RRB Technician Grade I (Signal) 13 Mar 2026 Shift 1 – Question Paper

Concept: Gharanas are lineages/styles of Hindustani classical music, usually named after a city.

1. Pandit Chhannulal Mishra (1936–2025), the famous khayal, thumri and bhajan singer of Varanasi, belonged to the Banaras Gharana (Purab-ang thumri tradition).
2. He received the Padma Bhushan (2010) and Padma Vibhushan (2020); he passed away in October 2025 at the age of 89.
3. Agra, Gwalior and Jaipur-Atrauli are other famous khayal gharanas but not his.

Yaad rakhein: Chhannulal Mishra = Kashi/Banaras = Banaras Gharana.

Answer: (C) Banaras Gharana

Concept: Replace the signs as told, then apply BODMAS.

1. Interchanging ‘+’↔‘−’ and ‘×’↔‘÷’: $297÷11+17\times 18-91$
2. $297÷11=27$ and $17\times 18=306$
3. $27+306-91=242$

Trick: Write the new expression first, then do ÷ and × before + and −.

Answer: (A) 242

Concept: Reply and Forward differ in who receives the message.

1. Reply sends your response back to the original sender only (Reply All → sender + all recipients).
2. Forward sends a copy of the received mail (with attachments) to a new recipient of your choice.
3. Neither deletes, encrypts or broadcasts the mail – options B, C, D are wrong.

Yaad rakhein: Reply = back to sender; Forward = onward to someone new.

Answer: (A) Reply sends your response only to the original sender, while Forward sends the email to a new recipient.

Concept: $a^4-b^4=(a^2-b^2)(a^2+b^2)$ and ${\sin }^2\theta +{\cos }^2\theta =1$.

1. ${\sin }^8\theta -{\cos }^8\theta =({\sin }^4\theta -{\cos }^4\theta )({\sin }^4\theta +{\cos }^4\theta )$
2. Dividing by $({\sin }^4\theta +{\cos }^4\theta )$ leaves ${\sin }^4\theta -{\cos }^4\theta =({\sin }^2\theta -{\cos }^2\theta )({\sin }^2\theta +{\cos }^2\theta )={\sin }^2\theta -{\cos }^2\theta$
3. Adding $2{\cos }^2\theta$: ${\sin }^2\theta -{\cos }^2\theta +2{\cos }^2\theta ={\sin }^2\theta +{\cos }^2\theta =1$

Trick: Put $\theta ={45}^{\circ }$: first bracket becomes 0, and $2{\cos }^2{45}^{\circ }=1$.

Answer: (A) 1

Concept: Stability factor $S=\frac{d{I}_C}{d{I}_{CO}}$ tells how much collector current changes with leakage current. A smaller $S$ means better thermal stability.

1. $S_1=101$ is typical of fixed bias (worst case, $S=1+\beta$).
2. $S_2=15$ is much smaller, so $I_C$ drifts less with temperature.
3. Hence circuit 2 is thermally more stable.

Trick: Lower S = better stability; ideal $S=1$. Voltage-divider bias gives small S.

Answer: (D) Circuit 2