10 + 5 − 0.5 = 14.5%; profit = 40 − 14.5 − $\frac{40\times 14.5}{100}$ = 40 − 14.5 − 5.8 = 19.7%.

Answer: (B) 19.7%

Concept: Mode = most frequent value.

1. Count: 71 → 3 times; 86, 84, 82, 60 → 2 times each; others once.
2. Mode = 71.

Short trick: Check only the option values: 71 (3), 82 (2), 84 (2), 86 (2) → 71.

Answer: (A) 71

Concept: Profit ratio = capital × months.

1. A = 29,000 × 12 = 3,48,000; B = 95,000 × 6 = 5,70,000; C = 67,000 × 6 = 4,02,000.
2. Ratio = 348 : 570 : 402 = 58 : 95 : 67 (sum 220).
3. Total profit = $\frac{6600}{0.15}$ = 44,000 → B = $\frac{95}{220}$ × 44,000 = 19,000.

Short trick: 44,000 ÷ 220 = 200 per unit → B = 95 × 200 = ₹19,000.

Answer: (A) ₹19,000

Concept: Evaluate powers and roots first.

1. $8^2=64$, $\sqrt{{10}^2}=10$, $1\sqrt{16}=1\times 4=4$
2. 64 + 10 − 4 − 5 = 65

Short trick: $\sqrt{a^2}=a$ — no need to compute 100 under the root.

Answer: (C) 65

Concept: Same direction: time = (sum of lengths) ÷ (difference of speeds).

1. Speed of A = $\frac{260+160}{28}$ = 15 m/s.
2. Speed of B = $\frac{340}{20}$ = 17 m/s (B is faster).
3. Time = $\frac{260+340}{17-15}=\frac{600}{2}$ = 300 s.

Short trick: Relative speed only 2 m/s → time = total length ÷ 2 = 600 ÷ 2 = 300 s.

Answer: (B) 300

Concept: Each letter of a cluster moves by a fixed step in its own column.

1. 1st letters: C(3) → J(10) → Q(17) → X(24) → E(31−26=5): +7
2. 2nd letters: A → H → O → V → C: +7
3. 3rd letters: U → B → I → P → W: +7

4. C	A	U
   J	H	B
   Q	O	I
   X	V	P
   E	C	W

Short trick: Check only the first column: X + 7 = E → options A–D all start with E, so check 2nd letter: V + 7 = C → only ECW.

Answer: (D) ECW

Concept: Letters common to both words take the digits common to both codes.

1. SHAT = 4956, ASHY = 3645.
2. Common letters: S, H, A ↔ common digits 4, 5, 6.
3. Left over: T = 9 (first word) and Y = 3 (second word).

Short trick: Y appears only in the second word, and 3 is the only digit of 3645 not found in 4956 → Y = 3.

Answer: (C) 3

Concept: Replace letters by operators and apply BODMAS.

1. (12 × 3) ÷ 4 + 5 × 8
2. = 36 ÷ 4 + 40 = 9 + 40 = 49

Short trick: Unit digit check: 9 + 0 = 9 → only 49 ends in 9.

Answer: (B) 49

Concept: Each column moves back by 6.

1. 1st: B → V → P → J → D (−6)
2. 2nd: A → U → O → I → C (−6)
3. 3rd: J → D → X → R → L (−6)

4. B	A	J
   V	U	D
   P	O	X
   J	I	R
   D	C	L

Short trick: Notice 1st and 2nd letters are always consecutive reverse pairs (BA, VU, PO, JI) → next is DC → DCL.

Answer: (D) DCL

Concept: Check every symbol: letter on its left AND letter on its right.

1. Series: J @ € * Y % V % C I D % D H $ K © L E £ M C
2. Y % V ✔, V % C ✔, D % D ✔, H $ K ✔, K © L ✔, E £ M ✔
3. @, €, * fail (a symbol on one side). Total = 6.

Short trick: Look for the pattern “letter–symbol–letter”: scan only isolated symbols; any symbol in a group of symbols (@ € *) is skipped at once.

Answer: (B) 6

Concept: Find each vowel and check both neighbours.

1. Series: N G T X R K H V A W Z W U B R E C F K L Z
2. V A W ✔, W U B ✔, R E C ✔
3. Only three vowels exist and all three qualify → 3.

Short trick: Count the vowels first (A, U, E = 3); if their count is small just check each one.

Answer: (C) Three

Concept: Mark every vowel and test its left and right neighbours.

1. X H O Z N M W I C G I U S O R Y I Y V I H W
2. H O Z ✔, W I C ✔, G I U ✘, I U S ✘, S O R ✔, Y I Y ✔, V I H ✔
3. Total = 5 (Y is treated as a consonant).

Short trick: Discard vowels that touch another vowel (I U pair) immediately — the rest of the 7 vowels qualify: 7 − 2 = 5.

Answer: (B) 5

Concept: Fix the definite positions first, then the conditional ones.

1. E = 3rd from bottom, G = 4th.
2. A is 3 places from G → 1st or 7th; A not lowest → A = 7th, B = 6th.
3. Free: 1, 2, 5. F with D just below, C two boxes away from F → F = 2, D = 1, C = 5.

4. Position (bottom→top)	1	2	3	4	5	6	7
   Box	D	F	E	G	C	B	A

5. 3rd from top = position 5 = C.

Short trick: 3rd from top = 5th from bottom in a stack of 7 (7 + 1 − 3 = 5).

Answer: (A) C

Concept: Need pattern: symbol – symbol – number.

1. 4 3 1 2 $ 9 & 2 ? 4 @ 1 9 * 3 7 3 @ & < %
2. Consecutive symbols occur only at the end: @ & < %.
3. & is followed by <, < by %, % by nothing → none followed by a number. Count = 0.

Short trick: Find symbol pairs first — the only run (@ & < %) is at the right end with no digit after it → None.

Answer: (D) None

Concept: Rabbits, ants and lions are three different kinds of animals; no member belongs to two classes.

1. No rabbit is an ant or a lion, and no ant is a lion.
2. So the three circles do not touch or overlap → option B.

Short trick: Three mutually exclusive groups (like three different species) = three separate circles.

Answer: (B) three separate circles

Concept: Find the rule: square, then ×2, then ×2.

1. 6 → 36 (6²) → 72 (×2) → 144 (×2); 7 → 49 → 98 → 196.
2. A: 12 → 144 → 288 → 576 ✔
3. B: 50 × 2 = 100 ≠ 110; C: 225 × 2 ≠ 625; D: 128 × 2 = 256 ≠ 226.

Short trick: Last number must be 4 × second number: 4 × 144 = 576 ✔ — check only this.

Answer: (A) 12 – 144 – 288 – 576

Concept: Combine the statements and see if one pole is above all others.

1. I: M > L > D (I and O unknown).
2. II: I > D > O.
3. Together: M > L > D > O and I > D — M vs I unknown, so tallest may be M or I.

Short trick: Two poles (M and I) both have nobody above them → two candidates → not sufficient.

Answer: (A) Both statements together are not sufficient

Concept: Draw the least-overlap Venn diagram.

1. All angry are birds → Angry circle inside Birds.
2. Some angry are pigs → Pigs overlaps Angry, hence also overlaps Birds → “Some birds are pigs” ✔.
3. Pigs may extend outside Birds → “All pigs are birds” ✘.

Short trick: “All A are B” + “Some A are C” ⇒ always “Some B are C” (the common A part is both B and C).

Answer: (C) Only conclusion (I) follows

Concept: Chain the inequalities.

1. W > Z > Y (Z older than Y, younger than W).
2. Y > X > V.
3. Order: W > Z > Y > X > V → second oldest = Z.

Short trick: W is above Z and nobody is above W → W 1st, Z 2nd.

Answer: (C) Z

Concept: Replace and solve with BODMAS.

1. 159 + 60 ÷ 12 × 11 − 203
2. = 159 + 5 × 11 − 203 = 159 + 55 − 203 = 11

Short trick: Do ÷ and × first: 60 ÷ 12 × 11 = 55; 214 − 203 = 11.

Answer: (C) 11